Hi all.
OK i've checked this over and over but, knowing me, i've probably missed something so please check these figures.
This is my crude replication of Toms device in this thread :
http://www.overunity.com/index.php?topic=9076.0
It's a standard Bedini circuit, i haven't added a relay yet as i want to prove the concept to myslf before maximising efficiency.
The drive coil is the usual bifilar, 800 turns of 0.30mm and 0.28mm.
The output coil is just over a kilometre (1145 metres) of 0.25mm magnet wire.
Input/output figures :
Output coil resistance = 388 Ohms
INPUT POWER: 18 Volts DC @ .280 Amps = 5.04 Watts
OUTPUT VOLTAGE : 155 Volts DC (Rectified)
OUTPUT CURRENT : 155 / 388 = 0.3994845360824742 Amps
OUTPUT POWER : 155 x 0.3994845360824742 = 61.92010309278351 Watts
Please advise if my calculations are wrong, i'm sure they're not as i'm more confident than i was when i joined this forum !
I'm now going to try and get it to run itself ...
Video :
http://www.youtube.com/watch?v=8R7ehAVnp8c
Gary.
I dont think you're measuring your output current properly. I believe you'd need to measure the voltage over a load of some sort, then you can calculate the current with voltage / resistance = current. You're just measuring the output voltage with no load.
Thanks void.
OK i've done a proper load test.
My input resistance is 18 volts / 0.28 amps = 64 Ohms.
I put the nearest i had, 66 Ohms, across the rectifier output.
Results :
OUTPUT VOLTAGE : 138 Volts DC
OUTPUT CURRENT : 0.3994845360824742 (Calculated).
OUTPUT POWER : 55 Watts.
I remember mscoffman talking about the AC impedance of the output coil having an effect on this so i will now try to get the thing to self-run.
Looking good though ...
Gary.
What kind of resistor are you using? I assume its a heavy duty power resistor as 55 watts of power would turn a 1/4W-1W resistor into a molten pile of oops pretty quick :)
I had to do a double take hehe, in your first post you had:
155 volts / 388 ohms = 399mA
in your reply you have:
138 volts / 66 ohms = 399mA, it should be 2.09A! Giving 288.54W of power!
Are you measuring the 138 volts across the 66 ohm load?
Ooops !
Ye that should have been :
OUTPUT VOLTAGE : 138 Volts DC
OUTPUT CURRENT : (138/388) 0.3556701030927835 (Calculated).
OUTPUT POWER : 48 Watts.
**EDIT** and i've not divided by 66 but only by the coil resistance which is 388 **EDIT**
My load resistor is across the rectifier output and i'm measuring from there.
I just tried to self run it, it stops immediately and the safety neon flashes very brightly for an instant.
I will try it with a puffer cap in a bit but i need a cup of tea and a smoke !
brb
Gary.
I still think you're measuring the output current incorrectly - you place the load on the output of the rectifier, probably with a big smoothing cap to get an accurate reading with your digital meter, then you place the ground and hot lead of the meter on either side of the load to get the voltage. Then you divide that voltage by the resistance of the load to yield the current. Shoot me if I'm wrong, I'm new too, but that's my understanding of the situation.
I'll see if I can draw a picture in paint or something.
Thanks void.
Ye that's exactly what i'm doing.
I'm just looking for a suitable cap right now.
haha excuse my paint skills!
Hi Gaz,
From one Gaz to another,
Power at the output has nothing to do with the resistance of the output coil.
What voidy is trying to tell you is -
Measure the voltage across your load resistor (66ohm)
Then use E = I x R like this
I = E/R
So if you read for example 24v -
I = 24v / 66 ohms
so I = .36 amps
and
Power = I x V
so
P = .36 x 24
8.73 Watts
Hope that helps.
Regards, Penno
Cheers penn.
Yup, that's how i did it.
I'm just looking for a smoothing cap now, will 450 Volts @ 150 microfarads be ok ?
Gary.
I'm too new to comment on that, but I think you'd need the frequency to nail the cap size down. That aside, if there isn't a measurement error there, AND, if your meter isn't going crazy from either the frequency or the proximity of the magnet, that implies something like 5000% OU, and this looks like a typical circuit I've seen pounded to death around here. I'll pore over the original thread you linked in the original post.
After you throw in the output cap, would you mind making another video? :)
Oh I See !
So my power is calculated using the load resistance NOT the coil resistance ?
But when i calculate it without the load the proper way is to use the coil resistance isn't it ??
Gary.
Hi Gaz,
No, you cannot make a power calculation without having a load.
Unloaded, you may only state your output voltage.
Also, I agree with Void, in that, frequency plays an important role in measurements.
Regards Penno
Well if the correct calculation is with 66 ohms then that would be a very large power output.
I'm just gonna solder this cap on (when i find my glasses !) and see if it self-runs.
Gary.
OK not self-running with the cap.
It's a 450 Volt cap but didn't get charged beyond 200 Volts or so, does this mean something i don't recognise ?
Will now do video of load test, i won't speak during it coz my GF is watching crappy TV ;+}
Gary.
I made a noob mistake ! Maybe coz i'm a noob ;+}
My resistor wasn'tt 66 Ohms, the meter said 66 while set at the 2000k mark, so god knows what it is.
The closest i've got is a 100 Ohms and it won't even start with that.
I read that generators shouldn't have a load attached until they are at full speed, so i ran it up to full speed then connected a bulb that is meant to run from the mains supply.
It lit it and the magnet still ran.
I'm gonna call it a night for now and get the proper resistors tomorrow.
Thanks for the help :)
Gary.
Gaz,
Good work.
You could if you wanted, measure the resistance of the globe.
But please note that as the filament heats, it ohmic resistance changes.
At least it will give you a rough idea.
Penno
5W in, and 60 out?
Where can I get one of this?
You don't 'get' one you read the thread i mentioned at the beginning of this thread and do your own replication :)
At 2000k (mine only has 200k, then 2M, then 20M), but that should make your reading of 66 imply 66K ohms resistance. With the 135 volts measured across it, that yields 2mA of current, and 27.6mW of power.
Sounds like the 100 ohm resistor was just too much to run as well.
(is your resistor color coded?)
Ye it's colour coded, i have a chart somewhere.
Today it wouldn't even start with the cap across it but it would start without the cap then keep going with the cap attache once it was running !
I hate when the same system behaves inconsistently ...
Quote from: DeepCut on November 09, 2010, 02:34:17 PM
Thanks void.
OK i've done a proper load test.
My input resistance is 18 volts / 0.28 amps = 64 Ohms.
I put the nearest i had, 66 Ohms, across the rectifier output.
Results :
OUTPUT VOLTAGE : 138 Volts DC
OUTPUT CURRENT : 0.3994845360824742 (Calculated).
OUTPUT POWER : 55 Watts.
I remember mscoffman talking about the AC impedance of the output coil having an effect on this so i will now try to get the thing to self-run.
Looking good though ...
Gary.
Is this RMS readings, or just peak readings?
Vidar
Hi Vidar, i made mistakes, as usual !
I've finally done it properly and my output is :
200 VAC @ 0.003 Amps = 0.6 Watts ...
LOL @ me !
You should check out Tom's thread, he is far more advanced in this and looks to be doing well :
http://www.overunity.com/index.php?topic=9076.0
Gary.