did anyone have using filament to feed electron to the captret in a close system(like vacuum tube)?
Setup:
tin the tube outside with black colour.
captret(highly negative)
positive terminal-> connect to the positive to the load
negative terminal -> to the negative of the load
To begin with, feed electron using filament connecting to a small circuit, then remove.
if the self charging effect is valid, the captret must be charged up with negative ion.
Thinking this way... High RE(low density of -ve) -> Low RE(high density of -ve)= battery
1. Atmosphere is slightly Low RE. Captret terminal connected here
2. positive terminal of the cap tend to move potential to same as the atmosphere.
3. negative terminal tend to stay Low RE
when connecting captret terminal with much negative atmosphere(Much Lower RE), positive terminal become High RE compare to the captret and push ion to negative terminal. Resulting in draining RE into the cap
So, cap voltage(density different) mean easiness of become Low RE that we really need
Actually, I have build a system to make a really big tendency to grab +ve charge, and put those charge into a big capacitor.
big capacitor captret terminal connect to the negative terminal of a capacitor for storage, all -ve and +ve connect to the positive terminal of the storage one.
for the storage capacitor, short captret and the negative terminal, the voltage between the storage capacitor grow up no longer in hour, but few second. (<3s +1mV)
the big capacitor and the storage one (250V 470uF)
I found it!
But i am not sure. it charge my 2.7V 63kF to 0.5V just a second without battery. i short it down to zero and it grow up to 0.5V again in a second!
I have used a Digital and a analog voltmeter to test it, the analog one showing 0.4V , digital one showing 0.6V and growing up.
i am trying to make one to light up 1 LED
It is beyond my understanding of physic!! No heat released in that such a high power charge up....... :o
no matter how many time i discharge, once the circuit is closed, my cap bank just charge up in a second
My tube provide me about around 1.1V right now. When I reduce the pressure inside the tube, the tube seem to give me much higher voltage output from a output terminal.
When I compare the voltage different with the ground, the ground act as a positive side. It is too hard for me to purify the output and amplifier the output to a higher voltage, since it has a strange behaviour of the output, just like a extremely high frequency(cannot be measure by any device) pulse voltage
I can now getting more the 3.4V~3.7V from my tube after shield with PVC, look really like the same as T.H. Moray one.
However, my tube doesn't require any battery.
After I can build something produce more than 12V and light up something like 40W LED, I will share this tube.
Also, I based on the same theory that already made something interesting like this, enjoy.
http://youtu.be/YuqiijUpvxY (http://youtu.be/YuqiijUpvxY)
Updated
My device now can produce 8.96V, however the power is lowered in this setup, out of my expectation :'( :'(
Test:
28p LED, 1/4 brightness
4s LED full brightness
1 LED, burn out
device weight now : 2kg
material of the device: glass, glass powder, metal, plastic, oil
Target: 4kg weight can charge up an iPhone :-[ :-[
5LED full bright
13 LED around 1/2 brightness
my device do not contain any battery. However, in this setup reduced the power output for a higher voltage.
So I will redesign and let it produce a much lower voltage and transform it to around 5V soon.
I can sure this energy is non-stop producing. After I short it down to zero, it will grow up back to the same range of voltage.
When the weather gone bad, the energy produced is around 70%
The spec. of the LED is 3mm 3.0V~3.6V 13~20mA focus light
http://sphotos-f.ak.fbcdn.net/hphotos-ak-prn1/417673_10151484426256052_1551950029_n.jpg (http://sphotos-f.ak.fbcdn.net/hphotos-ak-prn1/417673_10151484426256052_1551950029_n.jpg)
http://sphotos-d.ak.fbcdn.net/hphotos-ak-prn1/60401_10151484665841052_1868304443_n.jpg (http://sphotos-d.ak.fbcdn.net/hphotos-ak-prn1/60401_10151484665841052_1868304443_n.jpg)
The huge tube radial energy generator is in process......
