PhysicsProf Steven E. Jones circuit shows 8x overunity ?

[Tudi]

i guess the fair winner will be a DC to 15-24 Hz pulse generator circuit peak 1.2 v with minimal R to barely light up the diode ? I guess with a bit math a simple circuit could be designed.

[NickZ]

   Bill:
   Yes, you've mentioned that before.  But, who else has a device that runs while lighting 3 leds for 5 months on a button cell battery?  Not even those using the best 15.000 perm cores can beat that. 
  Kooler was not using ferrite, he is using a 3.8 inch crappy yellow iron powder cores on one of them, you can see the yellow color right through the windings.  5 months Bill... so, if it works with the low perm cores, then it's not the just the core.
  I only have access to mostly pc power supply toroids.  But Kooler has made it work even just using inductors.  He's probably laughing...
   If it weren't for him, I'd have given up already.   Thanks Kooler...
  and thank you Bill.  I'll keep trying... 
  The picture below is of my best lighting unit, (a Kooler replication), uses a tiny ferrite core, and does not use iron powder core, like his.
 
                                 

[JouleSeeker]

Nick, as I said, I'm more interested right now in getting the input power down to the lowest value possible -- with a reliable and repeatable capacitor/stop-watch measurement.    Hence the monetary prize incentive.  Yes, I think this will turn up several interesting circuits that will run for a LONG time, and perhaps we'll learn something along the way.

Measured with RadioShack 22-812 multi-meter. Watts = amps x volts = (1.0 volt) x (0.01 mA) = 10 uW approximately

OK -- now, so that we can compare using the SAME METHOD for consistency, please use the cap/time method to evaluate Pinput:

Here are the straightforward equations:
Ecap = 1/2 C V**2
so
Pinput = 1/2 C (Vstart**2 - Vstop**2)/time


My best result (to date):   using a 1000 uF cap for input energy, Cap dropped  from 2.55V to 1.5 V in 12.7seconds --  so
Pinput = 1/2 10mF (2.55**2 - 1.5**2)/12.7s

= 0.17 mW = 170 uW.

Easy. Repeatable by most anyone.

@Xee2 and @NickZ -- can you see how long it takes for a capacitor to go from about 2.5 to 1.5V while powering your device? Then we can calculate Pin from above equation, and we can make a direct comparison. 

I believe this is an accurate and reliable way to measure Pinput, all you need is a DVM and a stop-watch.  Click "stop" when the DVM over the Cap reaches 1.50 volts.  I measure twice usually, and values come out very close (then take an average).

I would really like to see what Pinput is drawn by Lasersaber's JouleRinger device, especially if he could put the output on just one LED. 

The idea is to measure input Power by an easy, repeatable method --  so we can make direct comparisons of Power usage for various circuits.

[poynt99]

Proffesor,

If I missed this, I apologize;

What is the stated criteria for the meaning of "powering the circuit"?

.99

[poynt99]

OK, I saw that you stated the following:

...which circuit can draw the LEAST POWER INPUT and still light an LED with reasonable visibility.

Is that in reference to the start or end of the run?

Super-brights! 

.99