Captret - Capacitor and Electret

[Kator01]

@RomeroUK: Thank you. There is no change with the diodes covered. (Does a diode work different under light? I don't know this... ()

@Kator01: Thank you! Between the ground and neutral line is 72 mV. Is it low?

And I still don't understand what is a difference between the Avramenko plug with just two diodes and AV-plug with more than two diodes?! (Stiffler has 18 diodes as AV-plug in some diagrams. - Why?)
Regards
--michael

Hello Michael,

yes, 72 mV is low. Just measured my loop-current and it is in the same range. Since my house-owner is an electric-engieneer I knwo that he has made all wire-connections at this critical point himself.

in order to understand the Avramenko-plug please study the attached picture. It is a Delon-circuit I once build for stable dual +-powersupply. Each positive halfwave loads the upper capacitor-level, each negative halfwave the bottom-cap-level. In the low-frequency-range of 50 or 60 Hz this only can work if you have the reference-line which is the other terminal of the transformer and which functions as the neutral line for both cap-arrays c1, c3 and c2,c4.

Now if you go up with the frequncy - as in the sec stiffler circuits - to 5 or 10 MHz this rectifying-process also works without a fixed line ( galvanically coupled), because high frequnecies seek ground-level in all metallic surface-areas in the near enviroment. This is done in his circuit-board by a plate attached to the bottom of his epoxi-board and can also be embedded a thin cupper-layer. This plate or layer is then galvanically coupled to the negative terminal of the power-Supply. But it works also without it.

Each additional diode in series increases the possible voltage-level the array can take while in the blocking-phase and second : the total capacity of the diode-array is lowered to 0,1 picoFarad ( it is a guess-value, have to measure the 1n4148 and calculate the total series-capacitance) thus beeing a blocking-filter for the lower-frequency-parts of his output-signal and let the higher frequencies pass easier. So any sharp nano-second-spike can pass easier into any target. His sec-exciter is a spike-generator with a lot of harmonics involved up to the 20 th harmonic of his basis-frequency. So be careful that you do not get into trouble with the administration ( wherever you live ) responsible for telecommunication-frequencies.
This is a fact, not communicated to people who buy his sec-exiters.

Regards

Kator01

[romerouk]

@majkl
Most of the diodes glass encapsulated will act as solar cell. Connect 2 or more diodes in series and measure voltage while exposed to the light. More diodes, more voltage...

Have a nice day,
RomeroUK

[DreamThinkBuild]

Hi Ib,

I built your circuit but had a hard time getting it to charge without going below the original potential of the battery. I tried different diodes(silicon, germanium, schottky) with low +vf but it seemed the lower the +vf the faster it would discharge the battery. I replaced the LED with another cap and that is when I started to get a charging effect that didn't lower the potential of the battery.

Measured last night the battery(9v Alkaline) base reading was 8.692v this morning the measurement was 8.790v.

9volt battery
CT1(captret) = 100uf, 25v + lead has no connection.
C1 = 100uf, 16v

Wired this way

9v- === o(CT1)- === -(C1)+ === 9v+

I'm going to do this test again with another 9v to confirm.

Edit:switched Captret around o(CT1)-

[ibpointless2]

I know i haven't answer many of the questions on this form and other things and thats because the energetic form is more alive with people doing the captret experiment then here. So if you want the latest info please check out the energetic form here

http://www.energeticforum.com/renewable-energy/6684-captret-perpetual-light-dead-batteries-7.html#post116308

The regular captret design will have a voltage drop below the normal standing voltage but what makes the captret unique is that it doesn't keep dropping like in a normal circuit load, the voltage will go up. This should not happen especially when you have a capacitor in series, the captret doesn't play by the rules that we know.

I'll post the last diagram of the latest design i have of the captret just to keep things going here.


The diagram below is very differnt and more advance then the others.
with this new design my standing voltage on the batteries was 17.17
when i put the captret load on it it still stayed at 17.17
and this morning when i woke up it was at 17.19 volts
very strange

enjoy

[DreamThinkBuild]

@All,

I hooked a 1500F, 2.7v ultra cap to the circuit below. I originally charged the cap with solar so the base reading was 2.245v. A hour later it is 2.246v. I will leave this running over night and see what the reading is tomorrow.

I tried a smaller cap and charged it to see if I could keep it going but it drained to quick. You need large caps that will discharge slower than the charge rate.

I noticed one thing on the scope that is odd the DC component has a slight AC component riding on it through the Captret. I'm wondering if this slight AC component is just enough to push it slightly over the source voltage and we are just catching it with the cap. So if your source voltage is 9v and a small AC wave is pushing it over say .001 we have 9.001v charge from our 9v input. As the voltage increases we are still catching this slight imbalance. So if our charge goes to 9.001 + next wave = 9.002v. It's something that needs to be looked at further.