The below thing is my tube using captret in high voltage, a 9V battery used.
http://www.youtube.com/watch?v=-ZGbGzhtqZo (http://www.youtube.com/watch?v=-ZGbGzhtqZo)
Sorry for the late update. I am still working on the prototype generator.
I received serval questions about the tube, I will only answer some questions.
1. I am not planning to show the circuit, since what I am building a huge prototype generator using the same theory and similar circuit. I can only provide limited information about the tube.
2. 3 terminals(including captret) of a capacitor will be use, none of the terminal with no connection.
3. The tube(the jar) showing in the picture having a foil inside as negative and foil outside as positive(0 V, "antenna" in my theory), the foil outside masked with tape
4. The tube(the jar) inside is low pressure, some water vapour maybe. (I pour alc. into the jar, light it up, pour out water and shield it fast)
Hi dequadin,
Greetings from HK! I have written a comment in your YT channel. Congratulations! Your discovery seems to be very impressive, using the captret concept. Plengo would be very interested in knowing someone has developed a better captret application from his original ideas.
I look forward to learn more from you. I currently do R & D in joule thief alike circuits.
Keep up the great work, bravo!
aaron5120
I have made the small scale of RE electric generator to light up a LED.
No battery involve at this time!
Energy from what we call "self charging effect", thats prove the RE does exist around us
http://www.youtube.com/watch?v=7zUKmH4YqVk (http://www.youtube.com/watch?v=7zUKmH4YqVk)
I will continue my research on this type of energy.
I tried my best to interpret your description of the modified captret device. This was done for the benefit of the fellow researchers here in OU.com in getting a visual idea of what you are currently doing. Sorry if the setup does not match closely to your actual connection.
You may choose to enlighten us a little bit more with your clarification. Thank you for sharing.
aaron5120
Not really look like arron5120 mention.
The jar I call it R.E. Receiver, 9V battery involved.
You can only see 3 terminals on the jar, all the circuit and stuffs placed inside the jar.
The Captret is placed inside the the jar, the storage capacitor too.
I highlight the foil is placed inside and outside the jar, the foil outside is feed-back to the jar as antenna.
The foil inside is slightly negative and feed to a small circuit then connected to captret with a 9V battery negative terminal.
Another picture is the design of the scale-down RE generator that "without" involve any battery.
It weights about 1.3kg placed in a gift box, 2 terminals for positive and negative.
Without the Load, its voltage above 24V, when the output after shorted, the voltage will suddenly grow up to 4V instantly, and +1V/s,+0.5V/s,+0.1V, half-hour with grow up to around 24V
With Load(LED 3.3V 20mA focus light), its voltage around 3.2V with around 11~12mA(just guess by compare the brightness)
Updates:
1. I find my sponsor for this research.
2. I have tried using joule thief to drain the energy from my tube, but this doesn't work(unstable voltage, what is the load for the transistor then?....using adjustable 3kohm, can't be tuned on the right spot)
3. new design is planning
Thanks all for the support
Now I see, you came here at OU.com with the intention of finding sponsors for your project.
Joule thief is a blocking oscillator, and is not a stable oscillator per se, its oscillation frequency fluctuates when the power source diminishes its voltage potential.
Choose other oscillation circuits if you want stable resonant tuning spot.
Good luck to your new design. We come here to share our projects for free.
Quote from: aaron5120 on March 25, 2013, 11:02:14 PM
Now I see, you came here at OU.com with the intention of finding sponsors for your project.
Joule thief is a blocking oscillator, and is not a stable oscillator per se, its oscillation frequency fluctuates when the power source diminishes its voltage potential.
Choose other oscillation circuits if you want stable resonant tuning spot.
Good luck to your new design. We come here to share our projects for free.
Correction: I should say I have found my sponsor on last weekend.
Yea, JT does not work for this project. So I have order some ferrite rod and U shape ferrite for the next research.
What I have right now is a generator fully running a LED not too bright without any batteries..........until now.
So, I proved the self-charging effect is an additional energy coming from the cap or the capacitor act like a battery, who's knows....
