Video link: http://www.youtube.com/watch?v=RnC9YTXXAjs
thats an interesting find G,....
....id like to see a doz or so Led like i see in the JT videos runing that solar panel...
@gotoluc
On this link there is something like your findings.
This guy claimed that it was A Self Runner or free energy.
But the instructable just dissappeared.
http://www.overunity.com/index.php?topic=6123.msg149658#msg149658
JESUS
Hey a Luc,
I just posted this comment to the youtube video...
"What voltage is your solar panel running at? Also, what is the charge battery voltage? The inverter is a load on the charge battery and pulls the charge battery voltage down while running. If the charge battery is really low then the solar panel could be putting out much lower than 12V and still be feeding the charge battery. Besides those voltage measurements, I'd suggest trying with the inverter disconnected."
-Steve
http://rimstar.org http://wsminfo.org
My explanation (of course only a guess):
Then inverter (that steps up the low voltage from the solar panel to about 12 Volt for battery charging) is feeding a strange wave-form (like spikes) to the battery (being charged) and therefore the amp-meter makes an erroneous measurement.
Amp-meters give funny measurements when a non linear current is flowing through them.
Only very expensive equipment can calculate a correct integral over a fluctuating voltage. (All current measurements are in the end voltage measurements over a shunt or an inductance. And electro-mechanical amp-meters are even more prone to fluctuating current misinterpretations.)
Greetings, Conrad
Ok if I'm seeing this correctly his solar panel is parallel to the battery being charged. But he says his amp meter is in series. So that means it has to be between the positive and negative of the panel and battery. So isn't this just a case of the battery flowing some current through the panel and back to the meter? After all he is only using a 5 watt solar panel lit by an LED bulb which is probably barely generating a volt or two on the solar panel if that. So current is flowing from the battery through the panel to the meter at a rate of about 0.63 amps. No overunity there IMO. In fact since it's a 5 watt solar panel the very most current it could put out under maximum sunlight would be about 0.41 amps. That LED is far from what the panel would do in bright sunlight.
@e2matrix,
Connecting positive of the panel to positive of the battery and negative to negative is the correct way of doing it. His meter would then be between the two positives or the two negatives. However, his meter could be backwards and the high voltage of the battery is feeding current against the lower voltage of the panel. Or it could be the return, as you say. However, there's usually a diode in solar panels to protect against that (well, really to protect a non-shaded panel from feeding a shaded panel, but the effect is the same.) It makes sense if there is no diode, or if the diode has short circuited.
-Steve
http://rimstar.org http://wsminfo.org
Sorry - yes you are right as far as how the meter would be inserted into the circuit. And it sounds like you agree with what I'm saying as far as the meter reading the current flowing FROM the battery through meter into the panel rather than the other way around. And again Ohms law says a 5 watt panel can't put out that much current especially running off just a LED light. I've put some very high power LED's (around 10 watt power LED's) on a solar cell and they are not pushing the solar cell anywhere close to what direct sunlight will do.