Hi my friends
Think that I have a power source of 9Volts 1 Ampere, I know that I can increase the voltage if I decrease the amperage.
And I think also that you can increase the amperage if you decrease the voltage.
MY QUESTION IS There is a ratio between the voltage and amperage? I mean, if I increase the voltage x3 times... the current decrease x3 times also? There is any conversion ratio or the result is unknow?
If you have a doubt about my question and you want that I explain it better, let me know.
Quote from: Magnethos on October 08, 2008, 02:42:48 PM
Hi my friends
Think that I have a power source of 9Volts 1 Ampere, I know that I can increase the voltage if I decrease the amperage.
And I think also that you can increase the amperage if you decrease the voltage.
MY QUESTION IS There is a ratio between the voltage and amperage? I mean, if I increase the voltage x3 times... the current decrease x3 times also? There is any conversion ratio or the result is unknow?
If you have a doubt about my question and you want that I explain it better, let me know.
Hi, if you are using a transformer, then your numbers are correct, increase voltage 3 times, reduce current 3 times, decrease voltage 3 times, increase current 3 times. Yes.
Very interesting...
P.S. Thank Xaverious
@Magnethos
You are basically correct but only if you are trying to maintain the same power in the circuit and it is direct current.
I suggest you do a Wiki on 'Ohm's Law' and play with how it works with D.C. circuits first. After all, it is just plumbing.
Volts = pressure
Amps = amount of flow
Resistance = restriction
Stay away from A.C. circuits until you have a good grasp on D.C. circuits with Ohm's Law ;)
@Bep
Pressure / volts
Volume / amps
Friction/ resistance
Velocity/ ?????
@Sparks,
As it is, Ohm's law is a good approximation ;)
That is one of the reasons for 'fudge factors'.
Let us not start another superluminal discussion ;D