Joule Thief 101

[MileHigh]

So here is my problem with that. many times before he admits to being corrected, his stance is this.......

"You are the epic failure others claim you to be.
You are a total disaster.
Your (sic) a fraud.
You epic failure.
You are now the laughing stock of this forum."

As far as your rant about me goes, I may deal with that later.  What I don't want to see is predatory harassment from you like you did to me the other day.

The reason for this posting is to clarify the words you quote above.  Those are Brad's words, not mine.

MileHigh

[tinman]

You are dead wrong.  So where did you make your mistake?

No mistake MH.
The results were the same on every test--> 5 tests done.

Should i make a video showing you this?
Did you watch the video i posted the link to a few post back--that will knock ya sock of when you do the calculations.

Here are mine from the video i speak of.

So 2.52 volts across 350F=1111.32 joules of energy in one cap,and none in the other.

The end result was
Cap 1 -1.468v across 350F= 377.129 joules
Cap 2-1.273v across 350F= 283.593 joules.

Total =660.722 joules
If we double this,we have 1321.444 joules.

So yes,he lost less than the half expected.
But there is also one other thing to take into account-->the little motor was running the whole time,and there for was also dissipating power the whole time current was flowing through it,by way of resistive heat loss.


Brad

[MileHigh]

An experiment where the final voltages are not equal is an invalid experiment and is not even applicable to the statement about half of the energy being lost.  It is as ridiculously simple as that.

[tinman]

An experiment where the final voltages are not equal is an invalid experiment and is not even applicable to the statement about half of the energy being lost.  It is as ridiculously simple as that.

Ah,that good old MH paradox kicks into action again lol.

Nice one MH--were all getting the hang of how you work now

So what would you say if i carried out the test again,and included a parallel resistor of 5K across the LED,and i ended up with more than half the starting voltage in both caps?
What paradox inclusion would you use then?


Brad

[tinman]

No mistake MH.
The results were the same on every test--> 5 tests done.

Should i make a video showing you this?
Did you watch the video i posted the link to a few post back--that will knock ya sock of when you do the calculations.

Here are mine from the video i speak of.

So 2.52 volts across 350F=1111.32 joules of energy in one cap,and none in the other.

The end result was
Cap 1 -1.468v across 350F= 377.129 joules
Cap 2-1.273v across 350F= 283.593 joules.

Total =660.722 joules
If we double this,we have 1321.444 joules.

So yes,he lost less than the half expected.
But there is also one other thing to take into account-->the little motor was running the whole time,and there for was also dissipating power the whole time current was flowing through it,by way of resistive heat loss.


Brad

Perhaps you missed this one MH.
What paradox will you add to this?
You will note that the lower voltage value cap is more than half the starting voltage that was in the charged cap,and the second cap has an even higher that half voltage value than the starting cap--and he was using a little DC motor to make the transfer,and it was running the whole time

Cant wait to see you explain this one


Brad