Agentgates´s TPU setup with strange wavehill hump

[Magluvin]

I hear ya ton. Im cool.  I dont really have many good things going good for me at this time, and just the reality that this is possible, will bring a tear to my eye that this will do good for all. Good luck

I had an experience where someone at fizzx said they figured out how AL got he whipmag to work, and I wasnt the only one impatiently awaiting the answer. It took a bit to get that answer and the answer was a secret motor drive. 

Take care of that heart and again  good luck.   Now Im really late. =]

Mags

[minde4000]

@agentgates

I gave you a geometrical/mathematical proof. You show me a rudder?...
Your formula is close. R = H is dead on.

I wont debate about this anymore.

Best of luck

Minde

[psm1963]

@minde

your fromula used 6.25 the square root of which is 2.5, shouldn't it have been 5.0625 square root of which is 2.25? Please check your formula and tell me where 6.25 comes from

[ketone]

Hi,

those who thinks about the winding geometry of this device may want to consider this posting from energeticforum.com
http://www.energeticforum.com/renewable-energy/4587-marko-rodin-15.html#post77884

In his follow up postings user 'rococo' also supplied drawings of the different patterns. Unfortunately you can only see the drawings when you are logged into the forum.

Hope this is not too far off topic.

Thank you for the info!

@agentgates
                     That build brought a tear to my eye  , so beautiful , i can't wait to slam it with all kinds of frequencies!Where can i send you a care package?

btw....your spacings look like you had a rotary table, did you do tht by hand?...great work!

[broli]

@agentgates

I gave you a geometrical/mathematical proof. You show me a rudder?...
Your formula is close. R = H is dead on.

I wont debate about this anymore.

Best of luck

Minde

Did you consider the curvature of the tube? Just like a square the sides have to be equal to have a 45° angle. This is why the height of the tube has to be equal to the arc length of the tube part where the diagonal line spans across. If no tube is used then indeed H = radius.