Pulsed DC Transformer with Embedded Magnets

[Paul-R]

You raised a few good questions.
The first one is on increasing input.  The LEDs, 2N2222s used cannot take very high voltages.

Why use LEDs at all? Is there a special reason? Why not use a heavy resistor,
possibly immersed in a small tank of oil, and then measure the temperature
increase in the oil to deduce the power out through the resistor.

[rave154]

Paul-R,

i agree, but this could all be settled in 5 minutes.....if only he'd use a cap or cap bank on the input...and an equal cap bank on the output.......if he drains the input bank....from a given voltage....and ends up with a bigger voltage in the output bank.....then thats OU

[The Observer]

Rave...

I you want to fill a couple Caps and Contemplate OU, then I suggest you get a disposable camera with a flash.

Here's your test.

      1. Hook up battery (1.5V)  straight to the Cap... for 1 Second.
          Then Measure Voltage. (probably ~ 1 Volt)

       2. Hook up battery to charging Circuit... for 1 Second.
          Then Measure Voltage. (probably ~ 100 V)

Question to contemplate.

"How the F___ did the same battery get that much energy in the cap in the same duration?"

    E=(1/2)*C*V²

What is that 100V*100V = 10,000?

So somehow the flash circuit got ~ 10,000 times more energy in the Cap during the same period.

    WOW !   WOW !   WOW !   WOW !

Explain to me how this is NOT OU?
Chris.. you can give it shot if you want too.
Tseung.. take note. ( I believe Rave is right about determining the energy by using the simple cap charging process)

Best Regards,
                     The Observer

[minde4000]

Rave...

I you want to fill a couple Caps and Contemplate OU, then I suggest you get a disposable camera with a flash.

Here's your test.

      1. Hook up battery (1.5V)  straight to the Cap... for 1 Second.
          Then Measure Voltage. (probably ~ 1 Volt)

       2. Hook up battery to charging Circuit... for 1 Second.
          Then Measure Voltage. (probably ~ 100 V)

Question to contemplate.

"How the F___ did the same battery get that much energy in the cap in the same duration?"

    E=(1/2)*C*V²

What is that 100V*100V = 10,000?

So somehow the flash circuit got ~ 10,000 times more energy in the Cap during the same period.

    WOW !   WOW !   WOW !   WOW !

Explain to me how this is NOT OU?
Chris.. you can give it shot if you want too.
Tseung.. take note. ( I believe Rave is right about determining the energy by using the simple cap charging process)

Best Regards,
                     The Observer

The question is how much energy did you consume from your battery by charging to 1VDC and how much to 100VDC?

You have charged cap to 100VDC in expense of high amp surge from your source battery during your charging time where to charge to 1VDC took only a fraction of amps. Correct me if I am wrong.

Minde

[Pirate88179]

The question is how much energy did you consume from your battery by charging to 1VDC and how much to 100VDC?

You have charged cap to 100VDC in expense of high amp surge from your source battery during your charging time where to charge to 1VDC took only a fraction of amps. Correct me if I am wrong.

Minde

This is exactly correct.  The amp draw was 10,000 times higher for that brief amount of time.

Cap to cap will tell the tale, one way or the other.  I would suggest super caps or a boost cap which will hold more energy and take longer to fill and to discharge giving you a larger window during which to observe the results.

Bill