STEORN DEMO LIVE & STREAM in Dublin, December 15th, 10 AM

[Omnibus]

As long as 2 point linear trendlines are use on graphs that represent exactly N*360 degrees, these are very reliable and as accurate as Excel itself.

Floating point errors can be calibrated by just using 0 Volt input.
Those trendlines should give you exactly zero angle and zero offset.

If that's the case, we got it. That's beyond words.

Now we have to figure out how the theoretical effects correspond to what's found experimentally. There may be some new phenomenon at work here. Something which is neither capacitance, not inductance and yet causing phase shift. Recall that doubly wound coil (not bifilar) I showed some pages back.

[Omnibus]

It will be great if even one lab can reproduce it. But I'm sure you can convince them. I will post detailed build instructions soon, and I'm posting the data again in text format to end the Excel2007 dependency.

That's great. It's good to have a concisely written document explaining the details.

As for the replicating efforts, I have already made contacts with influential science parties but I won't get into details here. We have to meet in person probably sometime in the near future and talk more about how this can be handled.

[blueplanet]

0.01 ohm is too small. And the energy data Eout  in your graph is unrealistically small. You will end up with round off errors. Use a bigger resistance instead.

@Omega_0,

Can't agree more. I've been saying this all along and also the need for a mathematician to help with this. That would be the ultimate.

Now, get this. Here are the theoretical data for 800kHz, 0.01Ohms and 44pF. Since I'm still having trouble with my Excel I was only able to plot, I believe around 30000 point. You may observe that at the beginning the input energy at the end of each half-cycle is farther away from the line of the output energy. As the end of the studied period (of ~30000 points) that distance becomes much shorter, indicating that eventually the input energy will fall below the output energy. That's a clear indication of OU existing in the very theory of electricity. Like I said, I don't hoe to work this out purely analytically, if that's at all possible or necessary.

P.S. Can't attach the Excel file -- too big even when compressed.

[Omnibus]

You can try, say, with 700kHz, 10Ohms and 30pF. The input energy-time slope isn't negative but is lower than the output energy-time slope -- 1.22 OU.

[blueplanet]

The equations look correct, but Ein will not ram up forever because the impedance of the source has not been taken care of.

The voltage source has its own source impedance. You should not assume that the source impedance is always ZERO, particularly when your output resistance is relatively low.

I have already posted the analytical equation for energy derived from the current and voltage equation for an RC circuit. This inherently includes the behavior of energy stored in the capacitor. It's up to you to choose an initial condition. You could start with a fully charged capacitor and use that as as your initial energy at t=0 or start with a completely uncharged cap and use 0J as your initial energy for t=0. Either way all the initial energy does is add/subtract some constant value to your graph and move it up/down. It doesn't change the slope. In a circuit with R=0 the slope would be 0 and this is what the equation shows too.

Below you can see the energy wave at R=0 and R=100.