Hello all,
update on this implosion motor design.
https://www.youtube.com/watch?v=IKsYhYptWNc
Great work Tom !!!
I am posting here a clip by a dead Russian inventor who died in September in Soul Korea. His name was Andrei Vladimirovich Slobodyan. Again the same old story he died when his air conditioner burned... He emigrated with his family 2010, his company was Infinity SAV.
There is a huge amount of information about this man NOT in English.. and ...It is all negative as this was a scam company..
I will not get in to this background as I know allot about him and he was killed for his BTG generator, it worked on the TPU principle..
If you want more data on him send me a message by VPN .. contact me through this "my message" service..
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Who also made an implosion engine with %1200 power out put with 200 watts in..
Perpetual motion machine consumes 200 watts gives 25000 watts efficiency 1200%
https://www.youtube.com/watch?v=hD8DlC7K_U8 (https://www.youtube.com/watch?v=hD8DlC7K_U8)
Acca...
(https://www.youtube.com/watch?v=hD8DlC7K_U8)
Hello all,
Another update on the Implosion motor.
https://www.youtube.com/watch?v=H8ymrMAfpwo
Hello all,
Getting ready for a simple test run, using a water pump.
I already balanced the rotor and repacked the rotary union seal. I will have a pressure gauge, vacuum gauge and a watt meter on the pump.
https://www.youtube.com/watch?v=H214Ny361kU
"without data, we are wasting our time"
Tom.
Hello all,
If you ever wonder why I use fluids instead of compressed air, is is my reason.
Hp = rpm x foot pound / 5252.
Examples:1) 1 hp =33,000 foot pounds in 1 minute or 550ft/lb one second.2) Take one pound of mass and raise it 33,000 feet in one minute, you just produce 1hp.3) Engine running at 3600 rpm's with a torque of 400 foot pounds, 3600 * 400ft/lb / 5252 = 274.18 hp
What is the difference between fluid and air thrust? 1 gallon of water (231cu/in) weights 8.33lb, 1cu/ft (1728cu/in) of air weights 0.0807
Examples
1) Thrust = pressure x area of compress air. 2in diameter jet with1000 psi, 1000 * r^pi =3,140 in/lb of thrust.
2) Water thrust = 1.57 * 1000 psi * diameter * diameter Using 2" diameter jet with 1000 psi, 1.57*1000*2*2 =6,280in/lb of thrust.
This is why a basic water rocket fill with water adding compress air to force out the mass has double amount of force then air.
Hello all,
Been busy, but have a update video on the Implosion Motor.
https://www.youtube.com/watch?v=AejiAc3y0AI
Hello All,
Another update on the Implosion motor with two videos. Test for leaks, flow and pressure.
https://www.youtube.com/watch?v=Uky1kZvGo6Q
Hello all,
Great news, we have data.
In the video I said 500 watts was made in the centrifugal force, it was hard to read the data while video taping the experiment.
Now, it turn out to be about 300 watts from 2250w at stalled constant down to 1950w while rotating at about 250 rpm's..
https://www.youtube.com/watch?v=JPlY12K5Kh4
Hello all,
This experiment confirms my theories that centrifugal force can be used to cancel out input hydraulic pressure.
https://www.youtube.com/watch?v=G8qpsFH4RME
Hi TommeyLReed !
I've found my password ! I'm very interested in the COP of the replication you're making!
Hi TommeyLReed !
The stator can add thrust like this:
Hi all,
I had to remove most of the build videos due to my contract and a partner, But I still have two last videos up and looking to show the new setup very soon.
I have a 50kw generator on standby and will be using the implosion motor to power it.
Some data of the build has become private.
Thank you.
https://www.youtube.com/watch?v=JPlY12K5Kh4&t=68s
https://www.youtube.com/watch?v=G8qpsFH4RME&t=8s
Tommey Reed
TOM SUPER GREAT WORK. MY TWO BOBS WORTH. WHY DON'T YOU PUT FIXED IMPELLERS AS
ATTACHED TO INCREASE THE REV AND TORQUE.
NOT THE TURBINE BUT JUST THE BUCKETS. YOU FIX THEM CENTER OUTSIDE OF THE ROTATING JETS.
Hello Seychelles,
Yes I'm fully aware of the technical design and it also defuse the thrust vector.
It will increase power output, but decrease as the it speeds up.
I'm waiting on a few more parts and modifying the design with a new gear pump to match the 10hp@3600 motor.
In fact all the calculation should show total input of power vanish.
The test was kind of a success, but the pump was a over kill. The total input should have been at 70% efficiency ((70psi@13gpm)/.75)= 1300/1714=0.75hp or 559 watts.
With centrifugal force 559w-300w = 259w
Thank you for your opinion.
JUST SAW TONY'S POST. GREAT IDEA TONY.