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Overunity Machines Forum



Overbalancing wheel

Started by SPANG, May 10, 2011, 12:46:30 AM

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0 Members and 7 Guests are viewing this topic.

SPANG

Hi All,
        I thought it might come in handy for you all, if I included this next piece about my design, in this 'post'!
              ______________________________________________________________________

SPANG.                             (BILL.)

Low-Q

Just remember that there is the final ENERGY that must be overbalanced. Not weights/torque alone.

The different distance to the common hub will differ the speed of the chains when they move. The kinetic energy in each of them will differ also - as long BOTH move. That means that the chain far away from the hub WILL force the wheel to turn, but that chain will also go "emtpy" sooner than the other chain. So the total energy when we consider TIME and VELOCITY into the equation, the energy that is expressed in the two chains will finally equalize, and the wheel will stop. How are you suppose to supply more chain to the outer part, and still keep track with the inner part, without adding more and more chain to maintain the overbalance? In this simple design, you must supply more chain constantly to keep it overbalanced forever. If you're not, the chains will go "emty" sooner or later. The outer chain will empty first. When that one is emty, what will happen to the wheel when only the inner chain is left? The wheel will reverse, because now the inner chain will overbalance because there is not chain left on the outer part. After that inner chain is empty, you're back on square one. No energy output. No over unity. Discussions, and theories are worthless.

As I have said a thousand times before: Build it, and see for yourself.

Vidar

SPANG

LOW-Q,
         I don't know where you've got the idea from, that the chain will 'run out', I realy don't!
The chain is 'continuous', --------------------- it CAN'T 'run out'.  What chain IS 'used' ----------
is instantly replaced ------------ NOT 'lost'!
Build it for YOURself, and find out!
Why you continuously, get it wrong ------- beats me!
It's no use telling me, that I'VE got it wrong ------------- YOU'VE got it wrong!

Low-Q

Quote from: SPANG on August 28, 2011, 06:26:45 AM
LOW-Q,
         I don't know where you've got the idea from, that the chain will 'run out', I realy don't!
The chain is 'continuous', --------------------- it CAN'T 'run out'.  What chain IS 'used' ----------
is instantly replaced ------------ NOT 'lost'!
Build it for YOURself, and find out!
Why you continuously, get it wrong ------- beats me!
It's no use telling me, that I'VE got it wrong ------------- YOU'VE got it wrong!
It's your idea. I do not need to build it to prove anything. I know the outcome already. This is kindergarden physics. You must in some way or another replace the chain. In a closed loop, it will not work because you must lift up the same abount of chain that goes down. In a non-closed loop you must apply chains to make it work. I understand the physics very well in this case. You don't. Sorry. Arguing about who is wrong, will not make your idea work.

Nature "hates" differences. It will not be able to convert from equilibrium to difference. Nature is "by nature" approaching equilibrium - not leaving it. In this process you can harvest useful energy. Your device will work as long the mechanisms approaches equilibrium. When equilibrium is met, no energy can longer be harvested. In the case of your design, it will take just a few seconds. Then you have to "wind" it up again with the same energy you got out of it.

Look closer at your design, no matter how much I misunderstand them, and see for yourself how obvious the outcome will be. Honestly, I am quite convinced that you already know it will not work.

All the best,

Your friend

SPANG

LOW-Q,
          Stop now, before you make a complete fool of yourself!      Your diagnosis of my design, goes from
one extreme to another.
I could pull apart your opinions, as easy as a-b-c ---------------- and you know it.   STOP!
I will NOT be answering any more of your 'diatribe'!