PhysicsProf Steven E. Jones circuit shows 8x overunity ?

[JouleSeeker]

  Thank you for the circuit diagram, NP. 
It will be interesting to see what the LED does to the measurements, certainly a higher load than D.

This method for measuring Poutput suggested by .99 over at OUR.com:

For a possible Pout measurement, we can try using a single diode or FWBR output to charge a capacitor. Then connect a potentiometer across this output cap and monitor the DC output with a DMM. Slowly decrease the resistance of the potentiometer until the DC output voltage begins to drop steadily. Back it off until the output voltage holds steadily. Now use the output voltage and resistance reading on the pot to compute power. I would suggest somewhere between a 10k to 50k pot.

My reply:

We can know the Pinput from the cap/stop-watch tests and can then run off a battery at a steady Vin, and with your cap/poten. measurement for Poutput, we can keep conditions steady.  It concerned me that with variable voltages on Vin and on the output cap, one could not really "tune" the circuit.  This way is much better.

Comments on this method are welcomed.

[JouleSeeker]

Hi Dr. Jones,

Yes, I have Phipps' book by the same name, don't know if the journal article would include this material, since the book is 600+ pages in length...
[snip]

So, both dealt with electric near-fields, not magnetic.  I'd expect a magnetic experiment measuring one-way delay effect with today's very fast scopes could be set up, if someone were motivated to do so.

Yes, I studied physics in college, 3 years into the graduate program before deciding to make a living in computer software.  But, I've maintained an ongoing interest and try to keep an open mind on possibilities.

Best,    Jim

600+ pages for 20 bucks -- I'm going to spring for this book.  Thanks, Jim.
I discussed the experiment with a physicist last evening at some length.  A few modifications arose from that discussion, but the conclusion was the same (apparent non-conservation of momentum).

1.  Have the current on in coil A for some period of time at the start, so the B-field at B is established.
2.  Turn A off at the same time that the current in B is turned ON. 
In this way, B is immersed in the field from A when it turns on, so receives an impulse to the right,
and A will be off (and open so no effective eddy currents) when the field from B arrives.


Keeping an open mind is key to scientific progress, IMO -- thanks, Jim.

[nul-points]

 

  Thank you for the circuit diagram, NP. 
It will be interesting to see what the LED does to the measurements, certainly a higher load than D.

This method for measuring Poutput suggested by .99 over at OUR.com:
[...]
Comments on this method are welcomed.

actually i already used that method on a previous test

   link-->http://www.overunity.com/index.php?topic=10773.msg290346#msg290346

and it didn't seem to tally at all with the previously reported DVM-based results (which suggested 'n' = 1.3 approx, iirc)

hence my latest test looking at the possibility of increasing or maintaining the state of charge of the supply cell


trying to 'simulate' a load level across a capacitor can be counter-intuitive sometimes - it's possible that you don't end up with an equivalent 'load resistance' but instead you form a 'potential divider' arrangement between source impedance and 'load resistor' - in which case the capacitor terminal voltage will tend to change towards the 'o/p' voltage of the divider


taking up your comment about the LED & Diode, above, i agree the two will cause different behaviour of the test circuit - hopefully, their target loads (AAA NiMH and 2200uF capacitor) will dominate over any differences in the forward transfer characteristics of the two components


thanks
np


http://docsfreelunch.blogspot.com

[NerzhDishual]

@Prof. Joule_Seeker 

Thank you for you comment about Yuri N. Ivanov. I'm not a physicist and I have  not done this experiment (Ivanov proposes one with a balance).

I can also just remember that violation of action-reaction principle has been 'claimed' by some people.

Now, to move the discussion forward, would I dare to say that Nul-Points  (the 'misnamed') is also a very good bass player? 

Very Best

[nul-points]

 

[...]
Now, to move the discussion forward, would I dare to say that Nul-Points  (the 'misnamed') is also a very good bass player? 

Very Best

Mr Dishual - how many moons have passed since we exchanged insults in a thread?!?  too many 

i have heard on good authority that if you shake a tree in Bretagne then a musician will fall out - unfortunately that authority wasn't referring to Grande Bretagne!!

'nul-points' is not so misnamed wrt my bass playing  - i've listened to Breton Rock played with Free NRG and i know when i am beaten! 

good to see you here, i hope you will have some more contributions to make

salut!
np


http://docsfreelunch.blogspot.com