Square tank with round hole in side.
Hole is tapered at the top and bottom just a hair, so that it bows outward. Just a hair.
O-ring is inserted and greased along inside of hole.
Solid ball is built into the hole so that it can rotate in any direction freely. Half of it is inside the tank and half of it is outside the tank.
Outside the tank another ball is held by it's axis, horizontal to ground. It is braced against the earth or a very heavy base.
This second ball is moved up against the first and presses up against it with a pressure equal to what will be the internal pressure on the ball.
The tank is filled with Mercury and the ball spins on it's own, forever.
Pull some power off of it if you want, it's all free energy.
Why it works:
Gravity is pulling on the outside half of the ball. Pulling down.
Buoyancy is pulling up on the inside half of the ball.
Any pressure from the weight of the Mercury that pushes against the ball, which would press it to hard on the o-ring is alleviated by the outside ball pressing back.
The ball wants to float straight up, but we need it to spin, so to keep it from just pushing straight up against the inside ring of the hole, we taper the top of the hole, just enough so that the upward push at that point is inward. That pull is overwhelmed by the rest of the forces acting on the ball, and the ball spins the other way, towards the outside.
(This thread is a Silver Gemstone)
if you check out http://www.lhup.edu/~dsimanek/museum/unwork.htm#cheng
go down to Buoyancy motor #2 you will find your design
and why it don't work.
nice try please play again.
perhaps try a simple model be for you think you have it.
fritznien
Quote from: fritznien on April 17, 2011, 03:56:08 PM
if you check out http://www.lhup.edu/~dsimanek/museum/unwork.htm#cheng
go down to Buoyancy motor #2 you will find your design
and why it don't work.
nice try please play again.
perhaps try a simple model be for you think you have it.
fritznien
Actually, the closest to my design on those pages is here: http://www.lhup.edu/~dsimanek/museum/unwork.htm#buoy2 (http://www.lhup.edu/~dsimanek/museum/unwork.htm#buoy2)
Notice that there are two important differences in my design than this one. The first of course is that in the drawing on the page, the ball is not bisected. Not a big deal but may matter.
The other main difference is that this ball has an axis on the ball itself. As the description states, the upward force here is transferred to the axis, which would simply push straight up and not rotate.
In my design, there is no axis, and so the force is transferred to the 0-ring. In particular the top half of the o-ring. With the top lip tapered outward a bit, the thing spins outward at the top.
All forces exerted by the liquid upon the circumference of the wheel/ball are normal to the wheel's surface, and therefore pass through the wheel's rotation axis. All of these forces have zero lever arm with respect to this axis. The liquid therefore provides no torque about the wheel axis and the wheel won't turn.
or you could make one that works, win a nobell prize and save the world.
in that case i owe you a coke.
not going to hold my breath.
fritznien
fritznien, Correct again. Good work. I do enjoy trying. I find it stimulating and exciting. I'm not a physicist or scientist, but am fascinated with all things in science and technology. Upon reviewing the page you pointed out, I have some new ideas. Hope I run into you again on this forum. Peace to you and thanks for the creative criticism.