I've seen a lot about EMF, capacitors, back to a battery, across the shaft, etc; but I'm not sure I have actually seen proof of returning EMF back to a system. Is this something that is accepted in general science as true, or is it still speculation?
Are you kidding me?
Howdy,
You are using back EMF every time you crank up you car and go cruising. The ignition system of you internal combustion engine powered automobile uses a capacitor discharge ignition system. This ignition system utilizes a flyback transformer. Basically the capacitor discharges into a coil, the ignition coil. Modern cars have a coil for each spark plug. The capacitor discharges into the coil then the coil builds a large magnetic flux field. When the current from the capacitor ceases there is a cascade effect as the magnetic field in the coil collapses. This energy is discharged through the spark plug to ground. The voltage going into the coil is generally around 13.8 volts. The voltage coming out of the coil is somewhere between 14,000 and 40,000 volts depending on how cool your car is. This flyback effect is back EMF.
The same effect is happening in your television and your computer monitor. Both these devices utilize a flyback transformer to generate the high voltage needed to generate the electron beam which excites the phosphors on the face of you cathode ray tubes.
So, yeah, totally proven...
Blessed Be Brother...
Quote from: z.monkey on July 08, 2008, 10:54:19 PM
So, yeah, totally proven...
Blessed Be Brother...
Cool,
Does that mean in the Kore system, when the current is cut to the pulse coils, the output of the coils at that point can be sent to capacitors to be reintroduced on the next pulse to the coil? If so, how do you contend with the difference in voltage?
Has anyone actually captured the output of a pulse coil, sent it to capacitors and used it to boost the next pulse?
hi guys
yes, not on the same scale as Z was mentioning with TVs or autos, but in my switched cap test circuit i capture the back EMF after the switching cap is charged thro' a coil - the 'flyback diode allows the collapsing field energy to dump its energy back into the switching cap & parallel load
in one version of the test setup there is a second cap being charged before final discharge - this cap also receives the captured back-EMF to boost the energy being stored
with a high-impedance load the flyback voltage will appear as a high voltage-spike across the load - high volts, low current - with a low-impedance load (or big capacitor), you'll more likely see a low-voltage peak at that point - low volts, higher current (same energy)
if i use a small DC motor (salvaged from a PC CD tray drive) as the load you can hear the motor speed up & down as the flyback diode is connected in & out of the circuit
to check that there is a real contribution of energy going thro' the flyback diode i also tried replacing the diode with a variety of different coloured LEDs - the LED lights brightly, showing that there is a significant amount of energy being returned to the cap or load thro this path (but an LED is not as efficient as using a diode - choose lowest forward Vdrop diode for required Amperage)
since the diode/LED is reverse biased to the normal circuit voltages the only way it can be passing current is in the flyback mode
hope this is some help & encouragement - keep up the good work, guys!
sandy
Doc Ringwood's Free Energy site http://ringcomps.co.uk/doc
Quote from: nul-points on July 09, 2008, 03:10:28 AM
hi guys
yes, not on the same scale as Z was mentioning with TVs or autos, but in my switched cap test circuit i capture the back EMF after the switching cap is charged thro' a coil - the 'flyback diode allows the collapsing field energy to dump its energy back into the switching cap & parallel load
in one version of the test setup there is a second cap being charged before final discharge - this cap also receives the captured back-EMF to boost the energy being stored
with a high-impedance load the flyback voltage will appear as a high voltage-spike across the load - high volts, low current - with a low-impedance load (or big capacitor), you'll more likely see a low-voltage peak at that point - low volts, higher current (same energy)
if i use a small DC motor (salvaged from a PC CD tray drive) as the load you can hear the motor speed up & down as the flyback diode is connected in & out of the circuit
to check that there is a real contribution of energy going thro' the flyback diode i also tried replacing the diode with a variety of different coloured LEDs - the LED lights brightly, showing that there is a significant amount of energy being returned to the cap or load thro this path (but an LED is not as efficient as using a diode - choose lowest forward Vdrop diode for required Amperage)
since the diode/LED is reverse biased to the normal circuit voltages the only way it can be passing current is in the flyback mode
hope this is some help & encouragement - keep up the good work, guys!
