Can anyone translate the gist of these two videos to english for me?
In my opinion he appears to be a modern Tesla/Figuera whom like them has discovered, or rediscovered some very nice energy secrets.
How does a little cap help with Lenz? I assume in the other video he is using Lenz to rotate the motor?
https://youtu.be/ZU2OBFky2B0
https://youtu.be/3uAnWtjpn5M
You can turn on CloseCaption [CC] on YouTube player and then choose auto translate to English from the settings.
Thanks kEhYo77. Much appreciated. And thanks again to the skycollection for sharing his work with us all!
So he uses a capacitor in the video to prevent Lenz. How does a simple cap achieve that?
I've learned from TinMan that current can keep flowing the same direction even if the voltage, aka the polarity of the charge changes. Is the changing of voltage polarity what lenz is? The cap keeps enough juice in the line long enough during a pulses off time to prevent a voltage polarity change and therefore stops lenz from manifesting?
In the second video, the translation was really bad but I got the idea that he really likes things to be 90 degrees to something else to keep Lenz from slowing things down? Not sure what a cap and 90 degrees have in common yet. Some kind of phase shift stuff going on perhaps?
It is posible the currest pass in one direction...!
Thanks for the info Skycollection1.
Is that how the capacitor stops the Lenz, by preventing the voltage from reversing?
Thanks for the info Skycollection1.
Is that how the capacitor stops the Lenz, by preventing the voltage from reversing?
I used many kinds of capacitors and only one Works, is a small capacitor from a high voltaje lamp (http://www.afinidadelectrica.com/articulo.php?IdArticulo=35) i really don´t know the reason
why this small capacitor reduce or delate the Lenz effect...! If you can investigate this effect you will find that the rotor do not stop with this capacitor. I hope it serves for you...!
A Capacitor provides low impedance for faster changes in voltage. This leads to large current, whenever voltage tends to change instantaneously.
When the voltage increases fast, capacitors draw large current from the voltage source. This current creates drop in internal resistance of the voltage source.
When the voltage reduces instantaneously, capacitors provides large current to the voltage source, which partially compensate the original reduction in the voltage. This current crates drop in internal resistance of the voltage source.
So can we say that capacitor opposes instantaneous changes in voltage? I think, this statement /question is little confusing. Better way is to say that "capacitor absorbs instantaneous changes in voltage"
https://www.quora.com/Why-does-a-capacitor-oppose-instantaneous-changes-in-voltage (https://www.quora.com/Why-does-a-capacitor-oppose-instantaneous-changes-in-voltage)
"If you have 10v across a 10uF capacitor, and the voltage has been steady for long enough, then no current flows. If you now try to change the voltage to 20v, ramping it up at 10^6 volts per second, so it takes 10uS to change from 10v to 20v, the current will go to 10A for that 10uS, and back to zero when the voltage is steady again. If you try to change the voltage at 10^7 volts/second, the current pulse will be 100A.
That sort of current amounts to a fairly violent 'objection' to the voltage being changed. If the power supply cannot supply it, then the voltage will not change as fast as expected."
https://electronics.stackexchange.com/questions/361661/how-does-a-capacitor-resist-changes-in-voltage (https://electronics.stackexchange.com/questions/361661/how-does-a-capacitor-resist-changes-in-voltage)
Could it be that the capacitor is absorbing the increase in voltage across the primary due to cemf? In this case the source would be the primary coil. The actual circuit source would be unaffected and would only have to supply enough current to maintain the magnetizing current.
Quote from: tomd on April 14, 2018, 09:04:48 PM
A Capacitor provides low impedance for faster changes in voltage. This leads to large current, whenever voltage tends to change instantaneously.
When the voltage increases fast, capacitors draw large current from the voltage source. This current creates drop in internal resistance of the voltage source.
When the voltage reduces instantaneously, capacitors provides large current to the voltage source, which partially compensate the original reduction in the voltage. This current crates drop in internal resistance of the voltage source.
So can we say that capacitor opposes instantaneous changes in voltage? I think, this statement /question is little confusing. Better way is to say that "capacitor absorbs instantaneous changes in voltage"
https://www.quora.com/Why-does-a-capacitor-oppose-instantaneous-changes-in-voltage (https://www.quora.com/Why-does-a-capacitor-oppose-instantaneous-changes-in-voltage)
"If you have 10v across a 10uF capacitor, and the voltage has been steady for long enough, then no current flows. If you now try to change the voltage to 20v, ramping it up at 10^6 volts per second, so it takes 10uS to change from 10v to 20v, the current will go to 10A for that 10uS, and back to zero when the voltage is steady again. If you try to change the voltage at 10^7 volts/second, the current pulse will be 100A.
