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Overunity Machines Forum



Trawoeer Power Pyramid Version 12 - Electrical output from a homemade pyramid

Started by hartiberlin, June 28, 2011, 04:05:30 PM

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Trawoeger


k4zep

Quote from: Trawoeger on July 27, 2011, 01:32:16 PM
Sorry formydelayin answering...I amalittle bitbusy now  ;D

Needless to say, BIGGER IS BETTER!!!!!  Be Careful!

Respectfully
Ben!!!!!

k4zep

Quote from: DiegoPalma on July 27, 2011, 12:44:55 PM
Hi @ all,

I have the copper reductions instead of brass.
I talked to Thomas and he point it is important to use the brass reductions instead.
I will make the brass reductions on my next trip to town this week, but for the moment I tried the copper ones...

I have a 220v (input) and 20,000v output DC transformer. I am not sure of the output since I can't use my multimeter to test it, and I don't trust the seller too much.
In any case, I connected the positive to the cable and the EARTH to the outer tube. I test the high voltage in the inner coil and there was no shorts in the cable. This is my second attempt. In my first one there was a lightning (short) in the entrance of the upper 5mm hole and the cable. Now I rewinded again and it is good. Thank @ Neptune for the security advise.

I filled in the quartz sand (very dried) and checked the voltage with the multimeter negative in the reactor IN (bottom) and the positive some centimeters away around the reactor and now it is giving me some very low fluctuating voltage (like 0.120 to 0.450 volts) in AC and DC measures. In my first attempt it was 0.001 volts (no reaction).
Also is good to say that I lived in an area with few and week TV or radio signals.

I tried my best to find a water node with a couple of L wires in my garden. Strange sensation for a non believer when the sticks crossed completely in same point in different tries. But finally I found a place that seems to be the correct one.

I mount the pyramid with all components in correct place and connection, alignment to North-South (the front open face triangle to South).
I connected the 12v cooler fan to try stimulate the system.
Nothing happened when trying to move the ventilator. The multimeter reads 0 volts.
Maybe it is the copper reductions...

I will try again with the brass ones when I have them.
Any suggestion?...

Hi Diego,

Very good work.  Be careful that when you "charge" the reactor that you do not get a "Arc" over inside.

One other note on alignment.  I notice in your picture with the cross string from the center of the sides of the pyramid on the center of the coil.  That is not the correct alignment.   The correct point is when the imaginary line from that center point is perpendicular to the side from all three sides,and where they meet, that is the center point.  the lines must come at RIGHT angles to the SIDES Not the base.    Your reactor is probably too high unless you have compensated for that in the setup.  See sketch attached.

Also, I do not know if you can use DC to charge/condition your reactor.  Thomas has always said AC on the high voltage version,
I will be interested to know if this works!!!!

I wish I was a far along as your are, most excellent work.

As Thomas told you, The brass plugs are mandatory!!!!

Respectfully,
Ben K4ZEP

neptune

@K4ZEP . Ben , with respect , I think you are mistaken , and Diego has his reactor positioned right . Refer to Thomas`s videos part 8 , at 7 minutes 40 seconds to the end .
With his pyramid the reactor centre is 25 Cms from the floor .

Pascuser

@K4zep

As Neptune, I did understand from Thomas Trawoeger's videos that you must place the reactor in a parallel from the square base and not right angle of the sides. Thomas says that right angle from the sides is not good.

According to him, this is because it is a reflection of the energy coming from the ground on the plate sides that it is set up this way.

As I am a math teacher, I computed the height from the base to have this point, instead of using wires from the gravity centers of the plate triangle sides; and this is easy, only Thales use. The interesting point is exactly 1/3 of the height of the pyramid, because he gravity center of the triangle sides is 1/3 of the height from the base. If you compute for a 1 meter pyramid with isosceles sides, you have the exact height for this point, from the square base: 23,57cm

For my small pyramid 1/2 scale this is 11,78cm

Thomas found 25m, which is an approximate work because of wires used and the exact height to use is 23,57cm=23,6cm with less than 1mm of error. This could help for positioning.

@Trawoeger

I thought that you were scaling down to 50cm sided, but now I know that I was wrong!! Huge reactor! Interesting to know what power you will drive with it.