The Ossie motor

[casman1969]

Has anyone tried this with Adams coils? I'm giving it a go with three bi-fillar wound and various combinations but the reed timing is a little tricky.

[woopy]

Hello all

I made a new test on the ossie motor original config of the coils that is    - + -+ - + - +

i  disconnected  the reed switch and diode circuitery      and        hooked  up the coils  directly   to my orbo circuit    see pix 1

that is a single Hall effect sensor circuit actuacting a mosfet to the coils.

And it works very nice  and the current is also very low and the system works  very  regular and smooth   And i get very similar trace as for the double reed circuit    see the scope shot   pix 2 and 3.   


and now my question to you

WHAT DOES EXACTLY  MEAN AND   SHOW  THIS UP AN DOWN SCOPE TRACE ??

When the trace goes up      that shows an impuls from the battery   =   energy lost to power the rotor   OK But     is  there an  hidden( behind )  generation curve which does not appears ?? I mean is there an original AC curve covered by the power pulse ?? which make me think that could be an equality between the in and out  of energy in the upper curve ??

when the trace goes down    that shows what ? Is it  a net gain of   energy which surpass  the upward one    or   simply the mirror energy which cancel the upward one. so total balance is  zero    I mean very nice AC trace but only for the show and unsuable ??

Thanks for a comprehensible explanation    i need to learn slowly  please

regards

laurent

[Jimboot]

Oh yeah

Now if the resistor with the batteries is to make up for reeds staying on longer than wanted, as they would let the coil charge slower, just as the cap would also need, but more ohms, then I would say the resistor could help some.
I have just, myself, been able to reduce my reed timing pretty good with polarizing mags on the reeds and a couple other techniques. I made some vids a bit ago on reeds.

Mags

Mm the volts initially went up but have decreased overnight. I was using the resistor with the batteries to see what the effect would be b4 trying with supercap.

I think I actually got better results with my circuit without the bridge. I'll switch back today to confirm.

[futuristic]

when the trace goes down    that shows what ? Is it  a net gain of   energy which surpass  the upward one    or   simply the mirror energy which cancel the upward one. so total balance is  zero    I mean very nice AC trace but only for the show and unsuable ??

Thanks for a comprehensible explanation    i need to learn slowly  please

I what I see from your scope shots is:
- you have motor working in attraction mode, because generator pulse fires right between magnets and it turns off when magnet comes close to the center od the coil.

- your generatur pulse is approx. 4V DC on the coil and induced voltage is 5V AC.

I can't say if you're getting more out than in if I don't see scope shot across the small resistor (1 ohm or less).

Have fun,
Frenky

[captainpecan]

I what I see from your scope shots is:
- you have motor working in attraction mode, because generator pulse fires right between magnets and it turns off when magnet comes close to the center od the coil.

- your generatur pulse is approx. 4V DC on the coil and induced voltage is 5V AC.

I can't say if you're getting more out than in if I don't see scope shot across the small resistor (1 ohm or less).

Have fun,
Frenky

I agree.  I'm not a pro at reading the scope yet, but if I'm reading correctly, his pulse width is a bit wide.  I know it will run at higher rpm with a wider pulse width, but if the goal was to replicate what Ossie has said, then the pulse width should be hidden inside the AC wave.  But what I do not quite understand is how you are seeing that he is getting higher AC voltage than the DC he is putting in?  Like I said I am still learning to read scope traces, but by seeing his pulse flatline at the peak, it appears the AC wave is less than the DC pulse.  Could you possibly explain to me how I'm misunderstand it?  I would expect to see instead of the flatline, the upwards curve of the top of the AC wave, as it over powers the pulse.  Thanks for any clarification.