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Overunity Machines Forum



Solid State Orbo System

Started by Groundloop, January 06, 2010, 12:21:24 PM

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0 Members and 15 Guests are viewing this topic.

wings

Quote from: Airstriker on March 03, 2010, 11:21:20 AM
That's the exact question to ask.
my be I am so stupid but:

both the magnetization (9.2 V on 10kohm) and demagnetization (35.3 V on 10Kohm) circuit gives the output power that is costant because DC.

the input power is 85% (because of duty cycle) with 4 V on the same resistance 10kohm.

I am not able to  calculate the opto power!

But the output/input power ratio is close to 98?

mondrasek

Quote from: wings on March 03, 2010, 12:26:17 PM
the input power is 85% (because of duty cycle) with 4 V on the same resistance 10kohm.

The 10kohm value is the resistance of the output coil.  The input voltage (4V) is to the toroid, not the output coil.

synchro1

Looks like JLN's 2SGen has positioned the Steorn Orbo in the museum of power technology right off the test bench. Steorn's admission that ¨hard drive tolerances¨ are necessary to achieve it's meager 3.8 percent COP can't begin to compare to the simplicity of JLN's MEG design and power ratio of over 13. Zaev reports a solid state ratio of over 16 with the 81 NM material. Zaev's domain shift and weight loss ratios in the magnetic core are fascinating! Makes the Orbo look like a steam engine.

wings

Quote from: mondrasek on March 03, 2010, 12:43:52 PM
The 10kohm value is the resistance of the output coil.  The input voltage (4V) is to the toroid, not the output coil.

In this circuit I see 10 kohm in series with the toroid coil!

10kohm everywere

I don't take into account the toroid resistance negligible in comparison to 10kohm, the output coil resistance free

mondrasek

Quote from: wings on March 03, 2010, 02:05:53 PM
In this circuit I see 10 kohm in series with the toroid coil!

Thanks.  I didn't pay attention to the resistors in the input circuit.  Guess that is why I asked if someone could help!

So, if this is the correct way to calculate, you have an input power of 0.0014 watts to the toroid during the magnetization portion of each cycle.  Yet the output coil is showing 0.009 watts during this same portion?  And then that is released as 0.1245 watts in the output coil during the demagnetization portion of the cycle, right?

I understand that there is a theory about the gain between magnetization and demagnetization in the output coil.  But any explanation for the difference between 0.0014 input from the supply circuit and the 0.009 watts reading on the output coil during magnetization?  Shouldn't those two be the same, minus heat losses?