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Overunity Machines Forum



United Nuclear Hydrogen Energy Systems

Started by ResinRat2, April 12, 2011, 10:48:17 AM

Previous topic - Next topic

0 Members and 2 Guests are viewing this topic.

Boja

You two have another stupidity in your head,
that every two pieces of iron will serve as a diode for you! 8)
The flag is in your hands! Let's not stop thinking like that!
May your personal conviction always be with you ::)

Sergh

In any case, when you create non-equilibrium conditions for electric current, you get a rectifier.

A unipolar pulse current, or any current that does not have a positive component equal to a negative one, is not a pure alternating current.

This is an alternating current with a component of direct current.

And even if you have alternating current with equal energy positive and negative part and with absolutely identical electrodes in electrolyser, this current can be partially rectified when passing through the electrolyzer.

How? If you have a positive pulse of 100 volts for 1 microsecond, and then a negative pulse of 1 volt for 100 microseconds.It seems to be the same, but a voltage of 1 volt usually does not lead to conductivity in electrolytes. The result of this is ordinary Faraday electrolysis.
https://simplifier.neocities.org/rectifier
https://www.youtube.com/watch?v=kam0f_UTb9c

kolbacict

A non-linear inductor with a permanent magnet inside, like those used in line-scan TVs and monitors, can serve as this element in the same way.
Have you tried to create an AC rectifier without diodes, only with the help of such polar inductors? ;)

Sergh

Regarding electrolysis.

If the current through the electrolyzer is not symmetrical, then Faraday electrolysis occurs.

Nonlinear inductors and other elements of electrical circuits are not important.
You have long been convinced that the decomposition of water by the correct alternating current does not occur. Even if the voltage is high.

Let's talk formally according to Stanley Meyer, although you can find worthy patents from other people.

Why did he accumulate voltage on the cell with a diode?

The literal decomposition of water by high voltage is extremely energy-consuming. Electrolysis has the highest efficiency at the lowest voltage. There are patents and articles that describe catalytic electrolysis processes at a voltage of less than 1.8 volts, even at 1 volt. Some even suggest that with the right catalysts, electrolysis or decomposition of water can be achieved even at 0 volts.

Now we have to think.

Why Stanley Meyer and other similar inventors need relatively high cell voltages?

Moreover, high-frequency, impulse and the like. Do you know how badly supports water these types of voltages? Even with distilled water, even with highly purified deionized water, I had problems with parameter instability and high voltage absorption in such purified  water.

But Meyer writes about ordinary natural water. Such water has a strong conductivity. Natural ordinary water practically makes a short circuit in Meyers small cells.

So, what is next? How could it even work then?

I hope you do not assume that the whole truth is written in patents?


I recently got a new idea. What if there was not quite water in the cells? Or even almost no water at all?
A liquid with high dielectric properties, in which some natural water is dissolved? Then everything falls into place.

For example, but maybe some other liquid:

https://en.wikipedia.org/wiki/Transformer_oil