Critique/help with, this 'real Meyer' circuit?

[Logic]

http://i7.photobucket.com/albums/y292/Elliven/UnipolarMeyer.jpg

Firstly; thanks Dynodon for posting a link to Richie's info, here:
http://www.ionizationx.com/index.php?topic=1264.new;topicseen#new

Also; thanks to Richie for pointing out that resonant circuits have a voltage 'doubling' or increasing effect with the amperage trailing the AC voltage by as much as 90 degrees.
This means that one can get the required high voltage peaks at zero amps, which is what Stanley Meyer hints at in his patents.
http://www.richieburnett.co.uk/dcreschg.html

The circuit diagrams you see here are to show the thought process  I followed to arrive at what I believe may be the real Stanley Meyer circuit.
The circuit which he chose not to show the world, in order to protect his intellectual property.
(Fat lot of good that did him!  Just goes to show that keeping secrets in order to get very rich, only works for the already very rich!)

I am no electronics engineer.
So; although there is beauty in simplicity, the circuit I have drawn is likely in need of plenty of refinement. (If it's any good at all!  )
I look forward to the critique and assistance of everyone that has more experience in building circuits than I do.

FIG 1
shows a standard resonant LC circuit.
One square wave AC pulse goes into the circuit which then resonates.
Due to losses in the circuit the resonant wave fades away.

The blue voltage graph shows the fading voltage wave in the top part of the circuit, up to the top plate of the capacitor.

The red voltage graph shows the equivalent voltage graph for the bottom half of the circuit, up to the bottom plate of the capacitor.

FIG 2
shows the same circuit, but with four square wave pulses going into the circuit at the resonant frequency of the circuit.
Due to the the voltage 'doubling' characteristics of the LC circuit; the supply pulses produce the increasing voltage graphs shown.
Remember that the amperage trails the voltage by as much as 90 degrees?

FIG 3
Shows a basic Stanley Meyer circuit, as can be found on the internet.
The pulses going into the circuit are square wave DC; not AC.
The circuit also contains a diode which blocks any backward flow in the circuit.
This diode, along with the DC pulses, means that the circuit is NOT a Resonant LC circuit, although it may have voltage 'doubling' properties?

FIG 4
Shows a resonant circuit in which the increasing voltage waves in the top and bottom halves of the resonant circuit are both split, or rectified, into positive and negative components.
This gives two pairs of positive and negative pulses with gaps between the pulses.
These pulses are 180 degrees out of phase with each other...
Ie:  The gaps in the pulses in the top part of the circuit are filled exactly by the pulses from the bottom part of the circuit when they are combined.
So: The two pairs of positive and negative voltage spikes are combined to give exactly the type of wave forms shown elsewhere in Meyer's patents!

The amerage wave form is not drawn, but should start in the middle of the voltage pulse and end at its end, while staying very low relative to the voltage wave?

This splitting of the positive and negative side of the circuit into positive and negative pulses that are then combined could be what Stan meant when he carried on about “A Unipolar  supply” to the tube cell/capacitor?

Notice that the positive voltage is above zero, or earth voltage, while the negative pulses are below zero; just as Stanley hinted.
(Remember to earth the cell container to an earth common to the power supply !  )

FIG 4 shows what I think may be the real Meyer circuit.
When you compare this circuit to the one he showed you notice that the original showed almost exactly half the circuit  in FIG 4:
Half the input wave. (Square DC in stead of AC)
Half the output wave going to the tube cell/capacitor...

I have also drawn in a switch, just before the tube cell/capacitor.
This switch simply represents a means of sensing when amperage has climbed to predetermined value so that the square wave supply can be cut for a time.
I see no merit in actually cutting the circuit at this point and wasting power that would produce hydrogen, however inefficiently?

When looking at a simple resonant circuit (FIG 1) one sees that the voltage at the top plate of the capacitor climbs from zero as it is charged by the inductor.
It then falls to zero as it recharges the inductor.
From zero the voltage falls further to a maximum negative value as it is again charged by voltage from the inductor; flowing in the opposite direction.

This is not the case when the output from the inductors is rectified:
Voltage in one plate of the capacitor/tube cell simply climbs in a staircase type pattern.
This begs the question:  Is it necessary to make sure the capacitor/tube cell has the correct capacitance to resonate in the simple LC circuit? (FIG 1)
Or will the  rectified circuit (FIG 4) resonate with any capacitor?

I feel that it is still important to insure that the tube cell resonates at a known resonant frequency of water (42.8 KHz?) and then design the inductors  and power supply to do the same.
This will keep the 'staircase graph' correct.

If you feel this circuit has merit; please spread/post this circuit diagram around and consider it as part of my CV! 

[Logic]

Nothing?
Not even a: "its crap;you'r an idiot"??

Thanks anyway
Bye

[Logic]

Ok; let me try one last time.

Does no-one here agree that:

The current from an inductor can lag behind the voltage by up to 90 degrees?

That a diode only lets current through based on the PD across the diode being 0,3 to 0.7 Volts higher on the input side than the output side?

This will only be true from about 70 to 110 degrees of each voltage pulse?

ie: You disagree that therefore current will only flow from 90 to 110 degrees of each voltage pulse?
This means current flow for 40 degrees in every 360, or 11% of the time, with only PD acting on the water the rest of the time?

That the inductors in a LC circuit have a voltage 'doubling' effect?

Can someone qualified please plot a graph of what they believe the current flow to the tube-cell will look like for one voltage pulse?

I feel that the amperage sine graph will only start to rise from zero at 90 degrees into the voltage sine graph?
ie: at the voltage peak.
Said current will then be cut at around 110 degrees, as the voltage in front of the the diode will fall below the voltage behind it, at this point?

[Artic_Knight]

what about a resonate tesla coil? there are simple designes on the internet and there is one that has 2 primary coils one delivers the power the other helps develop a resonance. then you have the secondary that recieves the power and instead of having one air and one ground lead you could put those to the plates. the input of course could be considerably lower since we are not in the buisness of generating long sparks. i recall a solid state setup that was very simple, i think i will look into that.

thanks