Mehess Motor

[billmehess]

Hi Stefan

Each capacitor is charged indiv. as the circuit is closed by the lead contacting the copper strips. Remember I have about 600 mv to work with each charge so I do not need to charge more than one at a time. The key word here is time
at 600mv per minute in 30 days I can produce a lot of juice. About 24kv/ month.

When I have a sufficient amount stored I would then pulse them into the battery.

This germanium diode is a special diode with only a .2 voltage forward drop I tried the other kind and the
germanium gave me a better performance

They are alu. cap. they have a voltage drop or leakage of about 30-40 mv over a 24 hour period. Since I would be paulsing the battery more frequently than that the caps I am using are doing the job

My big surprise was the amprage available I was hopeing for 20-30ma pr cap. in a paulse. I am getting
between 300-600 ma per paulse.

In terms of watt if I use say 20 caps at 600 mv each which is 12 volts and at a medium of say 450 ma
per cap at 20 caps which is 9 amps I can make the battery stand up and dance.
As a point of interest my voltage drop is so low on the battery (remember it only runs for 12 sec./month)
that when I put a standard 12 volt 600 ma battery charger on it the battery recharges in under 10 sec.

The battery at 12 volts and drawing 4.5 amps under the load of rewinding the mainspring draws around 50 watts.
I have also done this experiment 20-30 times running the battery with the load and then recharging with my 12 v.600 ma charger and the battery does excellent.

Frankly I could turn on the motor once  a month and run this device for an entire year before I would have to
recharge. better for the battery to charge up more frequently though. All closed system NOTHING IN.

[Dingus Mungus]

All closed system NOTHING IN.

Except the huge battery that starts off containing enough power to run the system for a year...

[billmehess]

Ok

If I run the system for a year and at the end of that year the battery has noT degenerated and the system has
also run x number of other loads.
Or at the end of a year the battery has not degenerated AND there are more batteries setting next to it fully charged...

                                                            WHAT DO WE CALL THIS?

[hartiberlin]

Bill,
why don?t you charge up one bigger capacitor to about 20 Volts ?
Why are you using several capacitors ?
Is there any reason for this ?

It seems, with the power you generate at the swinging pendulum
going into the coils you could just power an LED maybe constantly
over the time all the time,
if you would not use a battery.
So in this moment the energy output seems to be pretty low...

Did I understand it correctly that you only pulse the battery in this moment
about every 1 hour?
If yes, this is way too low and thus you could NOT connect a  for instance 10 Watt
load to the battery to have a real load on it and expect that the battery will
not be drained after a few days..

So in this moment you are generating maybe only a few milliwatts
of power, but if you wil take more power out of the battery by running a real load
all the time, the battery will be discharged, before you can rewind the clock
after 30 days..

Maybe you can scale it up by using this new bycicle generator that
Lee Bell tried in his wind mill ( The one, where there is a magnet in
a small plstic housing bouncing back and forth and generating induction,
when an outer magnet is passed by.)

So better try your experiment with a supercapacitor instead of a battery,
so you can be sure, that you really produce overunity with it.
Maybe you can speed the swinging pendulum up in speed,
so it runs faster and you can see the results faster than to wait for
one whole month !

Regards, Stefan.

[wizkycho]

Bill,
why don?t you charge up one bigger capacitor to about 20 Volts ?
Why are you using several capacitors ?
Is there any reason for this ?

well this is not adressed to me, but unlike battery capacitor when charging actually is rising it's "resistance" to a new charge,  so to
charge it well (to much higher voltage (20V)) source has to rise its voltage to overcome that resistance (that would make it inefficient to charge it to 20V). Of course we all now that but sometimes it slips...

wiz