Quote from: dequadin on March 25, 2013, 11:33:42 PM
Correction: I should say I have found my sponsor on last weekend.
Yea, JT does not work for this project. So I have order some ferrite rod and U shape ferrite for the next research.
What I have right now is a generator fully running a LED not too bright without any batteries..........until now.
So, I proved the self-charging effect is an additional energy coming from the cap or the capacitor act like a battery, who's knows....
Well, Dequadin,
So much for the utilization of using this forum as a means of sharing ideas for the rest of the members here ---
You wasted everyones time here. Accept of course the new sponser that you tricked into your accepting your idea.
You, sir, are a jerk! -- "DO NOT LET THE DOOR HIT YOU ON THE WAY OUT"--
Paul
Quote from: PARAV on March 26, 2013, 07:11:07 PM
Well, Dequadin,
So much for the utilization of using this forum as a means of sharing ideas for the rest of the members here ---
You wasted everyones time here. Accept of course the new sponser that you tricked into your accepting your idea.
You, sir, are a jerk! -- "DO NOT LET THE DOOR HIT YOU ON THE WAY OUT"--
Paul
Did I really not sharing the ideas?
you are representing everyone?
Do you even thing about the how to apply the theory into practical?
Do you even try?
Please be respect
Quote from: dequadin on March 26, 2013, 08:58:26 PM
Did I really not sharing the ideas?
you are representing everyone?
Do you even thing about the how to apply the theory into practical?
Do you even try?
Please be respect
Hi Dequadin,
Yes, with all due respect sir, I may have been a little too brash about this , but still ---The information you submitted was very vague. You refused to submit a schematic. The drawing of what looked like a Leydan Jar shows nothing. What's a guy suppose to do with a theory and with no pertinent information to start on?
Your theory and ideas may have been grasped by some of the guys but it went way over my head I guess.
Good luck with your venture.---Paul
Quote from: PARAV on March 27, 2013, 12:43:06 PM
Hi Dequadin,
Yes, with all due respect sir, I may have been a little too brash about this , but still ---The information you submitted was very vague. You refused to submit a schematic. The drawing of what looked like a Leydan Jar shows nothing. What's a guy suppose to do with a theory and with no pertinent information to start on?
Your theory and ideas may have been grasped by some of the guys but it went way over my head I guess.
Good luck with your venture.---Paul
Actually I don't really see your respect, you haven't ask for any clarify idea. Your act quite nonsense. Yes, Sir, you jerk too
There is no free lunch in the world, just free energy.
Did Tesla showing what is the circuit inside the "black box" to the public?
Did Tesla provide his AC generator invent for free at first?
Everything start with theory, not information of an existing "thing"!
If I give so much information, everyone will based on what I provide and stop thinking another designs like you. What a shame!
If I haven't find my angel funding, I can't even afford for those expensive caps.
I left the design of the generator below. Cuz I have redesigned another tube in better output and reduced weight.
http://youtu.be/gykT-j96caY (http://youtu.be/gykT-j96caY)
I started thinking the guys right here mostly are not inventor but the one with the rusty mind
Hi Dequadin,
You R free to share whatever you are willing to share here in this forum, as Internet is a free world for everybody to participate in it.
And we appreciate very much what you have released until now being the generator circuit Version 1.0 to us.
Your disclosure so far is enough for us to start experimenting with.
Keep on your good work, and when you have success with your new design, the sole good news will make us joyful and excited so much as to you.
We all need to use our brain, and invent, otherwise, we are reduced to a punch of armchair critics.
aaron5120
Dequadin,
Can you say what brand (and type) of capacitors you are using?
Also, what kind of reasoning led you to put all the capacitors into a shielded jar?
Keep up the good work... :-)
GL.
Quote from: Groundloop on March 28, 2013, 09:19:49 AM
Dequadin,
Can you say what brand (and type) of capacitors you are using?
Also, what kind of reasoning led you to put all the capacitors into a shielded jar?
