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Quote from: microcontroller on May 10, 2012, 10:49:26 AM
becuase the voltage is high enough to make electrons jump from one end of the broken filament to the other closing the circuit.

the halogen gas deposits vaporized metal back onto the filament where it normally would condens on the glass envelope blackening the glass.
i don't think it will burn forever the metal still vaporizes where the spark leaves and hit the filament so the filament slowly melts away.

can u explain why unbroken 12v filament did not light up....?

Hi dreamyear,

what you need to do is connect an AC amp meter to the 230vac side (primary of 1st MOT) to see if there is a difference in current when lighting 2 bulbs (one with broken filament) compared to lighting one bulb.

If the current is the same in both cases then you have something but if the current increases when 2 bulbs are lit compared to one bulb lit then it sounds normal

Thanks for sharing

Luc

Quote from: dreamyear on May 10, 2012, 12:09:26 PM

can u explain why unbroken 12v filament did not light up....?

Hi
same as in a flyswatter  if output contacts are shorted  nothing happens  but if left open  and connected to a normally open relay contacts   produced spark....  just like peter linderman plasma arc mod ( from my understanding)
the busted lamps filaments are broken   to produce light

http://www.intalek.com/Index/Projects/SparkGapExp/SparkGapExp.htm (http://www.intalek.com/Index/Projects/SparkGapExp/SparkGapExp.htm)

THIS PAGE is about Spark Gap Experiments.  It has very good information on it.  Might help you with something your looking for..

Quote from: dreamyear on May 10, 2012, 12:09:26 PM

can u explain why unbroken 12v filament did not light up....?

In two words - "impedance matching".  In more words ......

The 2kV supply source is very likely a high impedance output, and the broken 12 v filament bulb is a perfect high impedance load to suit it.

Spark gaps are a plasma phenomena* whereby the initial resistance of the air gap (or other gas) is high. A high enough voltage is initially required to break down the resistance of the gap,  until an arc appears. Once an arc is established, it can be sustained with low voltages.

If the high voltage drops too low after establishing an arc, the arc will cease. This will create an oscillatory arc, as the supply voltage rises until it reaches breakdown voltage again, re-establishing an arc, which then ceases due to low voltage etc .......

However, an unbroken 12V filament will be a low impedance load, and will immediately, when connected, cause the the high voltage of the supply to drop dramatically. The internal impedance of the supply, being high, will limit the current available to the low impedance filament.

There will be both, insufficient voltage and insufficient current, to normally power the light, due to the high impedance of the supply and the low impedance of the globe.

*The most obvious example of this plasma phenomenon, already put to good use, is the ubiquitous florescent tube lighting system.  This system makes use of high starting voltages, followed by lower running voltages, and was invented by Nicola Tesla. His florescent lighting system is still in use everywhere around the world today.


Cheers