let us take two coils, that measure 2 ohms
Now if we connect these in parallel, as many
of you audio buffs out there know, you have
Only 1 ohms......
Hmm ok
So we have our parallel coil of 1 ohms
And we couple this inductively to a single primary coil
Which itself measures 1 ohms
A nice core might help but that just complicates the
Math. We can use air, and find the L for each one.
So we have a 3 coil transformer, two coils in parallel
And both paths measure 1 ohms.
Well certainly the laws of induction dictate that one
coil has many more turns than the other, and thereby
each must have a different induction.
So what happens when this coil induces a voltage in the
secondary?
More importantly, what happens when a/c current runs
through the transformer?
In a/c: Inductive Reactance is the equivalent to impedance
or Resistance, and Ohms law still applies.
It is defined as R(x)= 2(pi)fL
Where f is the frequency and L is the inductance in Henries.
Frequency - we can control that......
What is this L thing? and why does it change?
It is always two things. No matter what coil
We can take these two things and twist and bend them
Flip them this way and that.
L is always two things.
The electric and the magnetic.
These two things are mathematical constants of the universe.
All we can do is change one dimension by affecting the other
And we do this by the inductive/capacitive exchange mechanism
It's like a trade off. We change our L by making the wire longer,
Adding more loops, using thicker wire, and changing the diameter
of the loops. (Note: the loops of a coil need not all be the same diameter)
LC =em always
What I propose, is a uniquely wound transformer
One the inductance of which follows a simple equation
There are a multitude of combinations that could be used
But the condition must hold true for both the primary coil
and the secondary double-coil.
Whatever frequency you want to run this at
The inductance of both paths of the transformer
Must be:
L = 0.159154943/f
At that frequency sir Georg Simon Ohm will destroy
Thermodynamic Theory, from his grave.
I didn't get it. Do you have any test setup?
Radius of a circle gives us a length.
That length bent around the circumference of that same circle covers 57.29577951 degrees of it.
57.29577951 / 360 = 0.159154943
I'm not sure why we would divide it by 360 (besides the Egyptians supposedly doing so), but ho hum, that's Smoky2's number.
I only have one comment and it is something I feel is often overlooked in the search for Free Energy, but in many circuits even if Free Energy appeared it would simply lead to an increase of whatever conventional energy is also used.
For instance if we had a battery and a bulb, the only likely way for Free Energy to occur would be as a voltage being induced in the circuit to increase the current.
But if the current increases even from Free Energy being induced, the battery will still be drained more rapidly (the battery might drain twice as fast but the load might burn up 4 times more energy).
What is needed besides whatever is used to get the Free Energy is a loosely coupled transformer, or some diode setup (Bridge rectifier) or something that will not put the gained energy through the input power.
Another option is a collapsing EMF from a coil, something that won't reflect on the input.
John
Quote from: aether22 on February 10, 2017, 06:19:20 AM
Radius of a circle gives us a length.
That length bent around the circumference of that same circle covers 57.29577951 degrees of it.
57.29577951 / 360 = 0.159154943
I'm not sure why we would divide it by 360 (besides the Egyptians supposedly doing so), but ho hum, that's Smoky2's number.
Interesting way to get to that number. Hmmm.....
Just to clarify, this is not "my number".
The mathematics came directly from Mr. Ohm himself.