Keep up the good work... :-)
GL.
those caps are not cheap, for such a high freq. source, what caps will you use?(T.H. Moray signal detector give us hints )
the reason is the foil is easy to capture charge, not the legs of those cap.
when it's complete shield, the output will more stable and voltage drop slower.(maybe output more)
in fact, the effect of put all the capacitors into jar is not huge changes, just better than nothing.
Since the output still small, hard to measure the different.
But one thing that I observed is the temperature does matter. When the cap is heated up, the output is far
lower than the room temperature. Shield it into jar can separate the from the heat source.
And what I want is to make it portable.
Hi Dequadin,
If the output of your captret generator decreases with heat, maybe it is due to the negative temperature coefficient of the capacitance with respect to the increase of ambient heat. That is, the higher the temperature, the lesser the capacitance, hence the lower total output potential.
There are electrolytic capacitors that have positive temperature coefficient of capacitance. That is, the higher the temperature, the higher the capacitance. Hence, choosing this kind of capacitors, maybe you can take advantage of the ambient heat to harness more output, and will not be necessary to isolate the caps from the exterior ambient.
Quote from: aaron5120 on March 29, 2013, 01:55:21 AM
Hi Dequadin,
If the output of your captret generator decreases with heat, maybe it is due to the negative temperature coefficient of the capacitance with respect to the increase of ambient heat. That is, the higher the temperature, the lesser the capacitance, hence the lower total output potential.
There are electrolytic capacitors that have positive temperature coefficient of capacitance. That is, the higher the temperature, the higher the capacitance. Hence, choosing this kind of capacitors, maybe you can take advantage of the ambient heat to harness more output, and will not be necessary to isolate the caps from the exterior ambient.
I know what you mean. My caps are naturally colder than air, that should be because of the turning RE into electric.
You should try different caps. I also based on some theory and started making something. (In my opinion, cold thing is better, chemical reaction is mostly related to heat)
I don't know how, try make it out and test it.
I am thinking to reform the caps or "conditioned" the cap, it should self-charge faster than normal cap.
If no one know what type of capacitor should use in this generator, please try UC, but not the hybrid type.
I have found that, the reformed or "conditioned" cap will self-charge faster than a normal cap.
The reforming process is .....(caution: if over-charged your cap, it will be damaged and explosive)
1. short 2 legs and connect positive power supply
2. captret connect negative power supply
3. power supply should be higher voltage than the cap's voltage(don't supply too much! Make sure no "swelling" of your cap!)
4. cap should be heated up a little bit, heat it up in addition source(caution: beware the explosion, no direct heat!!)
5. disconnect with power supply, wrap paper than wrap foil to maintain the temperature not to cool down so fast
6. let it cool down for 1 whole days.
7. Test it (short 2leg and captret, disconnect, test the self-charging effect. If no self-charge effect, your cap is dead)
The reforming cap should be around 30% faster in self-charge effect, and around 25% more voltage output.
(reforming process can be effective if provide a radial beam through the cap, which I don't have the radial substance/source)
Hi Dequadin,
Many thanks for sharing your progress in this project.
In regard with your latest hints, I have a few questions, which are more or less irrevelant, just due to my ignorance of the Electronic Engineering jargons:
1) You recommend the use of UC for the caps. Please confirm UC means Ultracapacitors.
2) I wonder if the conditioning of the caps will shorten the lifespan of usage of the caps, because the heating will dry up the electrolyte inside the cap eventually.
3) What do you mean radial beam? Is it radio frequency waveform ? Or does it mean radial position instead of axial position to the capacitor? Does Radial source mean a radio frequency source ?
Thanks a lot for clarifying these terms.
aaron5120
I have not posted results of my replication, because until tomorrow I will be able to go to Shenzhen city to buy the caps for the experiments. I plan to buy electrolytic caps ranging from 0.047uF to 30uF, 6V to 10 V capacitors of low ESR for selecting the best capacitance for the negative bias effect.
aaron5120
Quote from: aaron5120 on April 01, 2013, 11:47:46 PM
Hi Dequadin,
Many thanks for sharing your progress in this project.
