PhysicsProf Steven E. Jones circuit shows 8x overunity ?

[JouleSeeker]

hello Steven

i've finished the 'compact' version of my SJ1 looped bifilar variant

i don't have a 'D' cell to display against in a photo, so i've shown the unit alongside an AAA cell (see below)

the 'end-on' photo shows the unit operating from a 1000uF cap (temporarily connected to the screw contacts which will accept the supply wires when loaded in the Calorimeter)

the device will be a close fit to a 'D' cell envelope, and i guess that the Calorimeter will be either copper or steel, so it remains to be seen if the circuit still operates in close proximity to the container walls in the test!

i'll try and get that posted off to you asap (may have to be after the weekend)...

thanks
np


http://docsfreelunch.blogspot.com

Very impressive work, NP.  I now have three working DUT's, including my build of a Xee2 circuit, so that makes four for testing in the cal'r!  Fun...

Xee2, Chris, anyone really who wants to build a device as we're doing, for testing in the cal'r in this first round -- pls do and let me know.

DUT needs to fit inside a cylinder the size of a D-cell battery; I plan to use a standard cap OUTSIDE the Cal'r for these initial tests, with two wires leading in.  Will charge the cap to a specific voltage, measure voltage-start (then disconnect meter), then run down the voltage for a specific TIME, then switch off -- and then re-connect the DMM and measure the voltage-final.  Prior measurement will allow one to get the Vfinal close to what is expected, just from the time of the run.

You may let me know what voltage-range you wish to have tested, to include a "sweet spot", as you wish.  Otherwise, I will probably go from about 1.55V (single AA pre-charging the cap) down to 1.1V. 
  (Ps, my shipping address above.)

The goal of these tests is -- maximum Pout(from DUT inside cal'r) / Pinput (from cap).    I don't know if I expressed this contest-X clearly before, but the highest Pout/Pin from these initial tests will get at least a $100 incentive/prize!

(There is also a separate $100 prize for the JT-type circuit having the lowest required Pinput to light an LED visibly... but the above contest-X is of course the more significant test.)

[hartiberlin]

L1 is approx 4 metres of 0.45mm enamelled copper, wound on a ferrite tube approx 30x15mm OD (obtained from Maplin, material unknown)

L1 decouples the DC supply from the oscillator and allows the LED to be driven by the resulting voltage swing across the oscillator as a whole
(providing for the possibility of some looping of energy back to the supply after each pulse)


greetings
np

Hi NP,
can you please show a scopeshot of what this L1 is doing and how it recharges the
battery together with the rest of the circuit ??
Maybe show a voltage waveform on a 1 Ohm shunt near to it ?
Many thanks.

Regards, Stefan.

[xee2]

Xee2, Chris, anyone really who wants to build a device as we're doing, for testing in the cal'r in this first round -- pls do and let me know.

I will not be sending a device. I am quite sure that my circuit is not over unity. The point was to show how little power it takes to light an LED.

[nul-points]

 

Quote from: nul-points on June 29, 2011, 05:00:30 PM
[...]
>>(providing for the possibility of some looping of energy back to the supply after each pulse)

Hi NP,
can you please show a scopeshot of what this L1 is doing and how it recharges the battery together with the rest of the circuit ??
Maybe show a voltage waveform on a 1 Ohm shunt near to it ?
Many thanks.

Regards, Stefan.

hi Stefan

here is a trace recorded across a 1 ohm current sensing resistor in series with a 1.6V supply (2x AAA NiMH, depleted)

as you can see, each time the transistor is triggered there is a pulse of current supplied to the oscillator from the supply, followed immediately by a pulse of current in the opposite direction (ie. returned to the supply)

exporting the trace data into Excel shows that the energy supplied to the oscillator is 189 units per pulse, and the energy returned to the supply is 149 units per pulse (ie. the net energy converted is 40 units per pulse)

so approximately three-quarters of the energy transferred from the supply, each cycle, gets returned to the supply (in this case) - this means that the system is nearly five times as efficient as it would be without any energy feedback to the supply

of course, this is not the only energy conversion per cycle - there will be energy transmitted as light, and also some energy dissipated as heat

the calorimeter tests, will enable us to quantify these other energy 'outputs' more accurately and get a better understanding of why the original 'scope alone' results show a value for 'n' > 1

by using a variety of different (but related) circuit types in the tests, it should provide more insight into a generic understanding of how and where energy is being converted to work in this kind of oscillator

hope this helps
np

[EDIT: replaced results using alkaline cells as a supply, with results using NiMH]


http://docsfreelunch.blogspot.com

[JouleSeeker]

  Thanks for this waveform and additional information, NP -- very insightful.

I will not be sending a device. I am quite sure that my circuit is not over unity. The point was to show how little power it takes to light an LED.

Understood, Xee2 -- no problem.