Testing the TK Tar Baby

[Rosemary Ainslie]

You again have no idea what you are talking about. During the oscillations the battery is most certainly not disconnected from the circuit. IT IS POWERING THE OSCILLATIONS, you dimwit. Several people have told you that the mosfet(s) are operating in the linear region. You don't know what that means. Look it up.

You are repeating you argument.  And your argument is wrong.  IF the gate at Q1 has a positive signal - then the gate at Q2 is negative.  If the gate at Q2 has a positive signal then the Gate at Q1 is negative.  In a switched cycle either one or the other gate is continually biased to allow a flow of current from the battery supply.  The battery cannot discharge a negative current flow.  Therefore the current flow that the gates allow needs must be greater than zero.  So.  Again.  If there is a positive signal - then there is a continual path for the discharge from the battery supply.  That you are CLAIMING what SEVERAL people have told me - does NOT make it right.  Because the fact remains.  According to you ALL - there is a continual path available for the discharge of energy from that battery supply.  Which means that the there would be NO interruptions from the battery supply.  Which means that the voltage waveform across the current sensing resistor or the current 'viewing' resistor - as you put it - would remain greater than zero. 

When you use a POSITIVE going gate drive pulse, the oscillations are turned OFF by the FG's output and there is indeed POSITIVE DC CURRENT FLOW from solidly on mosfets as shown by your own scope shots.

Correct.  I absolutely agree.

When there is only a negative gate drive the oscillations persist and the mosfets operate in the linear current flow region: the resistance from drain to source depends on the magnitude of the charge on the gate, which is modulated by the  oscillations.

I WOULD agree - except that according to you there is NEVER a continual negative voltage applied to those gates.  Either the one is on or the other.  That's according to your assessments. 

THE OSCILLATIONS ARE POWERED BY THE BATTERY AND THE BIAS SOURCE, whether it is a FG, a battery  or the squirrels in your head.

I realise that this is your argument.  It's fallacious - in the same way as there are no squirrels in my head.  I think the term is 'projection'.

Rosie Posie

[TinselKoala]

According to you ALL - there is a continual path available for the discharge of energy from that battery supply.  Which means that the there would be NO interruptions from the battery supply.  Which means that the voltage waveform across the current sensing resistor or the current 'viewing' resistor - as you put it - would remain greater than zero. 

No, Ainslie. That is NOT what we ALL are saying at all. We are saying that the oscillations are turning the mosfets partially on, at a high frequency and not totally on. Linear region, remember? Once again you are misinterpreting deliberately and distorting what we have been telling you so that you can lie about it in a post like that one.

[TinselKoala]

I WOULD agree - except that according to you there is NEVER a continual negative voltage applied to those gates.  Either the one is on or the other.  That's according to your assessments. 

Where did I ever say this? Once again you get a simple fact wrong and distort it on playback.
You fool, for the past WEEK at least we have been using a CONSTANT DC NEGATIVE VOLTAGE to the source of Q2 and the GATE of Q1, supplied in various ways, and always resulting in a current flow, NOT THROUGH THE GATE but through the drain-load-battery-source pathway that is in PARALLEL with the voltage applied to the gate of Q2. This negative voltage on the SOURCE of Q2 results in the GATE of Q2 seeing a CONSTANT POSITIVE BIAS that is added to by the oscillations which are most certainly POWERED BY THE MAIN BATTERIES.



What is the IsoTech GFG 324 function generator? Where can I find information about this on the internet?

[TinselKoala]

So now you are claiming that the oscillations are not powered by the battery.

So... we have YET ANOTHER free energy machine that needs a battery to run, but isn't powered by it, but when the battery is removed entirely, or even replaced by a capacitor... the machine won't run at all, much less make free energy.

The secret of overunity and free energy isn't in some specific circuit or pulse motor... it is IN THE BATTERIES !! As long as you have some fully charged batteries, your Free Energy machine will run just fine !! And all the time we were thinking it's the circuit. It's the BATTERIES that make a free energy machine work, every time !!

[Rosemary Ainslie]

I am banging my head on the keyboard. CAN YOU NOT UNDERSTAND ENGLISH?

I understand English very well.  I write it very well.  I am entirely and sufficiently competent in this regard.  Are you?

When you supply a negative voltage to the source of Q2 you are THEREFORE and at the SAME TIME SUPPLYING A POSITIVE VOLTAGE TO ITS GATE.

INDEED.

Your use of "off portion of switching cycle" is  meaningless.

It is the standard term applied to a switching cycle and is WIDELY USED in mainstream both by electrical technicians and by power engineers and by all electrical engineers. And its meaning NEVER varies.

Your FG supplies a voltage that is positive or negative depending on its waveshape setting and the OFFSET.

Not actually.  The offset determines the level of the zero reference.  But otherwise I concur.

One polarity affects one mosfet, the other polarity affects the other mosfets, you think, but this is much too simple. If you provide a pulse that is from negative to zero to the source pin of your Q2 mosfets, the gate of those mosfets sees a POSITIVE voltage when the source is negative, whether it is from the oscillations or the FG+battery combo, with respect to the source pin, because that's how your circuit is wired.

LISTEN UP TK.  We apply the probe of the function generator directly to the Gate of Q1. We apply its terminal to the Gate of Q2.  And I challenge you to do this as well. Precisely to highlight our argument.  I will run our demonstration of this and thereby prove what I am here stating.  Therefore the applied negative or positive to the source rail is IMMATERIAL. Because then you will see that there is always an applied positive bias to afford a battery discharge during both periods of that switching cycle.  The battery can take it's pick.  Q1 or Q2.  That would resolve in a continual discharge from the battery which would be a continual above ground voltage waveform.     

VOLTAGE IS RELATIVE to some reference. A Negative voltage on the source means a positive voltage on the gate.

That is your assumption.  What we prove is that a negative at the Gate of Q1 would be a positive at the Gate of Q2.  And correspondingly a positive at the Gate of Q2 would be a negative at the Gate of Q1.

You are turning your Q2 mosfets partially on with the negative voltage to the source and this is what causes the oscillations, as Mile High (I think) described in detail, period by period, some time ago buried under all your crap.

TK.  I assure you BOTH - that there is no possibility of an oscillation if you have a continual path from either Q1 or Q2.  It has NOTHING to do with whatever signal is at the source rail.

Rosie Posie