In regard with your latest hints, I have a few questions, which are more or less irrevelant, just due to my ignorance of the Electronic Engineering jargons:
1) You recommend the use of UC for the caps. Please confirm UC means Ultracapacitors.
2) I wonder if the conditioning of the caps will shorten the lifespan of usage of the caps, because the heating will dry up the electrolyte inside the cap eventually.
3) What do you mean radial beam? Is it radio frequency waveform ? Or does it mean radial position instead of axial position to the capacitor? Does Radial source mean a radio frequency source ?
Thanks a lot for clarifying these terms.
aaron5120
1. Yes, I mean Ultracapacitor. If you have read T.H. Moray patented tube, he use ultracapacitor in his signal detection tube.
2. Maybe...however I need more power, all or nothing, no matter what.
3. I always miss-typing, no time to check. It should be radiation beam, radiate substances are hard to obtain for the test. After the reforming the capacitor with high radiation density, it will memorise the radiation density and drain more to maintain the radiant density inside after the reforming process in theory(I haven't test this one, cuz I don't have those radiation source).
@dequadin.what exactly in the most simple terms have you got ther.a self-charging cap? Is there oil in the cap?are the two plates of the cap made from different metals and is there a trace of moisture in the cap?lets get to the bottom of this using textbook science.
Quote from: profitis on April 02, 2013, 06:13:54 AM
@dequadin.what exactly in the most simple terms have you got ther.a self-charging cap? Is there oil in the cap?are the two plates of the cap made from different metals and is there a trace of moisture in the cap?lets get to the bottom of this using textbook science.
Please understand what is "Captret" first. Then you will know what I mean.
We don't use textbook science, since no "captret" on any textbook science and no "self charge effect" and no "free energy".
if you would like to know where does the terms located on the textbook science, please ignore this post. :)
ok mr dequadin.i just thought you might be intrested to know that the slightest traces of moisture in any capacitor will induce standard galvanic voltage and current,especially after its been charged due to chemical changes at electrodes.if you can rule that out then you may be onto something.
Quote from: profitis on April 02, 2013, 02:43:11 PM
ok mr dequadin.i just thought you might be intrested to know that the slightest traces of moisture in any capacitor will induce standard galvanic voltage and current,especially after its been charged due to chemical changes at electrodes.if you can rule that out then you may be onto something.
So?? ???
You can say due to the impurity of the chemical inside the cap, it acts like a weak battery.
But can a normal battery run a LED lighting for such a long time I wondered. (I use the blue light LED which is quite power consuming)
Also, we can short every terminal to the ground for a week, and a voltage gaining we can observed after the disconnection.
what's more, the same metal of the electrodes in most of the capacitor actually.
No matter what, how to use a capacitor is your own choice.
You may think it is a weak battery, but what I think it can be possible to be other thing for me to obtain those static charge :)
people seem to think that identical electrodes of highly reactive aluminum wil giv zero galvanic but they conveniently forget that oxygen in air and hydronium ions in water both attack aluminum nonstop slowly giving eddy currents in each electrode.the Al2O3 layer thickeness differences will also play a role.you can short it for weeks and you still get voltage,its a slow chemical combustion
if u want to strictly rule out chemical combustion you can try platinum,gold foil,or graphite electrodes
Apart of electrochemic processes - a cap with more complex geometry than a perfect plate cap in vacuum is never empty.
If you discharge such a cap by chort-circuit its leads - you nullify the output voltage. This doesn´t mean that the cap is chargewise completly empty.
The sum of all internal voltages in combination with the charge distribution after short circuit is "0".
This means that there are residual voltages and charges which nullify in relation to the leads.
Due to distributed leakage - this residual charge may rearrange after certain time - giving a rising voltage at the output leads.
This effect can increase dramatically if you switch to electrolytic caps, adding up electrochemical processes.
fyr.
Quote from: fritz on April 03, 2013, 10:26:18 AM
Apart of electrochemic processes - a cap with more complex geometry than a perfect plate cap in vacuum is never empty.
