PhysicsProf Steven E. Jones circuit shows 8x overunity ?

[jbignes5]

Hasn't anyone figured out that you guys are shorting out the magnetic field into the core. You are only using the e-field. This is why you are starting to scratch the surface of this. When you short out the heavy magnetic field the e-field becomes free to attract charges<-heavy magnetic field particles to the source e-field. I would not be using this in a Faraday cage because you are limiting your unit from collecting the charges and yes the charges are in the form of heat.

These systems run cold because they are depleted of their ambient charges or heat and then draw in charges from the e-field to follow back to the source high voltage(wire). This is where this energy is coming from. Increase the voltage and the field grows to collect from a bigger area. Give the field a different geometry and it will focus or amplify this collected charges. Now if you did a short test of adding an antenna of say 12 inches and a smaller in dimension antenna with equal mass to the system you might be able to draw even more and amplify the results by concentrating the collected charges onto the smaller antenna.

I doubt you will be able to effectively measure the power input in traditional ways here. This voltage has nearly no amperage at all. That means it is using the sub component of our traditional electricity. When you have one half of the fields
locked into the torrid there is very little resistance and hence the lower amp draw from the source. Except of course to fill the components with both the fields. Once the magnetic field is at full strength in the core then the draw goes way down and the e-field is free to interact with the environment.

I know this changes the direction to this experiment but I highly believe this system you are looking at is too closed looped to draw in enough to be useful. What you need to do is shield the wires with a static shielding all around the system then expose the antennas to the environment. Do not ground the shielding, leave it be so it creates an inductive bottle and keep the voltage from being satisfied by the environmental charges. Once the charges enter the system from the environment you should see plenty of power in the load.

If I'm way to off from your experiment then maybe there is something in my words that might clue you into knowing what is happening in this system you are looking at.

If you do decide that antennas would merit further experimentation then the proper placement of those antennas should be after the voltage increase and the antenna line is protected from a reverse from happening by a diode on the antenna line. The load should be connected before the diode and to one side of the load. The other side of the load should be connected to the smaller in dimension but equal mass antenna. This way the charges flow towards the high potential through the device after they are picked up by the smaller antenna.

This works in a method of line compression. The larger antenna has more surface area over a larger area of the environment. This makes the electric field around the larger antenna less dense. The smaller antenna has the same field but it is more compressed or higher density which makes it's value larger. The lines will connect from the larger antenna to the smaller antenna and because the larger antenna is lower in potential then the smaller, the flow will be towards the smaller antenna. Any charges that enter the system will be attracted around the smaller antenna and into the system towards the source voltage to try and balance it and drive your load in the process. Since resistance doesn't react to high voltages in the same way the resistance of the load means nothing except to force the charges to convert and be released as work which coincidentally is movement or heat again to be released into the environment by the load.
At that point I would strongly think about a transformer to separate the load from the unit and facilitate a better conversion of the high voltage down to a safer level for the load to use. Any extra charges would cause a raising of the current available after the transformer. This way you are inductively coupling to the source and the whole input system will not be in direct connection to the load. This should make tuning the system easier especially when the real load you are trying to run is based off of induction or capacitance or even resistance. The transformer coil would be a fixed load I would think.

[nul-points]

.

[kooler]

wow
you guys got alot further than i thought you would .. good job..
xee2.. you got 2 ua's.. good    but i think i will send you some 70,000 perm cores you can do better than that. dude..

the mentor has to out do the understudy..

i envy u guy having the time to work on this stuff..   my time is limited but i wish i could do more in it

robbie

[NickZ]

   Robbie:
   Good to hear back from you, its been a while.
                                                                       Nick

[Pirate88179]

Xee2 from the JT topic has a circuit that should light an led from an AA for seven years!

http://www.youtube.com/watch?v=a2SwZvE41Ok&feature=feedu

Bill

***EDIT***

Great job X!  Very well done sir.