Tom's induction generator looking VERY promising ...

gyulasun · January 07, 2011, 05:48:49 PM

Quote from: Omnibus on January 07, 2011, 05:41:41 PM
What I'm interested in is what is the input into the device (the coil or whatever) itself -- is it AC or DC?

Ok, I understand it is 12V DC taken from the power supply output, DC current taken here is presently unknown, this is one thing what I suggest he measure.

Omnibus · January 07, 2011, 05:51:57 PM

Quote from: gyulasun on January 07, 2011, 05:47:06 PM
Well, my understanding his setup is this: He measures (with the Kill A Watt) AC input power taken by his power supply from the 240V mains and also measures the DC output voltage and DC current taken out from his setup (the load seems to be a 4 LED lamp, I assume this). Looping would need using a specially made DC/AC converter that takes in the 34V and 235mA and makes 240V AC, I do not think Tom could solve this inverter building. First he could check the two things I suggested above, and then we could better judge what is at stake here...

Why measure the input into the AC power suplly. That's not the input into his device. The input into his device is after the power supply and I gather it's DC (nevertheless, current-time and voltage-time transients, bothfortheinput andthe outpushave to be clearly presented). Thus, if he's getting greater power out he should be able to loop it without using a converter. A transformer will do.

gyulasun · January 07, 2011, 05:56:14 PM

You should ask the whys from him I am afraid...

By the way a switch mode DC/DC converter ought to be used for looping which also stabilizes its 12V output which would feed his device's 12V DC input. A transformer is not enough.

Omnibus · January 07, 2011, 05:58:45 PM

Quote from: gyulasun on January 07, 2011, 05:56:14 PM
You should ask the whys from him I am afraid...

By the way a switch mode DC/DC converter ought to be used for looping which also stabilizes its 12V output which would feed his device's 12V DC input. A transformer is not enough.

Well, but I'm asking you, do you agree that the input should be at the input of the power supply. The power supply isn't part of the claimed device, is it? Besides, if he's measuring the input tothe power supply then he must use the instantaneous values method.

gyulasun · January 07, 2011, 06:01:27 PM

The power supply is not part of the device, any 12V DC source should operate his device, assuming the source meets the device current needs.