Tom's induction generator looking VERY promising ...

gyulasun · January 07, 2011, 05:31:23 PM

Quote from: Omnibus on January 07, 2011, 04:09:07 PM
Because he is not measuring the instantaneous current and voltage values taken at very small time intervals which he should then multiply and integrate to obtain the real energy-time dependence. What he's doing is a very common mistake and is the reason for so much confusion in the OU community.

Hi Omnibus,

If you mean the instantaneous current and voltage at his output, then it is not really needed in his case because he full wave rectified the AC induced voltage and uses those huge 330uF 450V electrolytic puffer caps. I suppose all this, assuming he, Tom did not change this part of his setup from earlier tests shown in earlier videos. Should he measure AC output from the huge coil under the rotating magnet you were really right.

I would suggest Tom to check the DC current taken out from the 12V output of the power supply and confront the results that way too. To do this, he would simply use the DMM on the left that showed the DC 34V output and he ough to hook it up as an ammeter directly at the 12V output of the supply, the other ammeter at the output ought to stay as showing the output current of .234A as usual. This way he would approach the truth on input and output powers more precisely.

Maybe his Kill a Watt power meter should also be checked with a known value power resistor, just giving 3.5W AC load to his 240V mains via the power meter. If he could use a R=16.46 kOhm resistor (R=240²/3.5), the meter ought to display around 3.5W... Of course such value resistor does not exist, it should be assembled from series and / or parallel combinations. I would certainly check this too, if I were Tom, once such results seem coming he is showing.

Rgds, Gyula

Omnibus · January 07, 2011, 05:36:10 PM

@gyulasun,

How about the input? Or both inpu and output are DC. Then, you're right as long as they are really DC at steady-state. If that's the case he should be able to makeitself-sustaining and all these questions of measurement will become moot. Why doesn't hejustmakeit self-sustaining and kill all critics' arguments.

gyulasun · January 07, 2011, 05:38:49 PM

You mean the input to his setup FROM the power supply or you mean the AC input TO the power supply from the mains? And please ask more concretely on that. Thanks

Omnibus · January 07, 2011, 05:41:41 PM

Quote from: gyulasun on January 07, 2011, 05:38:49 PM
You mean the input to his setup FROM the power supply or you mean the AC input TO the power supply from the mains? And please ask more concretely on that. Thanks

What I'm interested in is what is the input into the device (the coil or whatever) itself -- is it AC or DC?

gyulasun · January 07, 2011, 05:47:06 PM

Quote from: Omnibus on January 07, 2011, 05:36:10 PM
@gyulasun,

How about the input? Or both inpu and output are DC. Then, you're right as long as they are really DC at steady-state. If that's the case he should be able to makeitself-sustaining and all these questions of measurement will become moot. Why doesn't hejustmakeit self-sustaining and kill all critics' arguments.

Well, my understanding his setup is this: He measures (with the Kill A Watt) AC input power taken by his power supply from the 240V mains and also measures the DC output voltage and DC current taken out from his setup (the load seems to be a 4 LED lamp, I assume this). Looping would need using a specially made DC/AC converter that takes in the 34V and 235mA and makes 240V AC, I do not think Tom could solve this inverter building. First he could check the two things I suggested above, and then we could better judge what is at stake here...