Interesting Higher Powered Joule Thief I just made - Part 2.

[Legalizeshemp420]

Note that commercial LED power supplies are rated in current out, not voltage.  They are current sources.  So you always hook the LEDs in series to an LED power supply.  The higher the wattage of the power supply, the more LEDs it can drive in series.

Yep, that is very correct.

[Legalizeshemp420]

Using the shunt resistor of 1ohm 1% 1.23V battery with 175ma drain I read 48mV across the shunt resistor.

How can the 3W be so bright it burns to look at it with only 48ma?

[TinselKoala]

Where did you put your CVR in the circuit? First you say "175 mA drain", then you cite the reading of 48 mV drop across the CVR. These two numbers should agree, should they not?

[Legalizeshemp420]

Where did you put your CVR in the circuit? First you say "175 mA drain", then you cite the reading of 48 mV drop across the CVR. These two numbers should agree, should they not?

They would if the Joule Thief were 100% efficient which nothing is 100% efficient.

Shunt resistor was between the cathode of the 3W LED and ground.  175ma drain on the 1.23v battery.

So, 48ma going to the LED (I find that too low to be seeing the brightness I am on a 3.25V 700ma LED) and 175ma draining the battery.  If the 48ma(mv) number is right that is 48/175 is only about 27% efficient.