Anyone try to collect the BEMF off a store bought power inverter?
Was just wounding what the results were.
Power collected and if the amp draw went down.
I also wonder, your talking about the collapsed field in the primary coil right ? an inverter first converts dc to ac then steps it up with a transformer, i had an idea but there was no ac just a pulsing dc , the expansion of the magnetic field in the primary coil when voltage is applied would induce an output currant in the secondary windings as we all know, but could we recover most of the input power used from the collapse of the magnetic field in the primary windings and have the output for a longer run time that usual.
Of course in inductive kick back on the primary would disappear to the secondary winding unless we put a diode on the secondary winding so that it can have output current induced from the forward pulse from the primary but current cant go the other way so that when the power is disconnected the collapsed field generates voltage (back emf) on the primary coil only which goes back to the battery.
So output is on the secondary winding and backspike on the primary winding.
Quoted from seekingknowledge:
"Of course in inductive kick back on the primary would disappear to the secondary winding..."
>>Why not wind another coil around the transformer or otherwise parallel-connect another transformer to the first one? The size of the secondary coil can be set for a specific output voltage. Bedini was doing that in at least one of his patents. The number for a prime example was # 6,545,444, which had a magnet-studded rotating wheel energizing a transistor circuit and also having an extra coil coming off it to charge a battery. The downside is that there's only so much power available unless the batteries are possibly wired as a string for higher voltage.
@ Slayer007
Good timing for this thread, thanks for opening it.
Unfortunately I haven't got the answers in measurements you're looking for because I haven't tried it yet but here's my idea.
After looking at your other thread "MAGNETIC FIELD MODEL" at http://www.overunity.com/index.php?topic=7095.0;topicseen
I ran across a statement somewhere on the web where it mentioned using the circuit with AC to make it more efficient so I looked at it earlier today and was wondering if we couldn't replace the FET in the diagram with AC for switching the transformer and using the BEMF.
The following modified diagram is from the patent to show what I'm thinking.
If one was to place a light bulb driven by AC input where Q1 is wouldn't that act as a switch at 60 HZ?
@ Everyone
Don't try this, it's only a crude beginning of an idea
Regards,
Paul
Quote from: Goat on March 30, 2009, 12:01:56 AM
.... was wondering if we couldn't replace the FET in the diagram with AC for switching the transformer and using the BEMF.
The following modified diagram is from the patent to show what I'm thinking.
If one was to place a light bulb driven by AC input where Q1 is wouldn't that act as a switch at 60 HZ?
Hi Paul,
If I may chime in here with a question: how could a light bulb act as a switch? Is this what you mean? It never interrupts any circuit unless its filament is broken.
rgds, Gyula
Hi Gyulasun
I was thinking of using a small AC current driven through a NE2 rather than a filament type bulb to switch the circuit, but after reading more on the circuit in the patent and blog notes which mention using a FET capable of a couple of Amps the NE2 probably wouldn't be the best option either.
Regards,
Paul
"I ran across a statement somewhere on the web where it mentioned using the circuit with AC to make it more efficient so I looked at it earlier today and was wondering if we couldn't replace the FET in the diagram with AC for switching the transformer and using the BEMF."
>>Having a variable frequency AC input across where the transistor would have been would probably allow the experimenter to tune the circuit at the resonant point. A square wave generator may also work, if the circuit resonds predictably and reasonably.
But I remember seeing on a European experimenter's site awhile (several years) ago that if a circuit cannot charge up or recharge the power source that powers it, then it's not overunity. Does the inventor claim this circuit does that?
"If one was to place a light bulb driven by AC input where Q1 is wouldn't that act as a switch at 60 HZ?"
>>Electrically, the concept seems sound to me. A sine wave or square wave would seem the same to a resistive filament. There's also the safety factor of having a visual indication that the circuit is behaving in a fairly normal way.
--Lee