For example how many #24 wires equals a #19 wire?
Thanks in advance.
Are you thinking of current carrying capacity?
Patrick's first appendix shoud assist:
http://www.free-energy-info.com/Appendix1.pdf
If you are talking about area, then the area of the cross section is pi times radius squared
(You will get the radius or diameter from Patrick's tables).
Okay.
So the area of a #24 wire is .205 mm2 and the area of a #17 wire id 1.04 mm2.
That would indicate that it would take 5 #24 wires to make the equivalent of a #17 wire.
Does that sound right to you?
Thanks, I appreciate it.
Paul-R. your answer poses a question I don't know the answer to.
Does a number of smaller wires carry the same current as a larger wire of the same area?
Quote from: rukiddingme on January 17, 2014, 04:58:48 AM
Does a number of smaller wires carry the same current as a larger wire of the same area?
did you mean ?
"Does a number of smaller wires carry the same current as a larger wire of the same VOLUME "
Why not weigh the wire, cut one or two inch pieces and weigh them.
what to do with the weight @Dave45
Every three gauge steps almost identically doubles the area of the wire. If you go up five wire gauges, then you will need four of the smaller diameter wires to get below the resistance of one of the larger wires at DC. For AC currents, the ratios converge due to the skin effect. It's not that little wires get better, it is that thick wires get much worse.