Ultracaps tested for excess energy

[gadgetmall]

thank you Paul and that is good information.This tells up that a constant current supply at the very low voltage you charged to is 91% efficiency . What if you charged it to a usable 2.00 volts ?  i see a jump in joules verse charge at one point . Also This in no way deters me and the projects in no way . there is still a working model and still a cap to cap version and still won;t explain the minor drop charging from an aa battery to full bcap . So there is something else involved . Maybe charging it at a Frequency pulsed at 5.5 milliamps is the magic and the cap never heats internally ? Remains to be seen and i am working with the devices and not numbers or theory   so anyone is welcome to do there test . in the meantime we are full steam with the >1  self runner . and so seeing will be your proof also . I know its almost Christmas but being you have it set up . could you start at a voltage of the bcap  @ .521 . the actual cut off point for usable voltage for a silicon transistor . all my caps set here when discharged . this is where they stop running Jt's with silicon . and this is where mine take off from that point  to charge to full . I realize that's a half volt already in the cap but it make no difference in a self runner . the will be running on their own after that point .  our new chip will run as low as .8 volts  and it takes   a few hours to reach this point .
 

Gadget.

[MileHigh]

Paul:

In all likelihood the ultracapacitor is way more than 91.9% efficient for reasons that I have already outlined.

The secret might be in the pulses. Or it might not be the UC at all, as it might be in the JT, or perhaps a combination of both.

There is no "secret" in the pulses.  The capacitor will absorb and store the power supplied by a  DC current source in exactly the same way it will absorb pulsed energy spikes, there is no difference at all.

The JT circuit is by definition a device that will transfer less energy into the output side as compared to the energy that is being put into it on the input side.  There are energy losses associated with the transistor, the primary coil, and the secondary coil, and the resistor.  The JT circuit can give you increased output voltage but you have to pay for it and you loose energy in the overhead required to run the JT circuit itself.

MileHigh

[innovation_station]

speed is power lol  duh!!  why do you think im back ... ?

hummmm

lol


just like i said i dont know 4 years ago ...  your calculation of horse power is INCCORECT!  lol 

so is you interpertation of the effects ...   high freq ring a bell?   lol  the batteries and caps are TRANSLATING DEVICES ...  they dont care the freq ...  they switch it to PURE DC ....
so if you have a small source running really fast ...  you have a high freq ... and when you slow it back down  it ends up more

and every time you turn it on and off a simple kick is produced much higher in voltage than required to produce the effect ..

so you transmitt and you use only what you recieve ...   

so many thousand times i say the same thing ...  yawn...   



hummmmm

bla bla ... 

w

[powercat]

well done Paul,
91.9 efficiency is promising considering you were not pulse charging the UC,
are you willing to do a comparison test with a pulse charge ?
cat

[gadgetmall]

@mh . FrequencyPDC is different that pure Dc current .The Bcap Will react Differently with Frequency charge  just like an led will react differently but you get the same effect with less power from a source  . and i know leds lit by pulses produce the same if not more light on 1000th the amount of current required to light them and i know they are blinking so fast the human eye cannot detect this . same with Battery caps only they don't require the amount of joules the constant current supply gives them . there's and interruption and a slight rest time to consider when they are charging with a Jt so they shouldn't even see a temperature change like they will with dc constant current.  you are incorrect ! Go ahead and Flame me one more time and say anything pertaining to My work ,education or knowledge from Experiments . You have no way to prove what you are calculating because you have not tried it man . I am waiting for your counter action but i don;t expect you to prove anything without a real experiment .
Thank you so much for your interest . Paul says there 91% with a constant supply and that is good enough for everyone else ! Have a great Christmas Mh and family ! .

Gadget.