Stepping Down a Wimshurst

[mscoffman]

@All

Somebody mentioned the number of microamps involved in a Wimshurst
spark...but this current would be at least at 10KVdc+ so that is a lot of
zero decimal points coming from the voltage side of the P=I*E equation.

At the time I calculated Watts to tens of Watts available.   

Don't forget, you can always add an "antenna" wire to your influence
machine device to cause it to affect more of its environment. This
is why I don't think an electrostatic machine like this obeys the
simple conservation of energy laws and is where the plexiglas Bedini
ten-coiler machines gets their extra battery charging ability.

Also back when they were using Wimshurst machines as a power
supply for x-ray tubes they would spin a number of disks on the
same shaft. Capacitive coupling will cut down on the available power
over DC brushes but has some benefits as well.

Don't forget, the target goal for a free energy generator is
~1.5KWatts continuous~ for household use - not megawatts.

---

Book: Modern High-Speed Influence Machines
circa 1922

http://ebook.lib.hku.hk/CADAL/B31428137/

:S:MarkSCoffman

[wojwrobel]

hello

all this idea gets me to thinking

if we can charge by induction witout loss of our sorce so why dont we make something stationary that will work at the same princip...

maybe like this?

[gauschor]

Very interesting thought; The only problem I can see here is, how both negative & positive potentials are transferred alternatingly and in short time onto the first big capacitorplate.

In detail: at first you fill up the big capacitorplate on the left with a high negative potential e.g. with the help of a wimshurst device. If the capacitor area is big, it takes 1-3 seconds(!) to get it fully loaded. Then after you have loaded it, you need to reverse the potential quickly into a positive one. How could one do that?

[wojwrobel]

hello

well i dont think that its gonna take 1-3sek, 1m x1m 2mm apart mica insulator k=7.5 is just 0.0332024 uf and with potential 50kv its gonna charge in ms it is not rc circut that charging time would depend from R.

and how to make sinus 50 kv?
i have think about that but i think mechanical setup plus wimshurt?
wojsciech

[gauschor]

It definitely takes more than a few milliseconds to charge it up. I would say at least a half or 1 second for a spark of 50kV+ which is definitely too slow for a power generation device; consider that common wimshurst devices have 2 big capacitors on them (leyden jars), which are nothing else than 2 metal plates for each capacitor. However these leyden jars need some turns of the wimshurst discs to get fully loaded. Only then they have enough different potential to create a strong lightning of 50kV+. If you remove the capacitors completely you can get a lightning arc, which however is only an estimated 2-6kV (from my experience). So in any case the charging procedure is too slow.

And then the problem of the alternation between positive/negative potential is still not solved yet. You could achieve that by shortcutting both negative & positive potentials and then build up only one potential afterwards. But this sounds very inconvenient and would take too much time either.

That said, I am still sure there must be a way to achieve that. Maybe somehow like in the image beloiw although I am afraid that I am missing some points here, or make some logical errors. At least I wouldn't know how to connect the wires to the disc segments if the discs are rotating... :/