STEORN DEMO LIVE & STREAM in Dublin, December 15th, 10 AM

[Omnibus]

Jean Naudin is a legend. Well done. I too wish there were an English translation of this fine study. Now, it seems we're getting more and more into a positive territory we've never been before.

[k4zep]

Jean Naudin is a legend. Well done. I too wish there were an English translation of this fine study. Now, it seems we're getting more and more into a positive territory we've never been before.

Go to:  http://translate.google.com/# and paste in http://jnaudin.free.fr/steorn/index.htm
in the box.  Does an excellent job of translating the page!!!

Ben

[hartiberlin]

Google translation puts out a pretty good english version of JL Naudin´s page:

http://translate.google.com/translate?js=y&prev=_t&hl=de&ie=UTF-8&layout=1&eotf=1&u=http%3A%2F%2Fjnaudin.free.fr%2Fsteorn%2Findex.htm&sl=fr&tl=en

[k4zep]

Google translation puts out a pretty good english version of JL Naudin´s page:

http://translate.google.com/translate?js=y&prev=_t&hl=de&ie=UTF-8&layout=1&eotf=1&u=http%3A%2F%2Fjnaudin.free.fr%2Fsteorn%2Findex.htm&sl=fr&tl=en

Hi Stefan,

JLN's motor is vastly superior to mine.  MY hat is off to him.  It does suck current too, about 4.5 amp pulses but that is to be expected.
OK, who's next!!!!!

Ben

[hartiberlin]

Stephan:

You are incorrect here.  K4zep pointed out the exponentially rising current waveform on his scope trace and stated that's where the inductor gets charged with energy and he is correct.  Once the inductor is fully charged and the current levels off, then it is just acting like a resistor dissipating energy as heat.

In Sean's demo clip, you can see how the exponential rise to charge the coils with current is around only 2% or less of the ON time.  Therefore, the back EMF that you can get from the coil discharge is only about 2% or less than than the total amount of electrical energy expended to keep the core saturated.   In K4zep's most recent clip you can see the exponential curve of coil charging current levels off after about 10% of the total ON time.  Therefore in his setup you can only recover 10% or less of the total electrical energy expended to keep the core saturated.

So there is nothing free about this process if you want to recover the back EMF after the coil has done its job of saturating the ferrite core.  You have to put out a lot more energy to make the core "disappear" than you can get back in any back-EMF recovery circuit.  In a Joule Thief circuit, the charging current in the collector coil is automatically shut off once the coil is fully charged with current, it is a self-regulating process.  Therefore a Joule Thief would return a much higher proportion of the charging energy in its inductive kickback.

MileHigh

Hi Milehigh,
If you use a LR circuit which is just a coil with its internal ohmical
resistance, you can really extract 90 % of the energy of the inputed
energy, when you switch on for less than 1/5th of tau.

I did calculate this already a few years ago,
when I calculated a few Newman coils and their input energy
for varying input pulses.

To reach the required  current level for ferrite core saturation, you just have to change the
supply voltage for higher voltages,so you reach the required current level
already at 1/5th of tau switch-On-time.

Maybe I will just recalculate this again and post the formulas to see it for you ?