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Overunity Machines Forum



Need some help for my homopolar experiment!

Started by blueplanet, July 04, 2011, 01:35:31 AM

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CompuTutor

The magnetic field does not rotate with the magnet.

Low-Q

Quote from: neptune on July 04, 2011, 08:38:25 AM
OK .now some questions of my own . According to Wickipedia , and other sources , a homopolar using a permanent magnet or magnets , works just as well if the magnets are fixed to and rotate with the disc . If this is true , then there can be no posibility of lenz law lugging , so the biggest losses are to brush friction . Peter Lindeman talks about 1000 amps ! So if we are getting only 1 volt , that is 1 Kw . Devide that by 10 to be on the safe side , and this device still has to be WAY overunity . Some sources say a copper disc , and some just a conducting disc . So best to use copper to be safe . Does anyone have a link to other sources of info on Lindemanns machine , other than Patrick Kelly`s book ?
A rolling "brush" should fix this friction problem (A steel ball bearing should do). Plenty of contact all the time (way better than brushes), and almost no friction.

Vidar

forest

Quote from: gravityblock on July 10, 2011, 10:24:49 PM
When the magnet is stationary, then the rotating disc/circuit will cut the flux.  When the magnet/disc is both rotating together, then the stationary external circuit will cut the flux (assuming the field rotates with the magnet).  If the field doesn't rotate with the magnet, then the rotating disc/circuit will cut the flux of the stationary field.  Regardless of what part of the circuit cuts the flux (rotating or stationary circuit), lenz will still be there.  In order to avoid lenz in a HPG/HPM, we need to have a setup where there is no relative motion between the disc and external circuit.  An open external circuit may be another option to avoid lenz.

GB

What if external circuit is rotating along with the disc and magnet ? Would it work ?
Or maybe the other way is make it all stationary but force electrons to move inside copper disc ?

blueplanet

Quote from: forest on July 13, 2011, 04:39:39 AM
What if external circuit is rotating along with the disc and magnet ? Would it work ?

why not?

Quote
Or maybe the other way is make it all stationary but force electrons to move inside copper disc ?

what for?
movement of electrons = current

forest

Quote from: blueplanet on July 14, 2011, 10:15:04 AM
why not?

what for?
movement of electrons = current

I'm just trying to grasp why homopolar generator generate large current but small voltage. Here lies the mystery and understanding is important to me.