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Overunity Machines Forum



Very practical magnetic asymmetry

Started by dieter, February 22, 2014, 04:07:32 PM

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dieter

#5
February 23, 2014, 04:34:24 PM
Sounds good, go for it!  8)


Meanwhile I wonder: What defines the force that is required to turn the magnet when it sticks on an other magnet ... note, idea, two mechanicly linked magnets in parallel, out of magnetic influence by eachother, but near other magnets, one alligned to the field, the other reverse, cancel eachother out, so now to alter their polarisation, while they are attracted by other magnets,  no force is required... now it's me who must have made a mistake somewhere...

nwman

#6
February 23, 2014, 04:42:19 PM
Quote from: dieter on February 23, 2014, 04:34:24 PM
Sounds good, go for it!  8)


Meanwhile I wonder: What defines the force that is required to turn the magnet when it sticks on an other magnet ... note, idea, two mechanicly linked magnets in parallel, out of magnetic influence by eachother, but near other magnets, one alligned to the field, the other reverse, cancel eachother out, so now to alter their polarisation, while they are attracted by other magnets,  no force is required... now it's me who must have made a mistake somewhere...


Sorry, but you'll need to draw this out.

dieter

#7
February 23, 2014, 04:51:29 PM
Maybe that's not neccessary, I just realized, when 2 Magnets mechanicly cancel out eachothers axial alignement forces, then they also cancel out attraction and repulsion and are therefor useless. Got to rethink this on occassion.

nwman

#8
February 23, 2014, 04:55:34 PM
In regards to the first post and pictures:


You need to measure the attraction force over distance of the two magnets coming together directly. = 1 unit of work.


Then,



You would need to measure and graph the force needed to spin the magnets over the 90 degrees of rotation (note length of lever) to calculate work preformed. And then also the force needed to slide the top magnet off over the distance needed to have near zero attraction force. This would calculate total work needed to remove the magnet given your approach.


Then subtract the two and see what you get!


I always account for at least 10% margin of error. If it makes 1 unit of work to attract and  .9 units to remove I would say it's still probably in unity. If it makes one unit of work to attract and .5 units to remove then I would retest several times to confirm and you might have something!

dieter

#9
February 23, 2014, 08:58:31 PM
I absolutely agree with the distance thing. And when it comes to efficiency, I often see people like "crap, only 99%" where I tend to build "superefficient stuff" based on ideas, that then turns out to be extremly inefficient  ;D
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