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Overunity Machines Forum



Capillary Force Pump

Started by vineet_kiran, February 23, 2012, 05:19:27 AM

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vineet_kiran

Quote from: Low-Q on February 29, 2012, 06:03:53 AM
The same can be said about the capillary effect. It is negligble in both ends. So there is no point in using the capillary effect to anything useful. And you do not gain anything by putting the system into rotation.
The capillary effect will help fluids to enter the tube with a given force. The same force is preventing the fluids to exit. The rotation will make this device into a solely centrifugal pump. These pumps can move fluid with energy input. The energy is used to pump fluids upwards. If the pump is able to move a significant amount of fluid, the Coriolis effect will be as much significant.
No gain. Sorry.

Mr.Vidar,

It is surprising  that you are unable  to  differentiate  between  a centrifugal  pump and pump which I have drawn.
The energy  equation of centrifugal  pump is as follows :
Total head   =  Suction  head  +  delivery  head  +  loss  of head due  friction,  bends etc.
In the pump  what I have drawn :
Suction head =  0       Because  water is lifted  by  capillary  force
Delivery  head  = 0     Because  water  is ejected  at  same height  of capillary  lift and  no additional  head  is added.
Loss of  head due to friction is negligible considering   the  length of tube.

Once   the  inertia  of tubes  is overcome, the  energy required to  keep it rotating  is negligible,   that’s  what  the energy  motor  consumes.
Even  this  system  can be made ‘gainful’    if you apply  your thought.
 





Low-Q

Quote from: vineet_kiran on March 01, 2012, 10:39:18 AM

Mr.Vidar,

It is surprising  that you are unable  to  differentiate  between  a centrifugal  pump and pump which I have drawn.
The energy  equation of centrifugal  pump is as follows :
Total head   =  Suction  head  +  delivery  head  +  loss  of head due  friction,  bends etc.
In the pump  what I have drawn :
Suction head =  0       Because  water is lifted  by  capillary  force
Delivery  head  = 0     Because  water  is ejected  at  same height  of capillary  lift and  no additional  head  is added.
Loss of  head due to friction is negligible considering   the  length of tube.

Once   the  inertia  of tubes  is overcome, the  energy required to  keep it rotating  is negligible,   that’s  what  the energy  motor  consumes.
Even  this  system  can be made ‘gainful’    if you apply  your thought.

I understand the concept, but I think you have overlooked something important.


Let me comment: The capillary effect will rise the fluids to the same level as the centrifuge. No problem this far. Let us say that the capillary effect rise 1kg water, 1 meter up. That will result in a 2 meter capillary tube with a cross section of 0.5cm^2 to raise the mass 1m in average. That would be 1J of "free" energy. The capillary tube will also, with the same effect, prevent the fluids from escaping the tube 2 meters up. You need at least 1J of input energy in order to reach the point where fluids starts to flow. Then you have gained nothing.
Next is to let the fluid flow. Then you have to add even more energy in order to start the mass flow. The Coriolis effect can be partially countered by tangential nozzles that points in opposite direction of rotation.


An imaginary experiment:
If the capillary tube is able to lift fluids 2 meters up. What happens if you cut the tube in half? Will the fluid start to poor out on the top and fall back into the tank? The answer is probably no.


Vidar

vineet_kiran

Quote from: Low-Q on March 02, 2012, 05:30:05 AM
I understand the concept, but I think you have overlooked something important.


Let me comment: The capillary effect will rise the fluids to the same level as the centrifuge. No problem this far. Let us say that the capillary effect rise 1kg water, 1 meter up. That will result in a 2 meter capillary tube with a cross section of 0.5cm^2 to raise the mass 1m in average. That would be 1J of "free" energy. The capillary tube will also, with the same effect, prevent the fluids from escaping the tube 2 meters up. You need at least 1J of input energy in order to reach the point where fluids starts to flow. Then you have gained nothing.
Next is to let the fluid flow. Then you have to add even more energy in order to start the mass flow. The Coriolis effect can be partially countered by tangential nozzles that points in opposite direction of rotation.


An imaginary experiment:
If the capillary tube is able to lift fluids 2 meters up. What happens if you cut the tube in half? Will the fluid start to poor out on the top and fall back into the tank? The answer is probably no.


Vidar


@Vidar,

If  capillary  tube rises  water  to a height  of  1 meter,    it  has to be ejected  at  1 meter  height only.  ( I did not  understand  what  is 2 meters  height)
I  think  you are simply getting  confused  with  force  and  energy.       Water  is lifted  up  by  natural  capillary  force and  not  energy.     Same  force  prevents  water  from  falling  down  hence  no energy  transaction  is  involved.      The  potential  energy   of water raised  in  capillary  tube   is  zero.      Hence  you  need  just  another   force  (not   energy)   to  pull  this water out.        Centrifugal  force   is  a imaginary  or  pseudo  force  which  depends  mainly  on radius  of rotation  and not  on input energy to the  motor   and also  many  times  stronger   than  the  capillary  force.      Hence  centrifugal  force   ejects  the  water  out.      In  the total  process there will not  be  any energy  transaction.     Only  when  the  water  is  ejected out  of the  tube,   it (water)  gains  potential energy  with  respect  to  earth (ground)


The  equation  is  as simple  as this  :   Water  is lifted  by  a weak force  (not energy),   ejected out  by another  strong force  (not  energy)   and  gains  potential  energy  with respect to  a third  force  (gravity)  after  ejection.


Force  alone  is not  energy   but  difference  of force  (potential  difference)   is  equivalent  to  energy.


Vineet.K.


P.S.  :   I have  got  one doubt  :   How  does  a  tree  lift  water  to  a height  more  than 100 meters?

Low-Q

I think you have a special idea. Try it out in practice, and see if theory corresponds with reality.


A tree is a living organism. Energy from the sun, surrounding moist, living cells, and extremely narrow capillary tubes are involved in the process of lifting water 100 meters up.


Vidar

vineet_kiran

Quote from: Low-Q on March 02, 2012, 01:08:27 PM
I think you have a special idea. Try it out in practice, and see if theory corresponds with reality.


A tree is a living organism. Energy from the sun, surrounding moist, living cells, and extremely narrow capillary tubes are involved in the process of lifting water 100 meters up.


Vidar



@Vidar,

I  have  already  tried that  experiment .    I  did not  get a 90 degree bent  capillary tube hence  I used  a  90 degree bent plastic tube  packed  with  cotton.     Water  did  eject  out  of the tube  but in less  quantity  because  cotton absorbs  water  slowly   in less quantities.    That  is the  reason  why I  have  mentioned that  the experiment  is not of  any practical use.
There  are trees  which  grow  up to   400mtrs height.    So far  no satisfactory  explanation has been given  as to  how  trees  lift  water to  such a height.    Solar  energy, capillary  forces cannot  lift water to such a height.

Vineet.K.