Hydro Differential pressure exchange over unity system.

[mrwayne]

Thanks Johnny,

Our system has three seperate and comlete systems
and I see this has added to the confusion of our operation and system.

System one -
The simple over unity portion - its capture and operating system - very basic.

System Two -
The Data collection system 25 transducers and hoses and wires to connect them all.
(yes they could belocated next to the source - we located them together so they could be isolated - good planning when you have to go through peer review)

System Three -
The initialization process.
Exist for only one reason - to allow the peer group to measure the initail filling of the system.
It is locked out after that operation and is no longer needed.

I am glad you are a better engineer - We need them.

What you infere in your statement is both confusion of our process, I understand - who could have ever understood the stages of "Extra Ordinary Proof" and "Complete analysis of an Actual OU device.

A black box running a load - as many assume would be enough - only adds extreme questions - and funding an operation on that leads to nothing.

Scientific anaylsis is the only responsible direction to take, for both the Inventor, the investor, and the world - or else it gets now where.

Now trust me - If you had engineered a mechanical free energy device - you would be going to the same extreme efforts to put it togther - not for the best engineering - but the best function and isolation for our purpose of analysis.

This has been a learning curve for me also.

Wayne

[mikestocks2006]

  @All,
This is for a watts calculator. With what I am working on, I would be generating about 6 watts of power
by using a wheel with 1/2 Nm of force. That would be 1 kg at 1/2 meter.
To generate 25 watts takes 4 kg's @ 1 meter from it's axis of rotation. And it would need to rotate @ 60 rpm.
  @All, here's a watts calculator. .
http://www.magtrol.com/support/motorpower_calc.html

Hi johnny874,
It appears there is a misprint on the quote above, the 4Kg (mass) should be 4 Newtons (force), and that is the weight about 0.16kg or 160grams, in order to get 25 Watts, from 1 m arm (radious of rotaion) at 60 rpm.
Thanks for the link/analysis
Mike

[johnny874]

Hi johnny874,
It appears there is a misprint on the quote above, the 4Kg (mass) should be 4 Newtons (force), and that is the weight about 0.16kg or 160grams, in order to get 25 Watts, from 1 m arm (radious of rotaion) at 60 rpm.
Thanks for the link/analysis
Mike

  Just a misunderstanding. Still, for 1kg with 1/2 meter from it's axis needs to rotate at 60 rpm for 25 watts of power. Doubt your device generates that much energy.

[mrwayne]

Thank you Johnny,
"Doubt your device generates that much energy."
Well, after the converting the Buoyancy into hydraulic production, then splitting that production to run the Internal operating system, and then using the left over production to runa hydraulic motor - which then turns the Generator - thats about what we have ..
Now jumping ahead on the logic - if you have looked at the machine and calculater the size of the tanks and realized that there is not enough mass discplacment to cause enough buoyancy to generate that much energy - You are right - in your logic Because you impose the limitation of buoyancy to mass.
To be clear - using  the external mass to predict the Buoyant field - will agree with your conclusion - it is counter intuitive to assume we are gaining on the mass discplacement - under those limitations.
We have been clear - our layering system concentrates the physical effects of Mass displacement - and is the key to our process - and our IP.
Thank you.
Wayne

[mrwayne]

Hello Microcontroller,
We all get that you do not understand our process,
You speak as though you have "all understanding" by denying what you do not know - and then accuse us of playing god...
My only request for you;
May you have Peace.
Wayne