STEORN DEMO LIVE & STREAM in Dublin, December 15th, 10 AM

[PaulLowrance]

The total friction consumed by my terribly unbalanced replication at 1600 rpm is 4.36mW. Without even capturing any energy it would run for 124 days on a single 10Ah 1.3V D-cell battery.

Actually my above example was for a rechareable battery. Since you're using an Eveready Energizer Alkaline D cell, which has 18 Ah, it would run for 224 days! 

[Omega_0]

@Omega_0 and the rest,

I don't think the original data I sent you differs from the Saturday demo data. What is being done in the Saturday's demo to produce the bottom (input) trace is to extract only the, what they correctly call, net input energy. That is, the bottom trace only shows the energy with all losses subtracted. That's how I understand it. Therefore, probably, it is not the integral(V*I)dt which should be plotted in that Excel sheet but integral(V*I - I^2R)dt where R = 4.8Ohms. See what will happen if you do it that way. It is crucial to understand well what the shape of the input trace is due to.

You are right Omnibus, it seems they are subtracting the I^2R loss from the input to get that integrated trace. The measurement they are doing is not fair IMO. Lets see what others think of it.

Plots from your data are here:
.

[Omega_0]

The file is here :
http://www.overunity.com/index.php?action=downloads;sa=view;down=364

I got a better curve with R=4.9
It is surprising how sensitive to R the shape of the curve is, even a 0.1 change can make it totally different.

[Omnibus]

Omega_0,

Recall that in the first demo vid Sean was claiming that all input energy goes only for Ohmic heating. This means that the OU effect would have been infinity. That was a loose statement of his because, as we see now, he should've said most of the input energy goes for Ohmic heating.

I think if we're to calculate fairly the OU effect we have to subtract at least the Ohmic heat component from the input power and compare that to the output power produced in the pick-up coil. That's why I was saying above that if all the I*V went to Ohmic heating the OU effect would've been infinity. Now we see that there's some more power in the input I*V, in addition to the Joule heat calculated as I^2R. We see, however, that that extra (I*V - I^2R), part of which supposedly goes for turning the rotor, is three times less than the power produced in the pick-up coil (which I will denote as i^2r).

As seen, if the crucially important values of r and R are determined correctly, we have over 300% overunity without a doubt.

P.S. Current in the integrated curve should be always positive (i.e. absolute value of current should be used) so that the negative voltage would correctly reflect the power gain, as in the trace which Steorn show. You may wanna correct that.

[Omnibus]

This Max fellow who I suspect is at the bottom of this development is really brilliant. I think he's French, actually.