Throughout recorded history and probably back beyond that, the idea of the psychic vampire has haunted mankind’s dreams. Strange mystical, mythical creatures who lurked in the darker recesses of the human mind, these beings were thought to sap the energy of living mortals, reducing them, unless stopped, to shadows of their former selves. People who, for no apparent reason, became continuously tired, listless and lethargic were often thought to have been visited by vampires or evil spirits.
more...
http://www.whitedragon.org.uk/articles/vampyres.htm
Ok... so non-psychic vampires (aka assholes) let's begin.
Capillary action pulls water uphill (yes/no). Well.. that is yes I think we all agree.
So... what if you were to bend the top of that tube over? Would the water fall out?
Hmm... nope. Why? Well that would be due to the cohesion (aka surface tension) of the water.
Now... to think OUTSIDE of the box. How might it be possible to break that surface tension?
Perhaps a hole in the top that might allow air to break the vacuum/surface tension?
Hmmm?
Quote from: keihatsu on August 02, 2011, 01:03:56 AM
Ok... so non-psychic vampires (aka assholes) let's begin.
Capillary action pulls water uphill (yes/no). Well.. that is yes I think we all agree.
So... what if you were to bend the top of that tube over? Would the water fall out?
Hmm... nope. Why? Well that would be due to the cohesion (aka surface tension) of the water.
Now... to think OUTSIDE of the box. How might it be possible to break that surface tension?
Perhaps a hole in the top that might allow air to break the vacuum/surface tension?
Hmmm?
For the imaginationally-challenged:
- the bend in the tube holds exactly 8 water molecules.
- there is a hole in the top of that bend.
- the lower half of the tube is bulb-shaped.
So... are 8 water molecules sufficient "surface tension" (aka cohesion) to hold the gravitational pull on the larger mass of bulb of water?
Or... are you going to suggest that capillary action will fail due to the constriction of the tube to 8 molecules of water?
Hmmmm....
Awaiting your answer, geniuses.
Quote from: keihatsu on August 02, 2011, 01:14:41 AM
For the imaginationally-challenged:
- the bend in the tube holds exactly 8 water molecules.
- there is a hole in the top of that bend.
- the lower half of the tube is bulb-shaped.
So... are 8 water molecules sufficient "surface tension" (aka cohesion) to hold the gravitational pull on the larger mass of bulb of water?
Or... are you going to suggest that capillary action will fail due to the constriction of the tube to 8 molecules of water?
Hmmmm....
Awaiting your answer, geniuses.
Go study physics idiots.
I solved energy.
I have the patent.
Must I be a Barnum and Bailey marketing machine as well?
Idiots.
All on planet earth.
Idiots.
Quote from: keihatsu on August 02, 2011, 01:16:52 AM
Go study physics idiots.
I solved energy.
I have the patent.
Must I be a Barnum and Bailey marketing machine as well?
Idiots.
All on planet earth.
Idiots.
Now that we have THAT stupid problem out of the way, can we talk about physics?
Over unity....
Interesting concept...
All is one is a simplistic.
More to it....
Goes to language.
Also mathematics.
Quote from: keihatsu on August 02, 2011, 01:23:09 AM
Now that we have THAT stupid problem out of the way, can we talk about physics?
Over unity....
Interesting concept...
All is one is a simplistic.
More to it....
Goes to language.
Also mathematics.
To be honest, I do have a few ideas about that subject and I'm pretty sure on a few things... however... cannot say for certain. I would prefer a few differing opinions and viewpoints.
Is zero a number, for instance?
What is 5 chairs divided by 0 chairs? Are there not 5 chairs remaining?
Quote from: keihatsu on August 02, 2011, 01:29:42 AM
Is zero a number, for instance?
What is 5 chairs divided by 0 chairs? Are there not 5 chairs remaining?
yes, it is. it is a real number. it is an integer and all integers are real numbers.
i think you might be confusing yourself by using chairs... try it with dollars and friends. if you have 5 dollars and 0 friends, and you distribute those 5 dollars equally amongst each of them, how much would each of your 0 friends get? but how can you distribute any amount of money amongst friends who don't exist? your question makes no sense. 30 years ago i used to get under the skin of math teachers with questions like these. good way to burn a whole hour of class time. ;)