Hydro Differential pressure exchange over unity system.

[johnny874]

Wow,
My system does have a small 12v battery, to run the HMI, that runs the valves and track the data.

Something most people realize - that we are running a hydraulic motor - Self powered, a Generator - self powered, - a dual pumping system with a surface area of 525 inches - self powered, a HMI with to valves 25 sensors and self powered - hydraulics self powered, and burning two light bulbs self powered .....while creating a force of 5500 pounds and capturing it - self powered.....

And someone takes the time to complain of a batterythat can not possible do all of that.....you have witnessed an impossible machine.

When I was young an old man told me the boat left shore and both the people on the boat and the shore thought the other was shrinking.

Nice to smile

  @Stefan,
I think this is the info needed to reverse engineer it or to tell him how to make it work.
After all, haven't seen the patent. So any patent after this date with this information, well...

His pumps have 10 psi and lift a bar (1 r MrWayne, just paying attention to detail here ).
As the bellows expands, the hydraulic unit comes down with it maintaining the 10 psi of pressure.
At the same time, if converted at a 1:10 ratio, then of the 250 square inches of surface area, pumps with a surface area of 25 square inches would have theorhetically 100 psi to have a greater push downward operating the hydraulics being lifted in the opposing bellows.
This would mean there are 2 parts in the bellows and one dropping faster than the other.
The one thing I still don't understand is how they would change the potential from one side to the other. Changing air volume/pressure in something like this I would think would be critical to it's operational ability. It's what would give one side an advantage.
About the only way that I know of to try something like this would be the cylinders with 100 psi would need to use a part of their potential to move the air/gas of the opposing system depressurizing it. If that's where the gain comes from (the 100 psi cylinders), then it would need to use a part of it to change the air pressure/volume in the opposing bellow assembly. Then it would be this difference in potential that would be realized in the functioning of this type of machine.

                                                                        Jim


                                                                       

[mondrasek]

MileHigh,

Wayne played the professional victim instead of trying to answer some simple questions that anybody interested in the proposition would want to ask.

I agree that you asked some very good questions that I too would like to have heard answered.  However, those questions were either directly after or part of messages that were just dripping with thinly veiled passive aggressive statements.  You then hid behind statements of feigned innocence such that you were only speaking plainly and were not intending to be offensive.  Passive aggression is exactly how many of your statements were intended and received.

Also, completely ignoring statements from the inventor and instead telling your impression of what he really did or thinks is more behavior befitting RA than I would expect from you.

How can you say that there was something to study and learn?

A first example:  The "Travis effect" showed a behavior unknown to me.  I understand that it is nothing new and fully explained by known physics.  But it was new to me and therefor something I would study and learn.  That is why I read this forum.

I am pleased to see that Mr. Wayne has returned.  And I hope he is allowed and does offer more details and some answers to yours and others questions.

Thanks,

M.

[wings]

in this way?

.....
for experiment you can use small glasses , you can feel the difference in your hand.


added a more clear drawing

[johnny874]

in this way?

  I think it's done something like this. It would be a cylinder inside of another cylinder.
The inner cylinder as an example would have 20 psi, the cylinder or space beneath it would have 10 psi. Because of this difference, the cylinder with 20 psi would expand downward.
Because it has the hydraulic assembly in it occupying space, the pressure remains constant.
While this is happening, the space beneath the cylinder which has 10 psi is being compressed. Because the riser tubes total 1/10th the surface area, their pressure would be 100 psi. This would increase the push downward opening the bellowing lifting the opposing one and generating hydraulic pressure.
Why the system doesn't seem to work for Mr Wayne is his team never figured out a way to change the air pressure in the opposing inner air cylinder. This can be resolved by having a line feed a small pump that opens an expansion chamber attached to the opposing inner air chamber. When this happens, the air pressure is reduced allowing the other air chamber to become the greater force. Directionality is important.
And when the bellows are going to change direction, a spring which has more force than the air pressure in the cylinder empties the expansion chamber and is held in a locked position.
If something like this is possible, it can be demonstrated mechanically. otherwise how would anyone know where potential is failing to be realized ?

                                                                        Jim

edited to add;
the reason I show one bellows lower than the other which is not necessary is to convey the direction in which the work is being performed.

p.s., Mr Wayne, if your team of engineers haven't thought of this, then I'm not sure you are 10 years ahead of anyone. Just my humble opinion.

[mrwayne]

 
".s., Mr Wayne, if your team of engineers haven't thought of this, then I'm not sure you are 10 years ahead of anyone. Just my humble opinion."
Hello Jim,
I like your thinking, you continually show a full grasp of what you are talking about -
Every now and then you hit on something good.
You are Sherlock Holmes of Over unity ;-)
Keep up the good work.
Wayne