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Overunity Machines Forum



PhysicsProf Steven E. Jones circuit shows 8x overunity ?

Started by JouleSeeker, May 19, 2011, 11:21:55 PM

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Tudi

Quote from: NickZ on June 12, 2011, 09:57:37 PM
   @ Xee:
  All my latest cement beach sand cells produce 55 to 65 mA each cell, not micro amps.
  The last picture in my previous post is of a capacitor can cement cell, it outputs 55 mA, 1.2 volts).  Most of the larger aluminum beer cans output 65 to 70 mA, 1.4 volts.
  These cells will not connect in parallel, only series.  I've gotten over 10 volts from them so far, by using 8 cells.
cooool, so they work forever ? :D Practical :) . Someone mentioned havign 400 leds running forever on earth battery

pese

Quote from: Pirate88179 on June 10, 2011, 11:59:54 AM
I agree with this post totally!  I have argued this for years.  Many of my devices have been accused of tapping into man made energy transmissions...but...the radio transmitter has no idea how many radios are tuned in right?  1 or 10,000 still the same output.  So, since I am no scientist I can't really argue where the energy is coming from  BUT, I still call it free energy (Of which I have and use many devices)  I never call it OU.  My earth battery that lights my Christmas lights every year for free (400 leds) is free.  I can run a Bedini motor from it also that charges my batteries for free.  I think of it like solar, not OU but stick a panel outside and you can do useful things with it for free.

Bill
Hi Bill,

Over this RF fields i have think years ago .
Following:

Give attention that sensitive world-multiband-receivers have input sensitivity of 0,5 uV
the home-quality-receivers abot 5 uV.  (ON VERY-HIGH OHM LOAD!)
But this voltage WILL RECEIVED ONLY FROM on an very hight ohmic resonance-circuit (made by L/C),
that will come without (nearly) NO POWER losses to FET or other Semiconductor (or tube) amplifiers)

Any low ohm  power tapping in the recervers antenna circuit will only change  the fieldstrengh
of the RF-fieid (coming from from long distance station,.. only some meters around  with
very fast degreasing by distance from this shorted "tuned" circuit (that deliver
no usually power).  I tried this 1950 with best results, so my father and grand-dad
(both e-engineers) was wondering and couldn not explain me.

U know also that directly in front of an /example AM) Transmitter it is possible to lightning
filament-bulbs. with "watt-ages in power". such "Wonder-Experiment" that you find anyway
with LED, Neons, Lightning-tubes ... its nothing, they starting with static fields of near no
power to light.

So please do not so mutch in conflicts if you think "to have or can find" Power. It is´nt.   Most is wrong mesuared  or wrong way calculated
Gustav Pese     


P.S.
SO it make NO DIFFERENCE, if in long distance 1 or 1 Million Radios are tuning on ONE Station.

They are transitting 10KW to MWatts. More "grounding" absorbers suck more power of as all radio receivers that
are tuned over the world to this station.

This is the wrong way.  TESLA have not used "tuned" Herz-ian
waves.  He have spoken out this , if he was asked for his
"arrow electric car".
Skype Member: pesetr (daily 21:00-22:00 MEZ (Berlin) Like to discussing. German English Flam's French. Special knowledges in "electronic area need?
ask by messey, will help- so i can...

JouleSeeker

Quote from: Tudi on June 13, 2011, 03:43:07 AM
cooool, so they work forever ? :D Practical :) . Someone mentioned havign 400 leds running forever on earth battery

IIRC, the electrodes on the earth battery are not "forever" -- they degrade during operation of the battery.  Isn't that correct?

