Since many different values of L/C can be used for the same frequency, how do you select the best pair for a given frequency? I am working in the 20 to 80 khz area.
thay
I would think something along these lines:
https://youtu.be/r0Fq2BCtlOM (https://youtu.be/r0Fq2BCtlOM)
boguslaw: "Please explain your method of finding resonant frequency"
Armagdn03: "Two methods. One is to place the oscilloscope probe hear the coil and note when you have maximum peak to peak voltage. Two, place some sort of visual indicator in line with the resonant circuit....In this case a incandescent lamp. When the lamp is brightest you have minimum impedance within the circuit indicating resonant frequency" http://www.energeticforum.com/forum/energetic-forum-discussion/renewable-energy/14511-energy-propagation?p=436362#post436362 (http://www.energeticforum.com/forum/energetic-forum-discussion/renewable-energy/14511-energy-propagation?p=436362#post436362)
https://www.allaboutcircuits.com/textbook/alternating-current/chpt-6/parallel-tank-circuit-resonance/ (https://www.allaboutcircuits.com/textbook/alternating-current/chpt-6/parallel-tank-circuit-resonance/)
https://youtu.be/x-1EKjOtrPM (https://youtu.be/x-1EKjOtrPM)
https://youtu.be/R2y9w9cbwcg (https://youtu.be/R2y9w9cbwcg)
Quote from: Thaelin on January 27, 2021, 09:40:31 AM
Since many different values of L/C can be used for the same frequency, how do you select the best pair for a given frequency? I am working in the 20 to 80 khz area.
thay
Well according to Tesla, you would want your resonant freq to be low. From what I understand, 50khz and up will radiate magnetic energy that you cant get back into the system. Loss. So large inductance and small capacitance would be a criteria to follow.
Mags
Quote from: Thaelin on January 27, 2021, 09:40:31 AM
Since many different values of L/C can be used for the same frequency, how do you select the best pair for a given frequency? I am working in the 20 to 80 khz area.
thay
It is not as precise as you think. Just tip over the box of capacitors and grab one then, find an inductor that satisfies the equation.
As an alternative, my ex-wife used to select the capacitor by colour!
It all sounds like you have all need treated or taught via the mushroom method (kept in the dark and fed bull shit)
But doing it all on a hit and miss basis like your saying your going to have poor Q factor, err so what's Q ? don't you think you had better find out ?
While your at it find the right capacitor value to match your frequency to your inductance.
SIL
Quote from: Magluvin on April 05, 2021, 07:09:16 PM
Well according to Tesla, you would want your resonant freq to be low. From what I understand, 50khz and up will radiate magnetic energy that you cant get back into the system. Loss. So large inductance and small capacitance would be a criteria to follow.
Mags
Morey used 31.5 khz do you see a pattern here why he used this frequency ?
Quote from: Thaelin on January 27, 2021, 09:40:31 AM
Since many different values of L/C can be used for the same frequency, how do you select the best pair for a given frequency? I am working in the 20 to 80 khz area.
thay
Hello buddy.
Lots of L/C can resonate at 80 khz.
You can have a 30 turn inductor that resonates at that frequency..or you can have a 200 turn inductor.
More turn = more voltage peak.
What do you need? ...You question was kind of short....What do you want to do ?
Thank you.
PS:....At resonance the square wave is transformed into PURE SINE...PERFECT SINE wave....so it is not only about the peak voltage.
Quote from: sollaris1989 on April 06, 2021, 06:06:56 PM
At resonance the square wave is transformed into PURE SINE...PERFECT SINE wave....so it is not only about the peak voltage.
Easy/cheap way to make a pure-sine inverter?
Thanks to all here for their answers. An old ham radio guy gave me the answer I needed. Pick the frequency you want, pick the best coil value that gives you the best Q value and then select the cap to add.
thay
The chart in this page should help: https://www.rfcafe.com/references/electrical/frequency-reactance-nomograph.htm
Quote from: NdaClouDzzz on April 06, 2021, 06:13:48 PM
Easy/cheap way to make a pure-sine inverter?
a good description for a cheap and high efficient and save transformerless DC/AC inverter :
https://worldwide.espacenet.com/publicationDetails/description?CC=US&NR=2014078802A1&KC=A1&FT=D&ND=3&date=20140320&DB=EPODOC&locale=en_EP
Quote from: MasterPlaster on April 07, 2021, 07:24:40 AM
The chart in this page should help: https://www.rfcafe.com/references/electrical/frequency-reactance-nomograph.htm (https://www.rfcafe.com/references/electrical/frequency-reactance-nomograph.htm)
Have it right in front of me.
thx
Quote from: lancaIV on April 07, 2021, 07:30:35 AM
a good description for a cheap and high efficient and save transformerless DC/AC inverter :
https://worldwide.espacenet.com/publicationDetails/description?CC=US&NR=2014078802A1&KC=A1&FT=D&ND=3&date=20140320&DB=EPODOC&locale=en_EP
👍
https://youtu.be/ssL5scfIFZ8 (https://youtu.be/ssL5scfIFZ8)
Mags
Counsel
Mr. Tesla, at that point, what did you mean by electro-magnetic momentum?
Tesla
I mean that you have to have in the circuit, inertia. You have to have a large self-inductance in order that you may accomplish two things: First, a
comparatively low frequency, which will reduce the radiation of the electromagnetic waves to a comparatively small value, and second, a great
resonant effect. That is not possible in an antenna, for instance, of large capacity and small self-inductance. A large capacity and small
self-inductance is the poorest kind of circuit which can be constructed; it gives a very small resonant effect. That was the reason why in my
experiments in Colorado the energies were 1,000 times greater than in the present antennae.
Tesla
I mean this: If you pass a current into a circuit with large self-induction, and no radiation takes place, and you have a low resistance, there is no
possibility of this energy getting out into space; therefore, the impressed impulses accumulate.
Mags
Quote from: Magluvin on April 10, 2021, 01:16:11 AM
Counsel
Mr. Tesla, at that point, what did you mean by electro-magnetic momentum?
Tesla
I mean that you have to have in the circuit, inertia. You have to have a large self-inductance in order that you may accomplish two things: First, a
comparatively low frequency, which will reduce the radiation of the electromagnetic waves to a comparatively small value, and second, a great
resonant effect. That is not possible in an antenna, for instance, of large capacity and small self-inductance. A large capacity and small
self-inductance is the poorest kind of circuit which can be constructed; it gives a very small resonant effect. That was the reason why in my
experiments in Colorado the energies were 1,000 times greater than in the present antennae.
Tesla
I mean this: If you pass a current into a circuit with large self-induction, and no radiation takes place, and you have a low resistance, there is no
possibility of this energy getting out into space; therefore, the impressed impulses accumulate.
Mags
Yes. Hence Joseph Newman's Big Eureka.👍