If you discharge such a cap by chort-circuit its leads - you nullify the output voltage. This doesn´t mean that the cap is chargewise completly empty.
The sum of all internal voltages in combination with the charge distribution after short circuit is "0".
This means that there are residual voltages and charges which nullify in relation to the leads.
Due to distributed leakage - this residual charge may rearrange after certain time - giving a rising voltage at the output leads.
This effect can increase dramatically if you switch to electrolytic caps, adding up electrochemical processes.
fyr.
good to hear other voices.
So, I would like to ask a question. I know you are mentioning about the "relaxation" of a cap.
however, the time for the "relaxation" should be enough in a week of time. You can compare the different between the voltage different of 2 leads of the cap with the voltage different of captret & 2legs. The result is 2 leads near the same potential, however 2leads & captret around 0.5V in serval minute.
Can you explain why?
Only one thing can let the "relaxation" can't be effective, which is high freq. And that will pulsing the -ve charge from the chemical to be electronic/ionize towards the captret.
I am not going to say the sum of all internal voltage is "0" after short circuit, but same potential. as we know, both 3 metal plate are separated with capacity characteristic. The chemical which should shared for 3 plates, how 3 plates act differently?
Yes, you can say because of weak battery characteristic of a lytic cap. But can how we separate the terms of battery and generator?
chemical process!?who's knows!
So, I am trying to increase the output power from these cap in my project. :D
what happened in the end ?
Quote from: casstete on April 26, 2014, 08:09:05 AM
what happened in the end ?
2~3W output has been made, however the power output can't be step-up even scaling up the device in 10 times.
I am still developing and trying to solve this problem.
The output just like a static charge.Even I shorted the circuit, it won't heat-up.
That's what I am facing. I haven't gone! I am still working on it.
Quote from: dequadin on April 27, 2014, 09:42:50 PM
2~3W output has been made, however the power output can't be step-up even scaling up the device in 10 times.
I am still developing and trying to solve this problem.
The output just like a static charge.Even I shorted the circuit, it won't heat-up.
That's what I am facing. I haven't gone! I am still working on it.
when you scale it do you increase the load potential as well ? Do you make a larger device without a load or same load or increase the load ?
I agree with you that the galvanic process can't be seperated from the potential teluric energy .
IF you increase the load and it rises you however have a classic "free energy " device . Jean Luis Naudin explains this on his Lenzless generator Page .
Electricity is a expression of magnetism so it's the same effect you should see and we also see it on Bedidni's wheel that requires less energy from source when load battery are empty & wheel is spinning full speed than full battery slow spinning wheel .
+ Bedini claims ( and so do others ) that the wheel spins faster at full mon , chec to see if you get a potential difference at full moon ; )
A little out there but why not
Quote from: casstete on April 29, 2014, 08:45:37 AM
when you scale it do you increase the load potential as well ? Do you make a larger device without a load or same load or increase the load ?
I agree with you that the galvanic process can't be seperated from the potential teluric energy .
IF you increase the load and it rises you however have a classic "free energy " device . Jean Luis Naudin explains this on his Lenzless generator Page .
Electricity is a expression of magnetism so it's the same effect you should see and we also see it on Bedidni's wheel that requires less energy from source when load battery are empty & wheel is spinning full speed than full battery slow spinning wheel .
+ Bedini claims ( and so do others ) that the wheel spins faster at full mon , chec to see if you get a potential difference at full moon ; )
A little out there but why not
The load was the same. :( :(
The output still the same.
I have another idea and designs for this project using a special mineral powder instead of the old version one.
I won't tell much. Once I have done something I may show more details ??? ???
I am planning to apply the cold cathode to the tube.
If the water vapour can absorb UV/RE energy and charge up the electrons produced by the cold cathode, the tube may produce higher output?
I don't know, but better have a try.
If this theory is true, the oil in the capacitor acts like a absorber of UV/RE energy and charged up the electrons within the capacitor itself.