JouleSeeker

 I have some further results to share.  I'm working with two capacitors now, 10,000 uF = 10mF each, so a total of 20 mF.  Charged to 2.58V using 2 rechargeable AA's.  I use the caps to run the device until the voltage drops to 1.5V on the caps and note the time t required using a stop-watch.  Thus, I have a reliable measure of Ein and Pin:

E = 1/2 C V**2,  P = E/t,

So Pin = 1/2 20mF (2.58V**2 - 1.5V**2) /t   = 44.06mJ/t

So 44.06 mJ are put into the system, and dividing this Ein by the time, I derive Pin.  The measurements have proven repeatable -- and interesting.
Here are some results this morning:

Basic conditions:
Rb 52Kohms
MPS2222
C-B 151 pF
D red LED
L-B, L-O bifilar 9turns, ferrite toroid 1"OD,  ~120uH each

Ro = 1Kohm
Rr= 0, CSRout = 0 (removed)


1.  With the above conditions, the caps discharge from 2.58V to 1.5V in t = 37.8 seconds, so Pin = 44.06mJ/37.8s = 1.17 mW.
LED dim but clearly visible throughout the run.

2.  Next, I removed the Ro/LED from the system, so current flows back to ground through L1 loop only, t = 37.0 s, Pin = 1.19mW.
  A bit of a surprise, repeatedly, with the Ro/LED out of the circuit, without that load, the input power drain INCREASES.
  A bit hard to explain without OU perhaps, but not sure.  In any case, the power drain through the LED and 1Kohm resistor is small (if not negative ;) )...

3.  So I take the output of L1 and connect it to point 6 (instead of to point 4), so that the return path is through the 1Kohm Rout.   Rout/LED back in the circuit.
Now the LED is extremely dim, but visible in a darkened room.  t= 52s, Pin = 0.85mW.  Pin went down, as might be expected since the current through L1 is impeded by the 1Kohm Ro.

4.  Next, change Ro from 1Kohm to 220ohms.  Same test as in 3, now t = 62.2 sec, Pin = 0.71mW.  Now this is surprising to see Pin go down with Ro reduced, since  the current through L1 is impeded LESS by 220ohms than by 1Kohm Ro -- we are approaching the situation in 1 where the L1 output goes directly to ground.

5.  Back to condition as in 1, but with Ro=220ohms, t= 38.2 s, Pin = 1.15mW (about the same as with Ro=1Kohm).

6.   Next, I removed the Ro/LED from the system, so current flows back to ground through L1 loop only, t = 37.1 s, Pin = 1.19mW.
  A bit of a surprise, repeatedly, with the Ro/LED out of the circuit, without that load, the input power drain INCREASES.  As before.


Next I went to my own "replication", with the conditions as in 4 above, and found t=54 seconds (0.82mW), rather than 62.2 s (0.7mW) with the 1st DUT.  So small variations make a difference (not too surprising) -- in particular, the toroid/windings differ in the replication.

Now, this gives us an idea of how the circuit behaves, and a measure of the low power consumption in this device.

I believe this is a reliable way to measure Pin, without the use of an oscilloscope, using capacitors to provide the input energy.  Next I'm looking into means of measuring the output power; proving to be more challenging.  I'm looking at vacuum-thermocouples.

NickZ

  I am continuing to try different Hartley Oscillators trying to build one that will work with the cement cells small output.  Although I'm getting closer I'm still not there yet, as these hartley circuits seam to draw more than the 50 or 60 mA. that my cells can provide, to light just one led.  I can light a single white led direct off of two of the cement cells, but not through the BWJt, at least not for long.

   Interesting observation: 
   Last night I connected a 3v button cell battery to the capacitor can cement cell that I showed previously, overnight. Then this morning I took the button cell off of the cement cell, and the single red led (connected to the cement cell) is still lit, (3 hours later) from just the charge the button cell gave the cement cell last night, while at the same time lighting an led, all night, and not draining the charge on the button cell charge by much, (1/2 volt).  So, a single cement cell is lighting an led, directly. 
   The point is that there is a good relation between the cement cells as a source of power, capacitors, and other batteries, when all connected together.
  I'm still hoping to find a circuit that will help to take the small power factor from these cells, and increase that, some more.  But, I think that it takes some current, and not just voltage to do so,  I'm hoping to be wrong though, and that 50 mA is enough to start with.