Or are subjected greater by a direct force?
Working title : Half baked idea deserves a half baked title?
just a clip (2 minutes shroter than original ) From Segment 8 from RIGB Christmas Lecture 1974-75
http://www.youtube.com/watch?v=qMXNrNevrQ0
(the full lecture, one hour broken in like 19 clips
http://www.gyroscopes.org/1974lecture.asp
Where can I find the modification for force application m/s^2 that is ignored for a spinning mass perpendicular to its axis? ... either the acceleration from the weight due to gravity is a extra force... or that the gyroscope isn't subjected to as much force down?
what is that effect called? I found angular velocity/momementum and can describe them and compute them very well now ( v^2/r ) = (m/s) * (m/s) / (m) = ( m / s * s ) or m/s^2 or m/s2 (aka a force)...
But I cannot find - force calculation for gyroscopic body orbiting another in a circular path
on a level, somethings change.
On a level? It's not like it requires quantum or cosmic aparatus to simulate... seems like a level that's within reach. Wish I had a vomit comet.
So is this a case of somewhat slight of hand... he said 'balance it like a see-saw'... since the entire mass is really on the pivot... anyhow when he releases it if he tosses it upward, would it settle as overbalanced? like a seesaw?
Second - since it wants to fall relative to the pivot, that causes a sideways motion, that when stopped causes a upward tilt on the axis attached to the pivot aorund the center of the mass... which makes it look like it makes the arm goes up becasue the gyro is really trying to roll about its own center of mass?
I'm having problems finding parts to make a similar apparatus
www.physicsforums.com/archive/index.php/t-197183.html
Is an example and math that shows why this happens. And it is because the gravity's pull on the gyro vs the pivot results in a rotation of the gyro, which exerts an upward force.