So, cold cathode should apply in the tube ??? I hope so...
i have a 450v 4700uf big capacitor, i short circuit the captret terminal and +- terminal and release,after 2 seconds,
the voltate between captret terminal and +- recover to 0.2 V and climb up slowly when i using a digital meter.
dequadin, what type of capacitor are you use? is your captret when unconditioned ,the voltage will recover to >0.35V after 2 seconds?
i locate in 珠3角，i can buy all the cap in taobao in a very low price.
http://item.taobao.com/item.htm?spm=a1z0k.7385961.1997985097.d4918997.XQB9dW&id=41770328569&_u=j11julnpc46d
this PHILIPS 6.3v 100uf one cost 390rmb about 500HK or 70usd per one, are your cap more expensive than this?
sorry,i dont understand what you described ，so i draw a pic.is this what you means?
Quote from: dequadin on February 21, 2013, 03:11:59 AM
did anyone have using filament to feed electron to the captret in a close system(like vacuum tube)?
Setup:
tin the tube outside with black colour.
captret(highly negative)
positive terminal-> connect to the positive to the load
negative terminal -> to the negative of the load
To begin with, feed electron using filament connecting to a small circuit, then remove.
if the self charging effect is valid, the captret must be charged up with negative ion.
Thinking this way... High RE(low density of -ve) -> Low RE(high density of -ve)= battery
1. Atmosphere is slightly Low RE. Captret terminal connected here
2. positive terminal of the cap tend to move potential to same as the atmosphere.
3. negative terminal tend to stay Low RE
when connecting captret terminal with much negative atmosphere(Much Lower RE), positive terminal become High RE compare to the captret and push ion to negative terminal. Resulting in draining RE into the cap
So, cap voltage(density different) mean easiness of become Low RE that we really need
Quote from: rapbbit on November 18, 2014, 10:55:51 PM
sorry,i dont understand what you described ，so i draw a pic.is this what you means?
Sorry for late reply. Actually, nope. I use super capacitor in previous device.
And I am trying to explain how this device works by using another materials.
Vacuum tube is one of my choice. However I don't have enough ability to produce vacuum tube by myself.
Your pic is not correct, the tube have 4 connection points, 2 are connected to ground, 1 is antenna, 1 is power out line.
I am still thinking how to make an experiment to ensure whether this theory work or not.
Quote from: dequadin on November 24, 2014, 08:32:30 PM
Sorry for late reply. Actually, nope. I use super capacitor in previous device.
And I am trying to explain how this device works by using another materials.
Vacuum tube is one of my choice. However I don't have enough ability to produce vacuum tube by myself.
Your pic is not correct, the tube have 4 connection points, 2 are connected to ground, 1 is antenna, 1 is power out line.
I am still thinking how to make an experiment to ensure whether this theory work or not.
i think most of us in this thread wish a base circuit as what your described，because most of us not understand what you described in your first post in this thread. not need the detain operation,just the base circuit.
KESHE have a gans battery than will last many year for a consistent output,maybe that's a similar version of yours.
Yeah, I'd really like to give this a try. I was thinking the answer might lie in hooking treated captret up to an Esaki Effect LED flasher circuit. This might get round the issue of this configuration not working with standard joule thief type oscillators?
Quote from: rapbbit on November 25, 2014, 09:49:37 AM
i think most of us in this thread wish a base circuit as what your described，because most of us not understand what you described in your first post in this thread. not need the detain operation,just the base circuit.
KESHE have a gans battery than will last many year for a consistent output,maybe that's a similar version of yours.
I have provided the base circuit in these posts. Please read again.
i suspect the negative terminal of this battery can replace with a true earth ground according some tesla technology.
but i need some experiment to confirm it.
i think this thread have relative to some very important basic operation of tesla technology ,
if you have read some tesla patents,note and speech,you will understand it.
thanks dequadin for providing this valued demonstration.
i think this thread have relative to some very important basic operation of tesla technology ,
if you have read some tesla patents,note and speech,you will understand it.
thanks dequadin for providing this valued demonstration.