Confirming the Delayed Lenz Effect

[gotoluc]

Edited

Still a better improvement so I re-posted the Scope Shots.

Now 182mv of Reactive Power on the 10 Ohm load

0.00324 Watts of Free Power

Now it's time to plug it in the wall

Wish me luck

Luc

[gotoluc]

Hi Luc,

Can you show a photo of these setups BIT/GTL90? Just curious...
Your calculations are correct for the BIT.

On your GTL90 I wonder if a power factor correction could be done like Overunityguide mentioned this afternoon?
To do it, you need to know the input coil self inductance and choose a capacitor with the same reactance at 60 Hz the input coil has at 60 Hz. Then connect this cap in parallel with the input coil, this way the input impedance will be real with no phase shift between input current and voltage instead of the present 90° shift.

Gyula

Humm ... I thought that 90 degrees Phase shift was the best scenario. I achieve it and now you say something else is better.

Inductance of my Primary is 220mH

Luc

[gyulasun]

Humm ... I thought that 90 degrees Phase shift was the best scenario. I achieve it and now you say something else is better.

Inductance of my Primary is 220mH

Luc

Luc,  I do not know if it is better or not... just repeated a suggestion that a reactive input can be power factor corrected.

Primary coil inductive reactance is 82.896 Ohm, this needs a 32 uF parallel cap to get resonance at 60 Hz.

[CRANKYpants]

Humm ... I thought that 90 degrees Phase shift was the best scenario. I achieve it and now you say something else is better.

Luc

HEY LUC,

DON'T LISTEN TO THESE GUYS THEY ARE ALL ON CRACK! 
POWER FACTOR CORRECTION IS GENERALLY DONE ON A BUILDING AS A WHOLE ANYWAY...
SOON THERE WON'T BE A GRID SO THE POINT IS MOOT ANYWAY.

NOW IF YOU STICK YOUR BiTT (WITH ZERO POWER FACTOR) IN BETWEEN AN ELECTRIC CAR'S GENERATOR AND THE BATTERY (PF = 1) AND YOU WILL HAVE REACTIONLESS (LENZ FREE) TRANSFER OF POWER WHICH IS WHAT THIS THREAD IS ALL ABOUT. 

ACTUALLY YOU CAN USE THE BiTT BETWEEN THE BATTERY AND MOTOR AS WELL.

CHEERS
T

PS 1
GOTOLUC 90 TRANSFORMER PHOTOS PLEASE?

PS 2
NOW THAT YOU HAVE A PF = 0 PRIMARY POWER CONSUMPTION = Ip(squared) x Rdcprimary

PS 3
NICE SCOPE WORK BTW (EVEN IF I DO SAY SO MYSELF )

MY ELECTRONICS PROFESSOR PETER CARILLO IS SMILING DOWN FROM HEAVEN RIGHT NOW SEEING THAT I ACTUALLY LEARNED SOMETHING IN HIS CLASS AFTERALL).

[CRANKYpants]

0.00324 Watts of Free Power

Luc

0.00324 WATTS - PRIMARY CURRENT (SQUARED) x PRIMARY DC RESISTANCE.

CHEERS
T