sandy
Doc Ringwood's Free Energy site http://ringcomps.co.uk/doc
Nullpoints
It looks to me like you have made a Tesla switch
gary
Quote from: rukiddingme on July 08, 2008, 10:07:26 PM
I've seen a lot about EMF, capacitors, back to a battery, across the shaft, etc; but I'm not sure I have actually seen proof of returning EMF back to a system. Is this something that is accepted in general science as true, or is it still speculation?
AT THE UNIVERSITY OF OTTAWA WE ARE CURRENTLY USING COLLECTED BACK EMF TO
ACCELERATE OUR PRIME MOVER UNDER LOAD AND SIMULTANEOUSLY VIOLATING LENZ'S LAW IN THE PROCESS. WE DO IT WITH COILS RATHER THAN CAPACITORS - WE ALSO HAVE A BI-TOROID TRANSFORMER WHICH COLLECTS BACK EMF.
VIDEO #1 SELF ACCELERATING GENERATOR UNDER LOAD
http://www.youtube.com/watch?v=vaf9v0K-rZw
VIDEO #2 NEW COIL DESIGN
http://www.youtube.com/watch?v=FmFbINO0dCU
http://www.overunity.com/index.php/topic,4047.2960/topicseen.html
THIS REPLY SHOWS HOW TO DO IT.
Reply #2962 on: June 29, 2008, 04:48:40 PM
CHEERS
Thane
;D 8)
yep yep its every where lol
but lets call it what it is .....
RE .. in my opinion it is RETURNING ENGERY 8) IN TESLAS OWN WORDS HE HAS NAMED RADIENT ENGERY
IST
watching the world wake up form history ...... :)
Quote from: nul-points on July 09, 2008, 03:10:28 AM
hi guys
yes, not on the same scale as Z was mentioning with TVs or autos, but in my switched cap test circuit i capture the back EMF after the switching cap is charged thro' a coil - the 'flyback diode allows the collapsing field energy to dump its energy back into the switching cap & parallel load
So the current you capture is applied back to the cap and the coil at the same time, or is there another load than the coil?
Seems like you?d want to capture it and release it all at the appropriate moment, the next pulse. Why do you also send it back to the load?
There has to be a flow from the cap through the coil back to the caps already, What?s the difference between that initial flow and the EMF flow? What is your source of initial current?
In the Kore system, the load is the coils, right? The current would flow from the cap into the coils as the coils charge. Does this initial current also flow through the diode? The current is cut. Then the EMF current goes out the other side of the coil, goes through the diode and back to the cap? This EMF is of a higher voltage or frequency, right?
Quote from: nul-points on July 09, 2008, 03:10:28 AM
in one version of the test setup there is a second cap being charged before final discharge - this cap also receives the captured back-EMF to boost the energy being stored
Caps are in series and you apply to both, is the coil also being charged at this point?
Quote from: nul-points on July 09, 2008, 03:10:28 AM
with a high-impedance load the flyback voltage will appear as a high voltage-spike across the load - high volts, low current - with a low-impedance load (or big capacitor), you'll more likely see a low-voltage peak at that point - low volts, higher current (same energy)
if i use a small DC motor (salvaged from a PC CD tray drive) as the load you can hear the motor speed up & down as the flyback diode is connected in & out of the circuit
This would seem to be pretty good evidence. Are there any other reasons that the motor would speed up? There is a change in voltage between the input voltage of the coil and the output. Maybe this causes a change in motor speed with less torque?
