PhysicsProf Steven E. Jones circuit shows 8x overunity ?

[poynt99]

Agreed, Mags.  And I like to see more than one method used to measure power out, as a check.

My question has always been this:

Why must the load be a diode or LED? Can the load not be a pure resistance?

.99

[Magluvin]

My question has always been this:

Why must the load be a diode or LED? Can the load not be a pure resistance?

.99

Actually, I wouldnt use a diode as a load in any case. What for?   

I am also not keen on using leds as indicators of power. I think we talked this the other day. ;]

And, just above, on this page, I posted this, "Either way, if using the current resistors, measuring the resistor for power out would be the best bet." 

http://www.overunity.com/10773/physicsprof-steven-e-jones-circuit-shows-8x-overunity/msg312165/#msg312165



Mags

[poynt99]

Actually, I wouldnt use a diode as a load in any case. What for?   

I am also not keen on using leds as indicators of power. I think we talked this the other day. ;]

And, just above, on this page, I posted this, "Either way, if using the current resistors, measuring the resistor for power out would be the best bet." 

http://www.overunity.com/10773/physicsprof-steven-e-jones-circuit-shows-8x-overunity/msg312165/#msg312165



Mags

Yes, I saw the recent posts.

I assumed that the "current resistor" is still in series with either a diode or LED.

Did I assume incorrectly?

.99

[Magluvin]

Yes, I saw the recent posts.

I assumed that the "current resistor" is still in series with either a diode or LED.

Did I assume incorrectly?

.99

Yea, but I still objected to using led brightness as an indicator of power when comparing 2 circuits. Depending on the circuits, sure one may drive the led at 20ma and another at 30ma, then we could say  something about the power out by saying one is brighter than the other thus more power. But I would count on the measurement before relying on the led brightness to evaluate how much power. So I  (pre)agree,  no led needed. ;]

Mags

Mags

[poynt99]

So if you agree that no LED or diode is required, please post a diagram of the circuit. Please also indicate which resistor is the load.

Has anyone tested the circuit without a diode/LED? Does this then still conform to the Professor's circuit and claim?

.99