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Overunity Machines Forum



Rosemary Ainslie circuit demonstration on Saturday March 12th 2011

Started by hartiberlin, February 20, 2011, 06:14:05 PM

Previous topic - Next topic

0 Members and 13 Guests are viewing this topic.

Magluvin

Hey Stefan
If it is ok, you could put the posts in the igniter thread. If you insert them just before my first post today, it will fit the time period as there wasnt any posts for a long time. In it fits.  =]  Just a suggestion.


Thanks
Mags

Rosemary Ainslie

Quote from: hartiberlin on March 24, 2011, 11:46:38 PM
Yes, through the switching of the function generator
additional energy can be flown into the circuit via the
Gate Source and Gate Drain capacitances.
Really?  Where is this energy coming from?  The plug?  Or from ground?  I can prove that it does not come from the plug and I intend proving that it does not come from ground through the simple expediency of applying a groundless connection.  And that capacitance would need to generate in the order of 60 amps in BOTH directions.  The ONLY supply that is capable of that much current is from the battery.

Rosemary

hartiberlin

Rosemary,
please measure the battery voltage directly across the battery terminals
with the scope, not inside the circuit.


Here are the 2 scopeshots.
You decide which areas are bigger, the
red ones (positive ones) above the black
ground line or the green areas below the ground
line (negative current recharging the battery).

The math function of the scope says, the green area, is bigger.
You decide !

The question is, when the low potential of the
function generator also oscillates with 1.5 Mhz,
does this supply much power from the function generator
into the circuit via the capacity of gate to drain and source ?

As the funtion generator has about 50 Ohms output resistance,
I just calculated that it could add about 0.5 Watts max into the
circuit at these oscillation amplitudes via the capacitive coupling.

Regards, Stefan.
@ Poynt, please post your simulation file.
Thanks.
Stefan Hartmann, Moderator of the overunity.com forum

Rosemary Ainslie

Quote from: hartiberlin on March 25, 2011, 12:00:21 AM
Rosemary,
please measure the battery voltage directly across the battery terminals
with the scope, not inside the circuit.
I would do this with PLEASURE.  I cannot use the oscilloscope probes.  I've written this in an email reply to you.  I've mentioned this to Poynty here on this thread.  THE SCOPE PROBES DO NOT SPAN THOSE TERMINALS.  I can CERTAINLY do it if I add wire.  But then we're back to where we started. 

Quote from: hartiberlin on March 25, 2011, 12:00:21 AMHere are the 2 scopeshots.
You decide which areas are bigger, the
red ones (positive ones) above the black
ground line or the green areas below the ground
line (negative current recharging the battery).
Good point Harti.  I would say that there's more above than below which definitely CONFLICTS with the displayed values.  I suspect that this was taken from a stored shot of a full cycle.  Else the numbers would have adjusted accordingly.  I intend looking into this tomorrow.

Quote from: hartiberlin on March 25, 2011, 12:00:21 AM
The question is, when the low potential of the
function generator also oscillates with 1.5 Mhz,
does this supply much power from the function generator
into the circuit via the capacity of gate to drain and source ?
This can be easily proved or disproved.  And this will CERTAINLY be tested tomorrow.  I'll let you know.

Quote from: hartiberlin on March 25, 2011, 12:00:21 AMAs the funtion generator has about 50 Ohms output resistance,
I just calculated that it could add about 0.5 Watts max into the
circuit at these oscillation amplitudes via the capacitive coupling.
That EXACTLY matches the energy that we measured.

Stefan, will you PLEASE carefully read the email that I sent you.  We're missing each other by a mile.

Kindest regards,
Rosemary

hartiberlin

When the function generator has the low signal,
then the oscillation is running.

Then the oscillation amplitude of the 1.5 Mhz overlayed on the low
signal of the function generator is around 5 Volts
at maximum.
If we calculate the gate to drain-source resistance as a short
at this high frequency, there is only the limiting
resistor of 50 Ohms at the output of the function
generator.

Thus the maximum power can only be 5 Volts ^2 /50 Ohm / 2
cause the maximum power can be put out, when the
gate to drain-source capacitive resistance would be equal
to the internal output resistance of the function generator.

So at 5 Volts oscillation amplitude it could be a maximum
of 0.25 Watts.
( the function generator output resistance and the
gate to drain-source capacitive resistance are voltage
dividers and thus at the gate to drain-source capacitive resistance
only 1/2 of the output voltage of the function generator can occur at maximum)

At 10 Volts oscillation amplitude of the overlayed 1.5 Mhz signal it would be about 1 Watts max, what the
function generator could provide into the circuit.

Regards, Stefan.
Stefan Hartmann, Moderator of the overunity.com forum