That sort of current amounts to a fairly violent 'objection' to the voltage being changed. If the power supply cannot supply it, then the voltage will not change as fast as expected."
https://electronics.stackexchange.com/questions/361661/how-does-a-capacitor-resist-changes-in-voltage (https://electronics.stackexchange.com/questions/361661/how-does-a-capacitor-resist-changes-in-voltage)
Could it be that the capacitor is absorbing the increase in voltage (by way of current draw) across the primary due to cemf? In this case the source would be the primary coil. The actual circuit source would be unaffected and would only have to supply enough current to maintain the magnetizing current.
The idea is to filter out any voltages higher than the voltage which maintains the magnetizing current.
Further on this. The voltage required to maintain the magnetizing current is the source voltage minus the self induced voltage from the primary. So the idea is to stop the source from "seeing" the cemf voltage from the secondary. As this voltage will bring the voltage accross the primary back up to the source voltage and will result in a larger current draw.
http://www.physics.usyd.edu.au/~khachan/PTF/Transformer%20explanation.pdf (http://www.physics.usyd.edu.au/~khachan/PTF/Transformer%20explanation.pdf)
YO ALL THIS IS A CIRCUIT THAT WILL REDUCE LENZ EFFECTS.
Quote from: seychelles on April 15, 2018, 06:17:55 AM
YO ALL THIS IS A CIRCUIT THAT WILL REDUCE LENZ EFFECTS.
Pulsed DC in primary?
OR JUST AS A GENERATOR COIL..
I used this circuit with the diode as indicates the drawing but again the LENZ EFFECT stop the rotor 50% and when i eliminate the diode the lenz effect disappears...! i do not need a diode in the circuit
just the small capacitor.
Today i have some improvements in the motor and new results, ZERO LENZ EFFECT
https://www.youtube.com/watch?v=1wCjuuBVZlg
Quote from: skycollection 1 on April 14, 2018, 12:43:20 PM
...If you can investigate this effect you will find that the rotor do not stop with this capacitor. I hope it serves for you...!
Thanks for the info. Very helpful. I hope to incorporate your finding into a build and report back. Can't thank you enough for your efforts and especially for sharing such efforts with us all.
@tomd- Intriguing take on what may be happening here. Sound like a good path to pursue to me.
@seychelles- I've heard of good things with and without a diode. Sounds like a good idea to try one out hear and interesting how skycollection mentions it may not always help or be needed. Something to think about for sure.
Quote from: skycollection 1 on April 15, 2018, 07:08:32 PM
Today i have some improvements in the motor and new results, ZERO LENZ EFFECT
https://www.youtube.com/watch?v=1wCjuuBVZlg
Great job again!
Time for more coils surrounding the rotor for maximum effect?
Quote from: MagnaProp on April 10, 2018, 01:08:10 AM
Thanks kEhYo77. Much appreciated. And thanks again to the skycollection for sharing his work with us all!
So he uses a capacitor in the video to prevent Lenz. How does a simple cap achieve that?
I've learned from TinMan that current can keep flowing the same direction even if the voltage, aka the polarity of the charge changes. Is the changing of voltage polarity what lenz is? The cap keeps enough juice in the line long enough during a pulses off time to prevent a voltage polarity change and therefore stops lenz from manifesting?
In the second video, the translation was really bad but I got the idea that he really likes things to be 90 degrees to something else to keep Lenz from slowing things down? Not sure what a cap and 90 degrees have in common yet. Some kind of phase shift stuff going on perhaps?
It appears the effect is due to phase shift although I don't understand how. In an inductive circuit Voltage leads current by 90 degrees and in a capacitive circuit voltage lags current by 90 degrees.
This experimenter is doing pretty much the same thing. https://www.youtube.com/watch?v=4p9feKmnPNU (https://www.youtube.com/watch?v=4p9feKmnPNU)
One of the comments for that video says "You can go totally 180 degrees out of phase and then Lenz's law will work for you, not against you".
Well a CW primary and a CCW secondary also results in a phase difference of 180 degrees but I'm not aware of any Lenz benefits.
Sounds good to me tomd. Thanks for the info. Time to break out the coils and start seeing what happens.
Again many thanks to skycollection for providing such info.