can 380w electric motor running 10kw generator

[rstergar]

hi,

I have 220v el.motor with 380W and 16000 rpm... I was wondering if I can run new coreless generator which does not require much torque?

I find 10kw generator which need 100RPM... https://www.alibaba.com/product-detail/High-reliability-brushless-axial-coreless-wind_60755236987.html?spm=a2700.7724857.normalList.41.8b914851R0izXO

on image you can see if I add gear ratio from 16000rpm to 125rpm i get a lot of torque... if I am not wrong?

so is this possible to run by itself and have 9,5kw of free energy?

or my calculations are wrong and I get only 29Nm at 125rpm ? (0,23nm x 128)

[Paul-R]

As is, i.e. without any sophisticated mods etc etc (viz Hector etc), the answer is that it will run the generator head but it won't be able to give more than around 300 - 340 watt.

[F6FLT]

hi,

I have 220v el.motor with 380W and 16000 rpm... I was wondering if I can run new coreless generator which does not require much torque?

I find 10kw generator which need 100RPM... https://www.alibaba.com/product-detail/High-reliability-brushless-axial-coreless-wind_60755236987.html?spm=a2700.7724857.normalList.41.8b914851R0izXO

on image you can see if I add gear ratio from 16000rpm to 125rpm i get a lot of torque... if I am not wrong?

so is this possible to run by itself and have 9,5kw of free energy?

or my calculations are wrong and I get only 29Nm at 125rpm ? (0,23nm x 128)

Could you clarify the meaning of the table, especially the column "N.M"? It increases with the square of the angular velocity instead of being proportional.
To obtain the same output power, the torque T must be proportional to the angular velocity w: P=T*w.

At 16000 rpm, w=rpm*2*pi/60 = 1675 rd/s.  P=T*w=0.23*1675=385W, OK, we retrieve the given power.
But for other speeds, we obtain the power of 385W multiplied by the ratio, so the meaning of the N.M. column is doubtful. If it is the torque needed to rotate the gear at the input angular velocity, the output being always 16000 rpm, then it should be 0.23 0.46 0.92 and so on...

In all cases, since power is the product of torque by angular velocity, the use of a gear does not change anything in terms of power or energy, except for losses when you have a gear instead of a direct coupling.

[Low-Q]

The answer to the question is pretty simpe. The generator is not providing more energy than you put in.
Even if the generator is coreless, and does not provide significant resistance when it's unloaded, the generator will still provide countertorque when you load it with electric equipment. In general, you need to do the work for the work to be done. Plain and simple.


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