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Overunity Machines Forum



STEORN DEMO LIVE & STREAM in Dublin, December 15th, 10 AM

Started by PaulLowrance, December 04, 2009, 09:13:07 AM

Previous topic - Next topic

0 Members and 47 Guests are viewing this topic.

Omnibus

Forgot to mention -- caps of lower capacitance value yield a negative input energy-time slope as well in the shunt current measurement as they do in the current probe current measurement.

Omnibus

Quote from: blueplanet on June 28, 2010, 12:45:03 PM
This graph shows Pout/Pin changes sign at 41 Mhz:

http://www.overunity.com/index.php?action=dlattach;topic=8411.0;attach=45402;image

But this graph does not reflect this behavior:

http://www.overunity.com/index.php?action=dlattach;topic=8411.0;attach=45405;image

Didn't I say, or maybe you just didn't read it -- the data at frequencies higher than 1MHz will be the subject of further studies. So, go back to what's at hand here.

Also, carefully examine what the second graph is showing and see if you can really make the statement that it isn't reflecting the behavior shown in the first graph. That's just for exercise because, as I said, we're not concerned at present with the behavior in the MHz range.

broli

Quote from: Omnibus on June 28, 2010, 12:56:46 PM
Forgot to mention -- caps of lower capacitance value yield a negative input energy-time slope as well in the shunt current measurement as they do in the current probe current measurement.

Does the slope get more negative if only the shunt value is decreased? If so does it behave linearly? Also can you perform that phase shift measurement.

Omnibus

Quote from: broli on June 28, 2010, 01:58:33 PM
Does the slope get more negative if only the shunt value is decreased? If so does it behave linearly? Also can you perform that phase shift measurement.

I have done such study but can't open it, believe it or not. My Excel 2010 that was supposed to arrive on Friday hasn't arrived yet. When it arrives I'll post what I have.

teslaalset

Here's the first attempt to calculate the RC circuit, see attached excel file.
Diagram is in the excel to avoid confusion.
You can play with figures at the top to the 'Signal Calculation' tab and vary:
- input voltage peak/peak value
- frequency
- resistor value
- capacitor value
Output of the UIN and UOUT phase and amplitudes can be viewed instantly after altering any above parameters.
The result in the graph shows 2 full sinus periods.
Below the input/output graph some power calculations are done.
I find that input power is exactly equal to output power for every frequency.
But of course this is just a model to show that 'old school' theory is used.

Any comments/suggestions are welcome.


Some more details of my calculations:
'Signal Calculation' tab contains basic calculations of (from top to bottom):
1) complex impedance
2) complex current, amplitude and phase
3) voltage across the output resistor, amplitude and phase (of course output voltage phase is equal to phase of current)
4) phase between input and output voltage phase shift
5) amplitude of the output voltage across the resistor

Power calculations:
- I used the calculated complex current as calculated in 2) above and multiplied it by the complex input voltage.
- For power consumption (as it will be charged to everybody): only the real part of the input power is important
- Output power is calculated as the complex current times complex voltage across the resistor.

'Signal Curve calculations' tab contains the calculations for the actual phase graph.

[Edit1]
Maybe for clearity:
Voltage and currents are pure sinus shaped.
Power amplitudes are calculated but here sinus x sinus should be applied


[Edit2]
I will do a separate excel session on power calculations.
Attached file is too vague to be understood by most readers