Quote from: nul-points on July 09, 2008, 03:10:28 AM
to check that there is a real contribution of energy going thro' the flyback diode i also tried replacing the diode with a variety of different coloured LEDs - the LED lights brightly, showing that there is a significant amount of energy being returned to the cap or load thro this path (but an LED is not as efficient as using a diode - choose lowest forward Vdrop diode for required Amperage)
since the diode/LED is reverse biased to the normal circuit voltages the only way it can be passing current is in the flyback mode
What happens if you leave the diode in and put LEDs between the diode and the cap? Wouldn?t you want to leave the diode in? I may be confused about what the ?normal circuit? is. Wouldn?t this glow be from the passage of current through the system to charge the load?
Quote from: nul-points on July 09, 2008, 03:10:28 AM
hope this is some help & encouragement - keep up the good work, guys! Sandy
Doc Ringwood's Free Energy site http://ringcomps.co.uk/doc
Yes, this is encouraging. This is great information, thanks Sandy.
check out the jouel theif 8)
ist
pretty simple unit...
hi Ru
i should make it clear that i referred to my test circuit just to give you an example of "returning EMF back to a system" - the application you're interested in (the Kore system?) will presumably be trying to do a different job to my circuit
i'll try & answer your questions here
my test circuit is designed to repeatedly transfer small packets of charge from an input source (capacitor, battery, etc) to an output of some kind (another capacitor, resistive load, motor, etc) - it's a 'charge pump', converting a higher input voltage at a lower current draw into a lower output voltage at a higher current - i'm using it to investigate charge and energy gain anomalies in the switching process
i've hopefully uploaded an outline of my test circuit with this post (NB the connection at the lower end of the diode is circuit 'ground', eg. -ve side of C2)
my comments in the post above were just to share the evidence, which i've seen, that energy is really being captured from the collapsing field of an energised coil as it becomes disconnected from its power source
in my system, the switches Q1 & Q2 are MOSFETs, which switch on alternately at a few hundred Hz
C2 gets recharged from C1 (which is pre-charged before a test) through coil L each time Q1 is on
when Q1 turns off, Q2 turns on, the voltage on C2 starts discharging to the output - also at this time the coil tries to maintain its previous current into C2 (in the same flow direction as before)
diode D now provides a closed-loop circuit for the current through the coil and C2 (and the output, which is now switched in parallel with C2)
so the current from the collapsing field energy of the coil is shared both by C2 and and output load connected to it (divided according to their relative impedances)
diode D is connected in reverse to the 'normal' polarity in the circuit (which is +ve at top of Q1) so it doesn't conduct when Q1 is on and it doesn't conduct to discharge C2
if i replace D with an LED it lights brightly - so it can only be powered by the EMF being returned from the coil and fed to C2 and the output
yes, you can connect the LED in series with D and the LED still lights - but as i mentioned, the LED is not as efficient as the diode (it's wasting some energy as light and dropping more voltage) - it acts as a diode anyway, so i didn't need to use both the LED and diode to check the energy capture
when i replace C3 and RL with the small DC motor i mentioned, the motor speed falls if i disconnect the diode, showing it is then getting less power
since we know that the diode only conducts with captured EMF from the coil, the decrease of power to the motor when the diode is disconnected is due to the loss of recaptured EMF from the coil
or, to put it positively, when we add the diode the motor speeds up due to additional energy recaptured from the coil
the recaptured EMF will be a pulse (or a damped oscillation) superimposed on the rest of the voltage waveform at that time - its peak voltage will depend on the total impedance which is in parallel with the coil (in my case, C2 in parallel with whatever output components) - its 'frequency' (or pulse-width) will depend on the resonant frequency of C2 (& output etc) in parallel with L
lower total impedance will produce a lower pulse - higher total impedance will produce one or more cycles of higher amplitude (decreasing to zero)
the +ve or -ve direction of the initial 'pulse' depends on which end of the coil you're monitoring - at the instant the applied power is removed from the coil it becomes a 'generator' of current rather than a load and the polarity of the self-generated voltage across the coil will be reversed to its original direction
i hope this answers your questions in your previous post
all the best
sandy
Doc Ringwood's Free Energy site http://ringcomps.co.uk/doc